JAMB 2017 Physics · Question 8

A constant force of 5N acts for 5 seconds on a mass of 5kg initially at rest. Calculate the final momentum

Options

  1. A.125kgms−1
  2. B.25kgms−1
  3. C.15kgms−1
  4. D.0kgms−1

Answer: B. 25kgms−1

Explanation written with AI and checked against the answer key

1. Analyze the question

We are given:

  • Force (FF) = 5 N5\text{ N}
  • Time (tt) = 5 s5\text{ s}
  • Mass (mm) = 5 kg5\text{ kg}
  • Initial velocity (uu) = 0 m/s0\text{ m/s} (since it is initially at rest)
  • We need to find the final momentum (pp).
2. Explain the concept

Momentum (pp) is defined as the product of mass and velocity (p=mvp = mv). According to Newton's Second Law of Motion, the rate of change of momentum is equal to the applied force. This is expressed by the Impulse-Momentum Theorem:

Impulse=Change in Momentum\text{Impulse} = \text{Change in Momentum}
Force×Time=m(v−u)\text{Force} \times \text{Time} = m(v - u)

Since the object starts from rest (u=0u = 0), the final momentum is simply equal to the impulse applied to the object.

3. Show the solution

Step 1: Identify the formula for Impulse.

Impulse=F×t\text{Impulse} = F \times t

Step 2: Calculate the Impulse.

Impulse=5 N×5 s=25 Ns\text{Impulse} = 5\text{ N} \times 5\text{ s} = 25\text{ Ns}

Step 3: Relate Impulse to Momentum. Since Impulse = Change in Momentum (Δp\Delta p):

Δp=pfinal−pinitial\Delta p = p_{\text{final}} - p_{\text{initial}}

Because the object starts from rest, pinitial=m×0=0p_{\text{initial}} = m \times 0 = 0. Therefore:

25 Ns=pfinal−025\text{ Ns} = p_{\text{final}} - 0
pfinal=25 kgms−1p_{\text{final}} = 25\text{ kgms}^{-1}

(Note: The unit of Impulse, Newton-seconds (Ns), is equivalent to the unit of momentum, kgms−1\text{kgms}^{-1}.)

4. Identify the answer

Comparing our result to the options provided: A. 125 kgms−1125\text{ kgms}^{-1} B. 25 kgms−125\text{ kgms}^{-1} C. 15 kgms−115\text{ kgms}^{-1} D. 0 kgms−10\text{ kgms}^{-1}

The correct option is B.

5. Tip

Whenever you see a question involving "Force," "Time," and "Momentum," think of the word Impulse. Remember the acronym FIT: Force ×\times Impulse = Time (or more accurately, F×t=ΔpF \times t = \Delta p). This saves you the stress of calculating acceleration and final velocity separately!

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