JAMB 2019

2019 JAMB Mathematics Past Questions

The 2019 JAMB Mathematics past questions with answers: 80 objective questions from the 2019 paper in the DeeepSolve question bank, each with its answer behind "Show answer". Try each question before you check, then practise the paper as a timed JAMB-style CBT.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.

Questions

  1. 1.

    The histogram above represents the number of candidates who did Further Mathematics examination in a school. How many candidates scored more than 40?

    Diagram for question 1
    1. A.100
    2. B.79
    3. C.150
    4. D.90
    Show answer

    Answer: A. 100

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  2. 2.

    If the universal set μ = {x : 1 ≤ x ≤ 20} and A = {y : multiple of 3} B = |z : odd numbers} Find A ∩ B

    1. A.{1, 3, 6}
    2. B.{3, 5, 9, 12}
    3. C.{3, 9, 15}
    4. D.{2, 3, 9}
    Show answer

    Answer: C. {3, 9, 15}

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  3. 3.

    Find the value of (0.5436)30.017×0.219\frac{(0.5436)^3}{0.017 \times 0.219} to 3 significant figures.

    1. A.46.2
    2. B.43.1
    3. C.534
    4. D.431
    Show answer

    Answer: B. 43.1

    AI explanation

    Analysis

    To solve this problem, we need to perform the arithmetic operations in the correct order: first, calculate the cube of the numerator, then calculate the product in the denominator, and finally perform the division. After obtaining the result, we will round it to 3 significant figures.

    Concept
    1. Exponents: (0.5436)3=0.5436×0.5436×0.5436(0.5436)^3 = 0.5436 \times 0.5436 \times 0.5436
    2. Multiplication: Calculate the product of the two numbers in the denominator.
    3. Division: Divide the result of the cube by the result of the product.
    4. Significant Figures: When rounding to 3 significant figures, we count three digits starting from the first non-zero digit.
    Step-by-Step Solution

    Step 1: Calculate the numerator (0.5436)3=0.5436×0.5436×0.5436(0.5436)^3 = 0.5436 \times 0.5436 \times 0.5436 0.5436×0.5436≈0.295500960.5436 \times 0.5436 \approx 0.29550096 0.29550096×0.5436≈0.16063430.29550096 \times 0.5436 \approx 0.1606343

    Step 2: Calculate the denominator 0.017×0.219=0.0037230.017 \times 0.219 = 0.003723

    Step 3: Perform the division 0.16063430.003723≈43.146467...\frac{0.1606343}{0.003723} \approx 43.146467...

    Step 4: Round to 3 significant figures The first three digits are 4, 3, and 1. The next digit is 4, which is less than 5, so we keep the 1 as it is. Result ≈43.1\approx 43.1

    Conclusion

    Comparing our result with the options provided, we see that 43.1 corresponds to option B.

    Exam Tip

    When dealing with decimals in JAMB, if you are not allowed a calculator, try converting the decimals to standard form (e.g., 5.436×10−15.436 \times 10^{-1}) before multiplying. This helps prevent errors with decimal point placement. Also, always perform a quick "sanity check" by rounding the numbers to one significant figure first to estimate the magnitude of your answer (e.g., 0.53/(0.02×0.2)=0.125/0.004≈310.5^3 / (0.02 \times 0.2) = 0.125 / 0.004 \approx 31), which helps you spot if your calculated answer is way off.

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  4. 4.

    Score (x) 0 1 2 3 4 5 6 Freq (f) 5 7 3 7 11 6 7 Find the variance

    1. A.3.42
    2. B.4.69
    3. C.4.85
    4. D.3.72
    Show answer

    Answer: D. 3.72

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  5. 5.

    From the cyclic quadrilateral MNOP above, find the value of x.

    1. A.16°
    2. B.25°
    3. C.42°
    4. D.39°
    Show answer

    Answer: C. 42°

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  6. 6.

    Given sin⁡58°=cos⁡p°\sin 58° = \cos p°, find p.

    1. A.48°
    2. B.58°
    3. C.32°
    4. D.52°
    Show answer

    Answer: C. 32°

    AI explanation

    Analysis

    The question asks us to find the value of pp given the equation sin⁡58°=cos⁡p°\sin 58° = \cos p°. This is a classic trigonometry problem involving the relationship between complementary angles.

    Concept: Complementary Angles

    In trigonometry, the sine and cosine functions are "cofunctions." This means that the sine of an angle is equal to the cosine of its complement. The complement of an angle θ\theta is (90°−θ)(90° - \theta).

    The fundamental identity is:

    sin⁡θ=cos⁡(90°−θ)\sin \theta = \cos(90° - \theta)

    or conversely:

    cos⁡θ=sin⁡(90°−θ)\cos \theta = \sin(90° - \theta)
    Step-by-Step Solution
    1. Identify the given equation: sin⁡58°=cos⁡p°\sin 58° = \cos p°
    1. Apply the identity: We know that sin⁡θ=cos⁡(90°−θ)\sin \theta = \cos(90° - \theta). Substituting 58°58° for θ\theta: sin⁡58°=cos⁡(90°−58°)\sin 58° = \cos(90° - 58°)
    1. Simplify the expression: 90°−58°=32°90° - 58° = 32° Therefore, sin⁡58°=cos⁡32°\sin 58° = \cos 32°
    1. Compare with the given equation: Since sin⁡58°=cos⁡p°\sin 58° = \cos p° and we found sin⁡58°=cos⁡32°\sin 58° = \cos 32°, it follows that: p=32p = 32
    Conclusion

    Comparing our result with the options provided, we see that p=32°p = 32° corresponds to option C.

    Exam Tip

    Whenever you see sin⁡x=cos⁡y\sin x = \cos y in a JAMB question, simply remember that x+yx + y must equal 90°90°. In this case: 58°+p°=90°  ⟹  p=90°−58°=32°58° + p° = 90° \implies p = 90° - 58° = 32°. This shortcut will save you valuable time during the exam!

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  7. 7.

