JAMB 2019 Mathematics · Question 30

If the volume of a frustrum is given as V=πh3(R2+Rr+r2)V = \frac{\pi h}{3} (R^2 + Rr + r^2), find dV dR\frac{\mathrm d V}{\mathrm d R}.

Options

  1. A.πh3(2R+r)\frac{\pi h}{3} (2R + r)
  2. B.2R+r+πh32R + r + \frac{\pi h}{3}
  3. C.πh3(2R2+r+2r)\frac{\pi h}{3} (2R^2 + r + 2r)
  4. D.2R23πh\frac{2R^2}{3} \pi h

Answer: A. πh3(2R+r)\frac{\pi h}{3} (2R + r)

Explanation written with AI and checked against the answer key

Analyze the question

We need the derivative of V with respect to R. This means R is the variable, while h and r are treated as constants.

Concept

Use the power rule, d/dR (Rⁿ) = nRⁿ⁻¹, and the constant multiple rule. Any term without R differentiates to 0.

Solution

V = (πh/3)(R² + Rr + r²)

  • d/dR (R²) = 2R
  • d/dR (Rr) = r, since r is a constant
  • d/dR (r²) = 0, since r² is a constant

Therefore:

dV/dR = (πh/3)(2R + r)

Checking the options

  • A: (πh/3)(2R + r). This matches our result.
  • B: The factor πh/3 is added instead of multiplied, so it is wrong.
  • C: This has 2R² and a strange "2r", so it is wrong.
  • D: This ignores the other terms, so it is wrong.

Exam tip

When differentiating with respect to one letter in a formula, treat every other letter as an ordinary number. Here, h and r behave just like 5 or 7. Also, keep the constant factor (πh/3) outside and differentiate only the bracket.

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