JAMB 2017 Physics · Question 9
Which of the following representations is correct for an atom X with 28 electrons and 30 neutrons?
Options
- A.
- B.
- C.
- D.
Answer: A.
Explanation written with AI and checked against the answer key
Analyze the question: We need the correct nuclide notation for an atom with 28 electrons and 30 neutrons.
Concept: Nuclide notation is written as ᴬ_Z X, where:
- Z = atomic number = number of protons
- A = mass number = protons + neutrons
For a neutral atom, the number of electrons equals the number of protons.
Solution:
- The atom is neutral, so protons = electrons = 28. This gives Z = 28.
- Mass number A = protons + neutrons = 28 + 30 = 58.
- The notation is therefore ⁵⁸₂₈X.
Checking the options:
- A. ⁵⁸₂₈X: A = 58, Z = 28. Correct.
- B. ³⁰₂₈X: the mass number is wrongly given as 30, the neutron count.
- C. ²⁸₃₀X: the mass number and atomic number are swapped, and the values are wrong.
- D. ⁵⁸₃₀X: the atomic number is wrongly given as 30, the neutron count.
(The element is nickel-58.)
Tip: The top number (mass number) is always the larger one, because it counts protons plus neutrons. The bottom number is the atomic number, which counts protons only. Remember: "Atomic number = bottom = protons = electrons (in a neutral atom)."
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