    If f(x)=3x3+4x2+x−8f(x) = 3x^3 + 4x^2 + x - 8, what is the value of f(-2)?

    1. A.-24
    2. B.30
    3. C.-18
    4. D.-50
    Show answer

    Answer: C. -18

    AI explanation

    Analysis

    To find the value of f(−2)f(-2), we need to perform a process called substitution. This means we replace every instance of the variable xx in the given polynomial with the value −2-2 and then simplify the expression following the BODMAS/PEMDAS rule.

    Concept: Polynomial Evaluation

    A polynomial f(x)f(x) is evaluated at a specific point aa by calculating f(a)f(a). When dealing with negative numbers raised to powers, remember:

    • A negative number raised to an odd power remains negative (e.g., (−2)3=−8(-2)^3 = -8).
    • A negative number raised to an even power becomes positive (e.g., (−2)2=4(-2)^2 = 4).
    Step-by-Step Solution

    Given: f(x)=3x3+4x2+x−8f(x) = 3x^3 + 4x^2 + x - 8

    Step 1: Substitute x=−2x = -2 into the equation f(−2)=3(−2)3+4(−2)2+(−2)−8f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8

    Step 2: Evaluate the powers

    • (−2)3=−2×−2×−2=−8(-2)^3 = -2 \times -2 \times -2 = -8
    • (−2)2=−2×−2=4(-2)^2 = -2 \times -2 = 4

    Now substitute these back: f(−2)=3(−8)+4(4)−2−8f(-2) = 3(-8) + 4(4) - 2 - 8

    Step 3: Perform the multiplications

    • 3×−8=−243 \times -8 = -24
    • 4×4=164 \times 4 = 16

    Now the expression is: f(−2)=−24+16−2−8f(-2) = -24 + 16 - 2 - 8

    Step 4: Simplify the addition and subtraction

    • −24+16=−8-24 + 16 = -8
    • −8−2=−10-8 - 2 = -10
    • −10−8=−18-10 - 8 = -18

    The value of f(−2)f(-2) is -18.

    Conclusion

    Comparing our result to the given options: A. -24 B. 30 C. -18 D. -50

    The correct option is C.

    Exam Tip

    When substituting negative numbers into polynomials, always use brackets. This prevents common sign errors, especially when dealing with terms like −x-x or negative coefficients. Also, double-check your arithmetic for the final addition/subtraction, as that is where most students lose marks in JAMB!

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  8. 8.

    Given matrix M = ∣−2040−16563∣\begin{vmatrix} -2 & 0 & 4 \\ 0 & -1 & 6 \\ 5 & 6 & 3 \end{vmatrix}, find MT+2MM^{T} + 2M

    1. A.∣−421605062∣\begin{vmatrix} -4 & 2 & 1\\ 6 & 0 & 5 \\ 0 & 6 & 2 \end{vmatrix}
    2. B.∣−60130−31814189∣\begin{vmatrix} -6 & 0 & 13\\ 0 & -3 & 18 \\ 14 & 18 & 9 \end{vmatrix}
    3. C.∣52601134−7∣\begin{vmatrix} 5 & 2 & 6 \\ 0 & 1 & 1\\ 3 & 4 & -7 \end{vmatrix}
    4. D.∣−4080−2−1610126∣\begin{vmatrix} -4 & 0 & 8 \\ 0 & -2 & -16 \\ 10 & 12 & 6 \end{vmatrix}
    Show answer

    Answer: B. ∣−60130−31814189∣\begin{vmatrix} -6 & 0 & 13\\ 0 & -3 & 18 \\ 14 & 18 & 9 \end{vmatrix}

    AI explanation

    To solve this problem, we need to perform two operations: find the transpose of matrix MM (MTM^T) and calculate 2M2M, then add them together.

    1. Analyze the components

    Given M=(−2040−16563)M = \begin{pmatrix} -2 & 0 & 4 \\ 0 & -1 & 6 \\ 5 & 6 & 3 \end{pmatrix}

    Step A: Find the Transpose (MTM^T) To find the transpose, we swap the rows and columns. The first row becomes the first column, the second row becomes the second column, and the third row becomes the third column. MT=(−2050−16463)M^T = \begin{pmatrix} -2 & 0 & 5 \\ 0 & -1 & 6 \\ 4 & 6 & 3 \end{pmatrix}

    Step B: Find 2M2M To find 2M2M, we multiply every element inside matrix MM by 2: 2M=2×(−2040−16563)=(−4080−21210126)2M = 2 \times \begin{pmatrix} -2 & 0 & 4 \\ 0 & -1 & 6 \\ 5 & 6 & 3 \end{pmatrix} = \begin{pmatrix} -4 & 0 & 8 \\ 0 & -2 & 12 \\ 10 & 12 & 6 \end{pmatrix}

    2. Perform the Addition (MT+2MM^T + 2M)

    Now, we add the corresponding elements of MTM^T and 2M2M:

    (−2050−16463)+(−4080−21210126)\begin{pmatrix} -2 & 0 & 5 \\ 0 & -1 & 6 \\ 4 & 6 & 3 \end{pmatrix} + \begin{pmatrix} -4 & 0 & 8 \\ 0 & -2 & 12 \\ 10 & 12 & 6 \end{pmatrix}

    • Row 1: (−2+−4)=−6(-2 + -4) = -6, (0+0)=0(0 + 0) = 0, (5+8)=13(5 + 8) = 13
    • Row 2: (0+0)=0(0 + 0) = 0, (−1+−2)=−3(-1 + -2) = -3, (6+12)=18(6 + 12) = 18
    • Row 3: (4+10)=14(4 + 10) = 14, (6+12)=18(6 + 12) = 18, (3+6)=9(3 + 6) = 9

    Resulting Matrix: (−60130−31814189)\begin{pmatrix} -6 & 0 & 13 \\ 0 & -3 & 18 \\ 14 & 18 & 9 \end{pmatrix}

    3. Conclusion

    Comparing our result to the given options, it matches option B.

