NECO 2004 Physics · Question 14
Which of the following is used as a depolarizer in a Denial cell?
Options
- A.Ammonium chloride
- B.Copper (II) tetra Oxo sulphate (VI) solution
- C.Manganese (IV) oxide
- D.Tetraoxo sulphate (VI) acid
- E.Water
Answer: B. Copper (II) tetra Oxo sulphate (VI) solution
Explanation written with AI and checked against the answer key
Analyze the question: "Denial cell" is a misspelling of Daniell cell. The question asks which substance acts as the depolarizer in it.
Concept: Polarization in a simple cell happens when hydrogen gas bubbles form on the positive electrode (copper). The bubbles insulate the electrode and raise the internal resistance, so the cell's current drops. A depolarizer is a substance that removes the hydrogen, usually by oxidizing it, so the cell keeps working.
Solution: The Daniell cell has:
- A zinc rod in dilute tetraoxosulphate(VI) acid (H₂SO₄) or zinc sulphate, inside a porous pot
- A copper rod in copper(II) tetraoxosulphate(VI) solution (CuSO₄)
At the copper electrode, the Cu²⁺ ions are discharged instead of H⁺ ions:
Cu²⁺ + 2e⁻ → Cu
Hydrogen therefore never forms on the copper plate. The CuSO₄ solution is the depolarizer.
Checking the other options:
- A. Ammonium chloride is the electrolyte in the Leclanché cell, not a depolarizer.
- C. Manganese(IV) oxide is the depolarizer in the Leclanché cell, a common trap. It is not used in the Daniell cell.
- D. Tetraoxosulphate(VI) acid is the electrolyte around the zinc (or in a simple cell), not the depolarizer.
- E. Water is just a solvent.
**Answer: B. Copper(II) tetraoxosulphate(VI) solution.
Exam tip: Remember the pairs:
- Daniell cell → CuSO₄
- Leclanché cell → MnO₂
If the question says "Daniell", think copper sulphate. If it says "Leclanché" or "dry cell", think manganese(IV) oxide.
AI can make mistakes. Report anything that looks wrong.
Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.
