JAMB 2023 Mathematics · Question 18

200 tickets were sold for a show. VIP tickets costs ₦1,200 and ₦700 for regular. Total amount realised from…

Question

200 tickets were sold for a show. VIP tickets costs ₦1,200 and ₦700 for regular. Total amount realised from the sale of the tickets was ₦180,000. Find the number of VIP tickets sold and the the number of regular ticket sold.

  1. A.VIP = 80, Regular = 100
  2. B.VIP = 60, Regular = 120
  3. C.VIP = 60, Regular = 100
  4. D.VIP = 80, Regular = 120

Answer: D. VIP = 80, Regular = 120

Explanation written with AI and checked against the answer key

Analysis

To solve this problem, we need to set up a system of linear equations based on the information provided:

  1. The total number of tickets sold.
  2. The total amount of money realized from those sales.
Concept

We will use the Substitution or Elimination method for simultaneous equations. Let:

  • xx = number of VIP tickets
  • yy = number of regular tickets
Step-by-Step Solution

Step 1: Form the equations.

  • From the total number of tickets: x+y=200x + y = 200 --- (Equation 1)
  • From the total amount realized: 1200x+700y=180,0001200x + 700y = 180,000 --- (Equation 2)

Step 2: Simplify Equation 2. To make the calculation easier, divide Equation 2 by 100: 12x+7y=180012x + 7y = 1800 --- (Equation 3)

Step 3: Solve using substitution. From Equation 1, express yy in terms of xx: y=200−xy = 200 - x

Substitute this into Equation 3: 12x+7(200−x)=180012x + 7(200 - x) = 1800 12x+1400−7x=180012x + 1400 - 7x = 1800

Step 4: Solve for xx. 12x−7x=1800−140012x - 7x = 1800 - 1400 5x=4005x = 400 x=4005x = \frac{400}{5} x=80x = 80

Step 5: Solve for yy. Substitute x=80x = 80 back into Equation 1: 80+y=20080 + y = 200 y=200−80y = 200 - 80 y=120y = 120

So, 80 VIP tickets and 120 regular tickets were sold.

Conclusion

Comparing our result (x=80,y=120x=80, y=120) with the given options, it matches option D.

Exam Tip

When you have a system of equations in a multiple-choice exam, you can save time by testing the options. For example, in option D: 80+120=20080 + 120 = 200 (Correct total tickets). Then check the money: (80×1200)+(120×700)=96,000+84,000=180,000(80 \times 1200) + (120 \times 700) = 96,000 + 84,000 = 180,000. Since this matches the total amount, you don't even need to do the full algebra!

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