    Exam Tip: When dealing with matrix operations, always double-check your signs (positive/negative). A common mistake in JAMB is adding a negative number incorrectly (e.g., −1+−2-1 + -2 becoming +1+1 instead of −3-3). Take your time with the arithmetic!

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  9. 9.

    The angles of a polygon are given by 2x, 5x, x and 4x respectively. The value of x is

    1. A.31°
    2. B.30°
    3. C.26°
    4. D.48°
    Show answer

    Answer: B. 30°

    AI explanation

    1. Analyze the question

    We are given the interior angles of a polygon: 2x2x, 5x5x, xx, and 4x4x. We need to find the value of xx. Since there are four angles listed, this is a quadrilateral (a 4-sided polygon).

    2. Explain the concept

    The sum of the interior angles of any polygon is calculated using the formula:

    Sum=(n−2)×180∘\text{Sum} = (n - 2) \times 180^\circ

    where nn is the number of sides.

    For a quadrilateral (n=4n = 4):

    Sum=(4−2)×180∘=2×180∘=360∘\text{Sum} = (4 - 2) \times 180^\circ = 2 \times 180^\circ = 360^\circ

    Therefore, the sum of the given angles must equal 360∘360^\circ.

    3. Show the solution
    • Step 1: Set up the equation by adding all the given angles and equating them to 360∘360^\circ. $2x+5x+x+4x=360∘2x + 5x + x + 4x = 360^\circ$
    • Step 2: Combine the like terms. $(2+5+1+4)x=360∘(2 + 5 + 1 + 4)x = 360^\circ$ $12x=360∘12x = 360^\circ$
    • Step 3: Solve for xx by dividing both sides by 12. $x=360∘12x = \frac{360^\circ}{12}$ $x=30∘x = 30^\circ$
    4. Identify the answer

    Comparing our result to the options provided: A. 31° B. 30° C. 26° D. 48°

    The calculated value matches option B.

    5. Tip

    Whenever you are given the interior angles of a polygon, always count the number of terms to determine nn. Remember the "Sum of interior angles" table:

    • Triangle (n=3n=3): 180∘180^\circ
    • Quadrilateral (n=4n=4): 360∘360^\circ
    • Pentagon (n=5n=5): 540∘540^\circ
    • Hexagon (n=6n=6): 720∘720^\circ

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  10. 10.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  11. 11.

    A bricklayer charges ₦1,500 per day for himself and ₦500 per day for his assistant. If a two bedroom flat was built for ₦95,000 and the bricklayer worked 10 days more than his assistant, how much did the assistant receive?

    1. A.N20,000
    2. B.N28,000
    3. C.N31,200
    4. D.N41,000
    Show answer

    Answer: A. N20,000

    AI explanation

    1. Analyze the Question

    We need to find the total amount paid to the assistant. We are given:

    • Bricklayer's daily rate: ₦1,500
    • Assistant's daily rate: ₦500
    • Total cost of the project: ₦95,000
    • Relationship between days worked: The bricklayer worked 10 days more than the assistant.
    2. Explain the Concept

    This is an algebraic word problem. We can represent the number of days the assistant worked as a variable (xx). Since the bricklayer worked 10 days more, his days will be (x+10)(x + 10). We then set up an equation where the sum of the payments to both equals the total cost.

    3. Show the Solution
    • Let xx = number of days the assistant worked.
    • Then, x+10x + 10 = number of days the bricklayer worked.

    Calculate the total cost: (Bricklayer's rate × Bricklayer's days) + (Assistant's rate × Assistant's days) = Total Cost 1,500(x+10)+500(x)=95,0001,500(x + 10) + 500(x) = 95,000

    Expand and solve for xx: 1,500x+15,000+500x=95,0001,500x + 15,000 + 500x = 95,000 2,000x+15,000=95,0002,000x + 15,000 = 95,000

    Subtract 15,000 from both sides: 2,000x=95,000−15,0002,000x = 95,000 - 15,000 2,000x=80,0002,000x = 80,000

    Divide by 2,000: x=80,0002,000x = \frac{80,000}{2,000} x=40x = 40 days

    The assistant worked for 40 days.

    Calculate the assistant's total pay: Assistant's pay = (Assistant's daily rate) × (Assistant's days) Assistant's pay = 500×40500 \times 40 Assistant's pay = ₦20,000

    4. Identify the Answer

    Comparing our result to the given options, the correct choice is A.

    5. Exam Tip

    When solving "work and pay" problems, always define your variable based on the person who worked the least amount of time. This usually makes the addition in your equation simpler and reduces the chance of making a sign error.

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  12. 12.

    If given two points A(3, 12) and B(5, 22) on a x-y plane. Find the equation of the straight line with intercept at 2.

    1. A.y = 5x + 2
    2. B.y = 5x + 3
    3. C.y = 12x + 2
    4. D.y = 22x + 3
    Show answer

    Answer: A. y = 5x + 2

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  13. 13.

    In how many ways can the word MATHEMATICIAN be arranged?

    1. A.6794800 ways
    2. B.2664910 ways
    3. C.6227020800 ways
    4. D.129729600 ways
    Show answer

    Answer: D. 129729600 ways

    AI explanation

    To solve this problem, we use the formula for permutations of a multiset (arrangements of objects where some are identical).

    1. Analyze the question

    We need to find the number of distinct ways to arrange the letters in the word MATHEMATICIAN.

    2. Explain the concept

    When arranging letters, if some letters repeat, we use the formula:

    Number of arrangements=n!n1!×n2!×⋯×nk!\text{Number of arrangements} = \frac{n!}{n_1! \times n_2! \times \dots \times n_k!}

    Where:

    • nn is the total number of letters.
    • n1,n2,…n_1, n_2, \dots are the frequencies of the repeating letters.
    3. Show the solution

    Step 1: Count the total number of letters (nn). M-A-T-H-E-M-A-T-I-C-I-A-N Counting them: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13. Total letters (nn) = 13

    Step 2: Identify the repeating letters and their frequencies.

