JAMB Chemistry · Solutions, the environment and chemical change
Oxidation and reduction: JAMB Chemistry Past Questions and Answers
What the JAMB syllabus covers in Oxidation and reduction
Our summary: Oxidation and reduction in terms of oxygen, electrons and oxidation numbers, balancing redox equations, and oxidizing and reducing agents.
- Oxidation in terms of the addition of oxygen
- Reduction as removal of oxygen with the aid of hydrogen
- Oxidation and reduction in terms of electron transfer
- Use of oxidation numbers (Oxidation and reduction treated as change in oxidation number and use of oxidation numbers in balancing simple equations.)
- IUPAC nomenclature of inorganic compounds using oxidation number
- Tests for oxidizing and reducing agents
Objectives
- identify the various forms of expressing oxidation and reduction;
- classify chemical reactions in terms of oxidation or reduction;
- balance redox reaction equations;
- deduce the oxidation number of chemical species;
- compute the number of electron transfer in redox reactions;
- identify the name of redox species in a reaction;
- distinguish between oxidizing and reducing agents in redox reactions;
- apply oxidation number in naming inorganic compounds; and
- relate reagents to their oxidizing and reducing abilities.
Syllabus content © The Joint Admissions and Matriculation Board (UTME).
JAMB Chemistry questions on Oxidation and reduction
- JAMB 2025Mg + Pb ^ 2+ → Mg ^ 2+ + Pb What is the cell notation for the cell reaction above?
- JAMB 20252Na + Cl 2 → 2NaCl In the reaction above, the specie that undergoes reduction is
- JAMB 2025The compound in which the oxidation state of nitrogen is + 3 is
- JAMB 2025A table in which metals are arranged in series according to their comparative tendencies to give up their valence electrons is
- JAMB 2025In oxidation reactions, electrons are
- JAMB 2025Mg (s) + 2HCl (aq) → MgCl 2 (aq) + H 2 (g) In the reaction above, magnesium is a reducing agent because
- JAMB 2024The chemical formula for potassiumhexacyanoferrate(II) is
- JAMB 2024When a specie undergoes oxidation, its
- JAMB 2024When Sulphur(IV)oxide is passed into solution of acidified tetraoxomanganate(VII), the colour changes from
- JAMB 2024After breathing in a test tube that contains acidified K 2 Cr 2 O 7 , a man noticed the change in the colour of K 2 Cr 2 O 7 from orange to green. This suggests…
- JAMB 2024The IUPAC nomenclature of the complex K 4 Fe(CN) 6 is
- JAMB 2024Which of the following represents an order of increasing reactivity?
- JAMB 2024H 2 S (g) + Cl 2 (g) → 2HCl (g) + S (s) What is the change in oxidation state of sulphur from reactant to product?
- JAMB 2023Which element is placed at the top of the electrochemical series?
- JAMB 2023When a substance is oxidized, it
- JAMB 2023Zn + CuSO 4 → ZnSO 4 + Cu
- JAMB 2023What is the sum of the oxidation numbers in a neutral compound?
- JAMB 2023Balance the following redox reaction: Fe 2 O 3 + CO → Fe + CO 2
- JAMB 2023Which of the following is an example of a primary cell?
- JAMB 2022Zn + 2HCL → ZnCl 2 + H 2 What happens to zinc in the above reaction?
- JAMB 2021The reactions involving simultaneous oxidation and reduction?
- JAMB 2021A chemical process in which there is a gain of electrons is known as?
- JAMB 2021What is the chemical name for the compound CuCO 3 ?
- JAMB 2021A 'breath test' used by traffic police to check drunken driving uses?
- JAMB 2021The metal used to recover copper from a solution of copper sulphate is?
- JAMB 2020What are the possible oxidation numbers of an element if its atomic number is 17?
- JAMB 2019A cell shorthand notation can be written as A / A ^+ // B ^ 2+ /B. The double slash in the notation represents the
- JAMB 2019X is a substance which liberates CO 2 on treatment with concentrated H 2 SO 4 . A warm solution of X can decolorize acidified KMnO 4 . X is
- JAMB 2019If acidified Potassium Dichromate(VI) (K 2 Cr 2 O 7 ) acts as oxidizing agent, color changes from
- JAMB 2019The oxidation state(s) of nitrogen in ammonium nitrite is/are
- JAMB 2019Which of the following reactions is an oxidation process?
- JAMB 2019Which process(es) is/are involved in the turning of starch iodide paper blue-black by chlorine gas?
- JAMB 2019The reaction 2H 2 S + SO 2 3S + 2H 2 O is
- JAMB 2019Consider the equation below: Cr 2 O 7 ^ 2- + 6Fe ^ 2+ + 14H ^ + 2Cr ^ 3+ + 6Fe ^ 3+ + 7H 2 O. The oxidation number of chromium changes from
- JAMB 2018(I). 3CuO(s) + 2NH3(g) ----- 3Cu(s) + 3H2O(l) + N2(g) (II). 2NH3(g) + 3Cl2(g) ----- 6HCl(g) + N2(g) (III). 4NH3(g) + 3O2(g) ----- 6H2O(l) + N2(g) The reactions…
- JAMB 2018In electrovalency, the oxidation number of the participating metal is always
- JAMB 2018H 2 S (g) + Cl 2(g) → 2HCl (g) + S (g) In the reaction above, the substance that is reduced is
- JAMB 2017The oxidation number of iodine in KIO3 is
- JAMB 2016MnO 4 (aq) + Y + 5Fe ^ 2+ (aq) Mn ^ 2+ (aq) + 5Fe ^ 3+ (aq) + 4H 2 O (l). In the equation above, Y is
- JAMB 2015Cu 2S (s) + O 2(g) = 2CU (s) + SO 2(g) . In the above reaction, the oxidation number of Cu changes from … to … ?
- JAMB 2015Chlorine gas turns damp starch-iodide paper
- JAMB 2015An oxidation state of Cr in K2Cr2O7
- JAMB 2015The oxidation state of sulphur on H2SO4 acid is
- JAMB 2014H 2O (g) + C (s) → H 2(g) + CO (g) The oxidizing agent in the reaction above is
- JAMB 2013Zn(s) + CuSO4(aq) ZnSO4(aq) + Cu(s) In the reaction above, the oxidizing agent is
- JAMB 20132H2O (l) + 2F2(g) → 4HF(aq) + O2(g). In the reaction above, the substance that is being reduced is
- JAMB 2013Copper is displaced from the solution of its salts by most metals because it
- JAMB 2012A metal M displaces zinc from ZnCl solution This shows that
- JAMB 20122 Na 2O 2(s) + 2H 2O (1) → 4 NaOH (s) +O 2(g) The substance that is oxidized in the reaction above is
- JAMB 2012An example of oxidation - reduction enzyme is
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