NECO 2004 Physics · Question 13
Calculate the wavelength of light travelling with a speed of 3 × 108 and a frequency of 6.2 × 1014Hz.
Options
- A.4.8 × 10-8m
- B.4.8 × 10-7m
- C.4.8 × 10-6m
- D.4.8 × 10-5m
- E.4.8 × 10-4m
Answer: B. 4.8 × 10-7m
Explanation written with AI and checked against the answer key
Analyze the question: We're given the speed (v) and frequency (f) of light and asked for the wavelength (λ). Note that the speed is 3 × 10⁸ m/s and the frequency is 6.2 × 10¹⁴ Hz.
Concept: For any wave, the wave equation links speed, frequency and wavelength:
v = fλ, so λ = v / f
Solution:
λ = (3 × 10⁸) / (6.2 × 10¹⁴)
- Divide the numbers: 3 ÷ 6.2 ≈ 0.4839
- Subtract the powers of 10: 10⁸ ÷ 10¹⁴ = 10⁻⁶
λ = 0.4839 × 10⁻⁶ m
Convert to standard form: λ = 4.839 × 10⁻⁷ m ≈ 4.8 × 10⁻⁷ m
This is about 480 nm, which falls in the visible light range (blue-green), so the answer makes physical sense.
Answer: Option B, 4.8 × 10⁻⁷ m.
Exam tip: After dividing, always check that your coefficient is between 1 and 10. Here 0.48 × 10⁻⁶ must be rewritten as 4.8 × 10⁻⁷. Many students pick the wrong option (C) by forgetting this step. Also, visible light wavelengths are always roughly 4 × 10⁻⁷ m to 7 × 10⁻⁷ m, so you can quickly eliminate the other options.
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