    • M: appears 2 times
    • A: appears 3 times
    • T: appears 2 times
    • H: appears 1 time
    • E: appears 1 time
    • I: appears 2 times
    • C: appears 1 time
    • N: appears 1 time

    Step 3: Apply the formula.

    Arrangements=13!2!×3!×2!×2!\text{Arrangements} = \frac{13!}{2! \times 3! \times 2! \times 2!}
    • 13!=6,227,020,80013! = 6,227,020,800
    • 2!=22! = 2
    • 3!=63! = 6
    Arrangements=6,227,020,8002×6×2×2\text{Arrangements} = \frac{6,227,020,800}{2 \times 6 \times 2 \times 2}
    Arrangements=6,227,020,80048\text{Arrangements} = \frac{6,227,020,800}{48}
    Arrangements=129,729,600\text{Arrangements} = 129,729,600
    4. Identify the answer

    Comparing our result to the given options, the correct value is 129,729,600. This matches option D.

    5. Exam Tip

    Always write out the letters and their counts clearly before plugging them into the formula. A common mistake is forgetting to count the "1s" (letters that appear only once), though they don't change the denominator (since 1!=11! = 1), it helps ensure you haven't missed any letters in your total count of 13!

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  14. 14.

    Points X and Y are 20km North and 9km East of point O, respectively. What is the bearing of Y from X? Correct to the nearest degree.

    1. A.24°
    2. B.56°
    3. C.127°
    4. D.156°
    Show answer

    Answer: D. 156°

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  15. 15.

    Find the distance between the points C(2, 2) and D(5, 6).

    1. A.13 units
    2. B.7 units
    3. C.12 units
    4. D.5 units
    Show answer

    Answer: D. 5 units

    AI explanation

    1. Analyze the Question

    We are asked to find the distance between two points on a Cartesian plane: C(2,2)C(2, 2) and D(5,6)D(5, 6).

    2. Explain the Concept

    To find the distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), we use the Distance Formula, which is derived from the Pythagorean theorem:

    d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
    3. Show the Solution
    • Step 1: Identify the coordinates. • Point C(x1,y1)=(2,2)C(x_1, y_1) = (2, 2) • Point D(x2,y2)=(5,6)D(x_2, y_2) = (5, 6)
    • Step 2: Substitute the values into the formula. $d=(5−2)2+(6−2)2d = \sqrt{(5 - 2)^2 + (6 - 2)^2}$
    • Step 3: Simplify the expressions inside the brackets. $d=(3)2+(4)2d = \sqrt{(3)^2 + (4)^2}$
    • Step 4: Calculate the squares. $d=9+16d = \sqrt{9 + 16}$
    • Step 5: Add and find the square root. $d=25d = \sqrt{25}$ $d=5d = 5$
    4. Identify the Answer

    The distance between the two points is 5 units. This corresponds to option D.

    5. Exam Tip

    Whenever you see coordinates involving small integers like 3 and 4, always look out for a 3-4-5 Pythagorean triple. Recognizing these common triangles can save you time during your JAMB exam, as you won't always need to write out the full calculation!

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  16. 16.

    The simple interest on ₦8550 for 3 years at x% per annum is ₦4890. Calculate the value of x to the nearest whole number.

    1. A.19%
    2. B.20%
    3. C.25%
    4. D.16.3%
    Show answer

    Answer: A. 19%

    AI explanation

    Analysis

    To solve this problem, we need to use the standard formula for Simple Interest. We are given the principal, the time, and the interest earned, and we need to find the rate (xx).

    Concept

    The formula for Simple Interest (II) is:

    I=P×R×T100I = \frac{P \times R \times T}{100}

    Where:

    • II = Simple Interest (₦4890)
    • PP = Principal (₦8550)
    • RR = Rate (xx)
    • TT = Time (3 years)
    Step-by-Step Solution
    1. Substitute the given values into the formula: $4890=8550×x×31004890 = \frac{8550 \times x \times 3}{100}$
    1. Simplify the right side: $4890=25650×x1004890 = \frac{25650 \times x}{100}$ $4890=256.5×x4890 = 256.5 \times x$
    1. Solve for xx: $x=4890256.5x = \frac{4890}{256.5}$ $x≈19.064x \approx 19.064$
    1. Round to the nearest whole number: Since 19.064 is closer to 19 than 20, the value of xx to the nearest whole number is 19%.
    Conclusion

    Comparing our result to the options provided, the correct value is 19%.

    Exam Tip

    When dealing with "Simple Interest" questions in JAMB, always write out your variables (P,R,T,IP, R, T, I) first. It prevents you from accidentally swapping the Principal and the Interest, which is a common mistake students make under exam pressure.

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  17. 17.

    Solve for x in 4x−63≤3+2x2\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}

    1. A.x≤112x \leq 1\frac{1}{2}
    2. B.x≤212x \leq \frac{21}{2}
    3. C.x≥212x \geq \frac{21}{2}
    4. D.x≥112x \geq 1\frac{1}{2}
    Show answer

    Answer: B. x≤212x \leq \frac{21}{2}

    AI explanation

    Analysis

    To solve this linear inequality, we need to eliminate the fractions by finding a common denominator and then isolate the variable xx.

    Concept

    When dealing with inequalities involving fractions, the most efficient method is to multiply the entire inequality by the Least Common Multiple (LCM) of the denominators. In this case, the denominators are 3 and 2, so the LCM is 6.

    Important Rule: When multiplying or dividing an inequality by a negative number, you must reverse the inequality sign. Since we are multiplying by a positive 6, the sign remains the same.

    Step-by-Step Solution

    Step 1: Multiply both sides by 6 to clear the fractions.

    6×(4x−63)≤6×(3+2x2)6 \times \left( \frac{4x - 6}{3} \right) \leq 6 \times \left( \frac{3 + 2x}{2} \right)

    Step 2: Simplify the expression.

    2(4x−6)≤3(3+2x)2(4x - 6) \leq 3(3 + 2x)

    Step 3: Expand the brackets.

