To simplify the expression 2log(52)−log(12572)+log(9), we will use the fundamental laws of logarithms.
1. Analyze the expression
The expression is:
2log(52)−log(12572)+log(9)
2. Explain the concepts (Logarithm Laws)
- Power Rule: nlog(x)=log(xn)
- Subtraction Rule: log(a)−log(b)=log(ba)
- Addition Rule: log(a)+log(b)=log(a×b)
3. Step-by-step Solution
Step 1: Apply the Power Rule to the first term
2log(52)=log((52)2)=log(254)
Now the expression is:
log(254)−log(12572)+log(9)
Step 2: Combine the first two terms using the Subtraction Rule
log(254)−log(12572)=log(72/1254/25)
=log(254×72125)
Simplify the fraction:
=log(11×185)=log(185)
Step 3: Add the final term using the Addition Rule
log(185)+log(9)=log(185×9)
=log(25)=log(5)−log(2)
Wait! Let's re-examine the options. Since the options involve log(2) and log(3), let's express the numbers in terms of their prime factors (2, 3, and 5).
log(254)−log(12572)+log(9)
=(log4−log25)−(log72−log125)+log9
=(2log2−2log5)−(3log2+2log3−3log5)+2log3
=2log2−2log5−3log2−2log3+3log5+2log3
Step 4: Group like terms
=(2log2−3log2)+(−2log5+3log5)+(−2log3+2log3)
=−log2+log5
Since log5=log(210)=log10−log2=1−log2:
=−log2+(1−log2)
=1−2log2
4. Identify the answer
Comparing our result (1−2log2) to the given options, it matches option D.
5. Exam Tip
When you see logarithms with different bases or fractions, always try to break the numbers down into their prime factors (2, 3, 5). This makes it much easier to cancel out terms and reach the simplified form required by the options!
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