    8x−12≤9+6x8x - 12 \leq 9 + 6x

    Step 4: Group the xx terms on one side and the constants on the other. Subtract 6x6x from both sides:

    8x−6x−12≤98x - 6x - 12 \leq 9
    2x−12≤92x - 12 \leq 9

    Add 12 to both sides:

    2x≤9+122x \leq 9 + 12
    2x≤212x \leq 21

    Step 5: Solve for xx. Divide both sides by 2:

    x≤212x \leq \frac{21}{2}

    Or, in mixed fraction form:

    x≤1012x \leq 10\frac{1}{2}
    Conclusion

    Comparing our result (x≤212x \leq \frac{21}{2}) with the provided options, it matches option B.

    Exam Tip

    Always check your answer by picking a number that satisfies your result. For example, if x=0x = 0 (which is ≤10.5\leq 10.5), the original inequality becomes −63≤32\frac{-6}{3} \leq \frac{3}{2}, which is −2≤1.5-2 \leq 1.5. Since this is true, your solution is likely correct!

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  18. 18.

    Find the equation of the locus of a point A(x, y) which is equidistant from B(0, 2) and C(2, 1)

    1. A.4x + 2y = 3
    2. B.4x - 3y = 1
    3. C.4x - 2y = 1
    4. D.4x + 2y = -1
    Show answer

    Answer: C. 4x - 2y = 1

    AI explanation

    1. Analyze the question

    We are looking for the equation of the locus of a point A(x,y)A(x, y) that is equidistant from two fixed points, B(0,2)B(0, 2) and C(2,1)C(2, 1). This means the distance from AA to BB is equal to the distance from AA to CC.

    2. Explain the concept

    The distance dd between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the distance formula: d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

    Since the point A(x,y)A(x, y) is equidistant from BB and CC, then AB=ACAB = AC. To make the calculation easier, we square both sides: AB2=AC2AB^2 = AC^2

    3. Show the solution

    Step 1: Set up the distance equations. For AB2AB^2: AB2=(x−0)2+(y−2)2AB^2 = (x - 0)^2 + (y - 2)^2 AB2=x2+(y2−4y+4)AB^2 = x^2 + (y^2 - 4y + 4)

    For AC2AC^2: AC2=(x−2)2+(y−1)2AC^2 = (x - 2)^2 + (y - 1)^2 AC2=(x2−4x+4)+(y2−2y+1)AC^2 = (x^2 - 4x + 4) + (y^2 - 2y + 1)

    Step 2: Equate AB2AB^2 and AC2AC^2. x2+y2−4y+4=x2−4x+4+y2−2y+1x^2 + y^2 - 4y + 4 = x^2 - 4x + 4 + y^2 - 2y + 1

    Step 3: Simplify the equation. Subtract x2x^2 and y2y^2 from both sides: −4y+4=−4x+4−2y+1-4y + 4 = -4x + 4 - 2y + 1

    Combine the constants and variables: −4y+4=−4x−2y+5-4y + 4 = -4x - 2y + 5

    Move all terms involving xx and yy to one side and constants to the other: 4x−4y+2y=5−44x - 4y + 2y = 5 - 4 4x−2y=14x - 2y = 1

    4. Identify the answer

    Comparing our result 4x−2y=14x - 2y = 1 to the given options, it matches option C.

    5. Tip

    When dealing with "equidistant" problems, always square both sides immediately to get rid of the square root sign. This saves time and prevents errors involving radicals. Also, remember that the locus of a point equidistant from two points is simply the perpendicular bisector of the line segment joining those two points!

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  19. 19.

    Determine the values for which x2−7x+10≤0x^2 - 7x + 10 \leq 0

    1. A.2 ≤\leq x ≥\geq 5
    2. B.-2 ≤\leq x ≤\leq 3
    3. C.-2 ≤\leq x ≥\geq 3
    4. D.2 ≤\leq x ≤\leq 5
    Show answer

    Answer: D. 2 ≤\leq x ≤\leq 5

    AI explanation

    Analysis

    To solve the inequality x2−7x+10≤0x^2 - 7x + 10 \leq 0, we need to find the range of values for xx that makes the expression less than or equal to zero. This is a quadratic inequality.

    Concept
    1. Factorize the quadratic expression: We look for two numbers that multiply to give +10+10 and add up to −7-7. These numbers are −2-2 and −5-5.
    2. Find the critical points: Set the factors to zero to find where the expression equals zero.
    3. Test the intervals: Determine which region between the critical points satisfies the "less than or equal to" condition.
    Step-by-Step Solution

    Step 1: Factorize the quadratic x2−7x+10=0x^2 - 7x + 10 = 0 (x−2)(x−5)=0(x - 2)(x - 5) = 0

    Step 2: Identify the critical points x−2=0  ⟹  x=2x - 2 = 0 \implies x = 2 x−5=0  ⟹  x=5x - 5 = 0 \implies x = 5

    Step 3: Determine the interval We have three regions on the number line: x<2x < 2, 2≤x≤52 \leq x \leq 5, and x>5x > 5.

    • If we pick a number between 2 and 5 (e.g., x=3x = 3): (3−2)(3−5)=(1)(−2)=−2(3 - 2)(3 - 5) = (1)(-2) = -2. Since −2≤0-2 \leq 0, this region satisfies the inequality.
    • If we pick a number less than 2 (e.g., x=0x = 0): (0−2)(0−5)=(−2)(−5)=+10(0 - 2)(0 - 5) = (-2)(-5) = +10. Since 1010 is not ≤0\leq 0, this region does not satisfy the inequality.
    • If we pick a number greater than 5 (e.g., x=6x = 6): (6−2)(6−5)=(4)(1)=+4(6 - 2)(6 - 5) = (4)(1) = +4. Since 44 is not ≤0\leq 0, this region does not satisfy the inequality.

    Therefore, the inequality holds true for 2≤x≤52 \leq x \leq 5.

    Conclusion

    The values for which the expression is less than or equal to zero are between 2 and 5 inclusive.

    Exam Tip: For quadratic inequalities of the form (x−a)(x−b)≤0(x - a)(x - b) \leq 0 (where a<ba < b), the solution is always the interval between the roots: a≤x≤ba \leq x \leq b. If the inequality were ≥0\geq 0, the solution would be x≤ax \leq a or x≥bx \geq b.

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  20. 20.

    Evaluate 2log⁡39×log⁡381−2log⁡5625\frac{2\log_{3} 9 \times \log_{3} 81^{-2}}{\log_{5} 625}

    1. A.4
    2. B.-32
    3. C.-8
    4. D.16
    Show answer

    Answer: C. -8

    AI explanation

    To solve this expression, we need to apply the laws of logarithms, specifically the power rule: log⁡b(xn)=nlog⁡b(x)\log_b(x^n) = n \log_b(x) and the definition log⁡b(bn)=n\log_b(b^n) = n.

    1. Analyze and Simplify each term

    The expression is: 2log⁡39×log⁡381−2log⁡5625\frac{2\log_{3} 9 \times \log_{3} 81^{-2}}{\log_{5} 625}

    • Term 1: 2log⁡392\log_{3} 9 Since 9=329 = 3^2, we have: 2log⁡3(32)=2×2log⁡33=4×1=42 \log_{3} (3^2) = 2 \times 2 \log_{3} 3 = 4 \times 1 = \mathbf{4}
    • Term 2: log⁡381−2\log_{3} 81^{-2} Since 81=3481 = 3^4, then 81−2=(34)−2=3−881^{-2} = (3^4)^{-2} = 3^{-8}. So, log⁡3(3−8)=−8\log_{3} (3^{-8}) = \mathbf{-8}
    • Term 3 (Denominator): log⁡5625\log_{5} 625 Since 625=54625 = 5^4, we have: log⁡5(54)=4\log_{5} (5^4) = \mathbf{4}
    2. Substitute the values back into the expression

    Now, substitute these simplified values into the original fraction:

    4×(−8)4\frac{4 \times (-8)}{4}
    3. Final Calculation
    −324=−8\frac{-32}{4} = -8

    Comparing this result to the given options, we find that it matches option C.

    Exam Tip: Whenever you see logarithms with numbers like 9, 81, or 625, always try to express them as powers of the base (e.g., 32,34,543^2, 3^4, 5^4). This makes the log⁡b(bn)=n\log_b(b^n) = n rule very easy to apply and saves you a lot of time during the exam!

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  21. 21.

    If ∣2−4x9∣=58\begin{vmatrix} 2 & -4 \\ x & 9 \end{vmatrix} = 58, find the value of x.

    1. A.10
    2. B.30
    3. C.14
    4. D.28
    Show answer

    Answer: A. 10

    AI explanation

    Analysis

    The question asks us to find the value of xx in a 2×22 \times 2 determinant equation. To solve this, we must apply the standard formula for finding the determinant of a 2×22 \times 2 matrix.

    Concept: Determinant of a 2×22 \times 2 Matrix

    For any 2×22 \times 2 matrix given as: A=∣abcd∣A = \begin{vmatrix} a & b \\ c & d \end{vmatrix}

    The determinant is calculated using the formula: det(A)=(a×d)−(b×c)\text{det}(A) = (a \times d) - (b \times c)

    Step-by-Step Solution

    Given the matrix: ∣2−4x9∣=58\begin{vmatrix} 2 & -4 \\ x & 9 \end{vmatrix} = 58

    Step 1: Apply the determinant formula (2×9)−(−4×x)=58(2 \times 9) - (-4 \times x) = 58

    Step 2: Simplify the multiplication 18−(−4x)=5818 - (-4x) = 58 18+4x=5818 + 4x = 58

    Step 3: Isolate the term with xx Subtract 18 from both sides of the equation: 4x=58−184x = 58 - 18 4x=404x = 40

    Step 4: Solve for xx Divide both sides by 4: x=404x = \frac{40}{4} x=10x = 10

    Conclusion

    Comparing our result to the provided options, the value of xx is 10.

    Exam Tip

    When dealing with determinants involving negative numbers, always be extra careful with the signs. Remember that subtracting a negative number (like −(−4x)-(-4x)) is the same as adding a positive number (+4x+4x). This is a common place where students lose marks due to simple sign errors!

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  22. 22.

    The locus of a point which moves so that it is equidistant from two intersecting straight lines is the

    1. A.bisector of the two lines
    2. B.line parallel to the two lines
    3. C.angle bisector of the two lines
    4. D.perpendicular bisector of the two lines
    Show answer

    Answer: C. angle bisector of the two lines

    AI explanation

    Analysis

    The question asks for the geometric path (locus) traced by a point that maintains an equal distance from two lines that intersect at a point.

    Concept: Locus of Points

    In geometry, a locus is the set of all points that satisfy a specific condition.

    • When two straight lines intersect, they form angles at the point of intersection.
    • If a point is equidistant from two intersecting lines, it must lie on a line that divides the angle between those two lines into two equal parts. This line is known as the angle bisector.
    • Because two intersecting lines create two pairs of vertically opposite angles, there are actually two such bisectors (the internal and external angle bisectors), both of which are straight lines passing through the point of intersection.
    Step-by-Step Solution
    1. Visualize the intersection: Imagine two lines crossing like an 'X'.
    2. Define the condition: We are looking for a point P(x,y)P(x, y) such that the perpendicular distance from PP to Line 1 is equal to the perpendicular distance from PP to Line 2.
    3. Apply the geometric property: The set of points that are equidistant from two intersecting lines are the lines that bisect the angles formed by the intersection.
    4. Evaluate the options: • A "bisector of the two lines" is vague. • A "line parallel to the two lines" would not be equidistant to both unless the lines were parallel themselves (which they are not). • An "angle bisector" specifically describes the line that maintains equal distance from the two intersecting sides of an angle. • A "perpendicular bisector" refers to a line that cuts a line segment into two equal parts at a 90-degree angle, which is not the case here.
    Conclusion

    The locus of a point equidistant from two intersecting lines is the pair of lines that bisect the angles formed by the intersection. Among the given options, "angle bisector" is the mathematically correct term.

    Exam Tip

    Whenever you see the phrase "equidistant from two lines," immediately think of angle bisectors. If the question mentions "equidistant from two points," think of the perpendicular bisector. Don't confuse the two!

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  23. 23.

    Evaluate 2sin⁡30+5tan⁡60sin⁡60\frac{2\sin 30 + 5\tan 60}{\sin 60}, leaving your answer in surd form.

    1. A.233+10\frac{2\sqrt{3}}{3} + 10
    2. B.32−15\frac{3\sqrt{2} - 1}{5}
    3. C.32+15\frac{3\sqrt{2} + 1}{5}
    4. D.233−10\frac{2\sqrt{3}}{3} - 10
    Show answer

    Answer: A. 233+10\frac{2\sqrt{3}}{3} + 10

    Get a step-by-step AI explanation in the app

  24. 24.

    If P=(Q(R−T)15)13P = (\frac{Q(R - T)}{15})^{\frac{1}{3}}, make T the subject of the formula.

    1. A.T=15R−QP3T = \frac{15R - Q}{P^3}
    2. B.T=R−15P3QT = R - \frac{15P^3}{Q}
    3. C.T=R−15P3QT = \frac{R - 15P^3}{Q}
    4. D.T=R+P315QT = \frac{R + P^3}{15Q}
    Show answer

    Answer: B. T=R−15P3QT = R - \frac{15P^3}{Q}

    AI explanation

    To make TT the subject of the formula, we need to isolate it by performing inverse operations step-by-step.

    1. Analyze the equation

    We are given:

    P=(Q(R−T)15)13P = \left( \frac{Q(R - T)}{15} \right)^{\frac{1}{3}}

    Our goal is to move everything away from TT until it stands alone on one side of the equation.

    2. Step-by-step solution

    Step 1: Remove the cube root (the power of 1/31/3) To eliminate the exponent of 13\frac{1}{3}, we raise both sides of the equation to the power of 3:

    P3=[(Q(R−T)15)13]3P^3 = \left[ \left( \frac{Q(R - T)}{15} \right)^{\frac{1}{3}} \right]^3
    P3=Q(R−T)15P^3 = \frac{Q(R - T)}{15}

    Step 2: Clear the fraction Multiply both sides by 15 to remove the denominator:

    15P3=Q(R−T)15P^3 = Q(R - T)

    Step 3: Isolate the term containing TT Divide both sides by QQ:

    15P3Q=R−T\frac{15P^3}{Q} = R - T

    Step 4: Solve for TT To get TT by itself, we can move TT to the left side (making it positive) and move 15P3Q\frac{15P^3}{Q} to the right side (making it negative):

    T=R−15P3QT = R - \frac{15P^3}{Q}
    3. Conclusion

    Comparing our result to the given options, we can see that our derived formula matches option B.

    4. Exam Tip

    When dealing with "change of subject" questions, always remember the Reverse Order of Operations (SADMEP). Usually, you undo addition/subtraction first, then multiplication/division, then exponents/roots. However, because the term (R−T)(R-T) was trapped inside a bracket with a power, we had to deal with the power first!

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  25. 25.

    Find the value of k in the equation: 28+112−k=175\sqrt{28} + \sqrt{112} - \sqrt{k} = \sqrt{175}

    1. A.28\sqrt{28}
    2. B.7
    3. C.28
    4. D.7\sqrt{7}
    Show answer

    Answer: B. 7

    AI explanation

    To solve this problem, we need to simplify each square root by expressing the numbers under the radicals as products of perfect squares.

    1. Analyze the question

    We are given the equation: 28+112−k=175\sqrt{28} + \sqrt{112} - \sqrt{k} = \sqrt{175}. Our goal is to isolate k\sqrt{k} and solve for kk.

    2. Explain the concept

    To simplify a square root, we look for the largest perfect square factor (e.g., 4, 9, 16, 25, 36, 49, 64, 81, 100) that divides the number. For example, 28=4×7=4×7=27\sqrt{28} = \sqrt{4 \times 7} = \sqrt{4} \times \sqrt{7} = 2\sqrt{7}.

    3. Show the solution

    Step 1: Simplify each radical term.

    • 28=4×7=27\sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7}
    • 112=16×7=47\sqrt{112} = \sqrt{16 \times 7} = 4\sqrt{7}
    • 175=25×7=57\sqrt{175} = \sqrt{25 \times 7} = 5\sqrt{7}

    Step 2: Substitute these back into the original equation. 27+47−k=572\sqrt{7} + 4\sqrt{7} - \sqrt{k} = 5\sqrt{7}

    Step 3: Combine the terms on the left side. (2+4)7−k=57(2 + 4)\sqrt{7} - \sqrt{k} = 5\sqrt{7} 67−k=576\sqrt{7} - \sqrt{k} = 5\sqrt{7}

    Step 4: Solve for k\sqrt{k}. Subtract 676\sqrt{7} from both sides: −k=57−67-\sqrt{k} = 5\sqrt{7} - 6\sqrt{7} −k=−17-\sqrt{k} = -1\sqrt{7} k=7\sqrt{k} = \sqrt{7}

    Step 5: Find kk. Square both sides of the equation: (k)2=(7)2(\sqrt{k})^2 = (\sqrt{7})^2 k=7k = 7

    4. Identify the answer

    Comparing our result to the given options, k=7k = 7 matches option B.

    5. Exam Tip

    When dealing with surds in JAMB, always try to express all terms in the equation in terms of the smallest possible surd (in this case, 7\sqrt{7}). This makes adding and subtracting them as easy as adding simple algebraic terms like 2x+4x2x + 4x.

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  26. 26.

    If a fair coin is tossed 3 times, what is the probability of getting at least two heads?

    1. A.23\frac{2}{3}
    2. B.45\frac{4}{5}
    3. C.25\frac{2}{5}
    4. D.12\frac{1}{2}
    Show answer

    Answer: D. 12\frac{1}{2}

    Get a step-by-step AI explanation in the app

  27. 27.

    Given the matrix A=∣3−216∣A = \begin{vmatrix} 3 & -2 \\ 1 & 6 \end{vmatrix}. Find the inverse of matrix A.

    1. A.∣6216∣\begin{vmatrix} 6 & 2 \\ 1 & 6 \end{vmatrix}
    2. B.∣211112320110∣\begin{vmatrix} \frac{2}{11} & \frac{1}{12}\\ \frac{3}{20} & \frac{1}{10} \end{vmatrix}
    3. C.∣−32−1−6∣\begin{vmatrix} -3 & 2 \\ -1 & -6 \end{vmatrix}
    4. D.∣310110−120320∣\begin{vmatrix} \frac{3}{10} & \frac{1}{10} \\ \frac{-1}{20} & \frac{3}{20}\end{vmatrix}
    Show answer

    Answer: D. ∣310110−120320∣\begin{vmatrix} \frac{3}{10} & \frac{1}{10} \\ \frac{-1}{20} & \frac{3}{20}\end{vmatrix}

    AI explanation

    To find the inverse of a 2×22 \times 2 matrix A=(abcd)A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}, we use the formula:

    A−1=1det⁡(A)(d−b−ca)A^{-1} = \frac{1}{\det(A)} \begin{pmatrix} d & -b \\ -c & a \end{pmatrix}

    where det⁡(A)=(ad−bc)\det(A) = (ad - bc) is the determinant of the matrix.

    Step 1: Calculate the determinant of A

    Given A=(3−216)A = \begin{pmatrix} 3 & -2 \\ 1 & 6 \end{pmatrix}:

    • a=3,b=−2,c=1,d=6a = 3, b = -2, c = 1, d = 6
    • det⁡(A)=(3×6)−(−2×1)\det(A) = (3 \times 6) - (-2 \times 1)
    • det⁡(A)=18−(−2)\det(A) = 18 - (-2)
    • det⁡(A)=18+2=20\det(A) = 18 + 2 = 20
    Step 2: Apply the inverse formula

    Now, swap the elements on the leading diagonal (33 and 66) and change the signs of the elements on the other diagonal (−2-2 and 11):

    • The adjugate matrix is (62−13)\begin{pmatrix} 6 & 2 \\ -1 & 3 \end{pmatrix}

    Now, multiply by 1det⁡(A)\frac{1}{\det(A)}:

    • A−1=120(62−13)A^{-1} = \frac{1}{20} \begin{pmatrix} 6 & 2 \\ -1 & 3 \end{pmatrix}
    • A−1=(620220−120320)A^{-1} = \begin{pmatrix} \frac{6}{20} & \frac{2}{20} \\ \frac{-1}{20} & \frac{3}{20} \end{pmatrix}
    Step 3: Simplify the fractions
    • 620=310\frac{6}{20} = \frac{3}{10}
    • 220=110\frac{2}{20} = \frac{1}{10}
    • The matrix becomes (310110−120320)\begin{pmatrix} \frac{3}{10} & \frac{1}{10} \\ \frac{-1}{20} & \frac{3}{20} \end{pmatrix}

    Comparing this result to your options, it matches option D.

    Exam Tip: Always remember the "Swap and Negate" rule for 2×22 \times 2 matrices: Swap the positions of the top-left and bottom-right numbers, and change the signs of the top-right and bottom-left numbers. Don't forget to divide the final matrix by the determinant!

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  28. 28.

    If S = (4t + 3)(t - 2), find ds/dt when t = 5 secs.

    1. A.50 units per sec
    2. B.35 units per sec
    3. C.22 units per sec
    4. D.13 units per sec
    Show answer

    Answer: B. 35 units per sec

    AI explanation

    1. Analyze the question

    We are given a function SS in terms of tt, defined as S=(4t+3)(t−2)S = (4t + 3)(t - 2). We need to find the derivative of SS with respect to tt (dSdt\frac{dS}{dt}) and then evaluate that derivative at t=5t = 5.

    2. Explain the concept

    To solve this, we use the Product Rule of differentiation or expand the brackets first. The expansion method is often simpler for polynomials.

    • Expansion: Multiply the two binomials to get a standard polynomial.
    • Power Rule: If y=axny = ax^n, then dydx=n⋅axn−1\frac{dy}{dx} = n \cdot ax^{n-1}.
    • Differentiation: Once expanded, we differentiate term by term.
    3. Show the solution

    Step 1: Expand the expression for SS S=(4t+3)(t−2)S = (4t + 3)(t - 2) S=4t(t)+4t(−2)+3(t)+3(−2)S = 4t(t) + 4t(-2) + 3(t) + 3(-2) S=4t2−8t+3t−6S = 4t^2 - 8t + 3t - 6 S=4t2−5t−6S = 4t^2 - 5t - 6

    Step 2: Differentiate SS with respect to tt Using the power rule: dSdt=ddt(4t2)−ddt(5t)−ddt(6)\frac{dS}{dt} = \frac{d}{dt}(4t^2) - \frac{d}{dt}(5t) - \frac{d}{dt}(6) dSdt=(2×4)t2−1−(1×5)t1−1−0\frac{dS}{dt} = (2 \times 4)t^{2-1} - (1 \times 5)t^{1-1} - 0 dSdt=8t−5\frac{dS}{dt} = 8t - 5

    Step 3: Evaluate at t=5t = 5 Substitute t=5t = 5 into the derivative: dSdt=8(5)−5\frac{dS}{dt} = 8(5) - 5 dSdt=40−5\frac{dS}{dt} = 40 - 5 dSdt=35\frac{dS}{dt} = 35

    4. Identify the answer

    The result is 35 units per sec. Comparing this to the given options: A. 50 B. 35 C. 22 D. 13

    The correct option is B.

    5. Tip

    When you see a product of two brackets, always check if expanding them is faster than using the Product Rule formula [udvdt+vdudt][u \frac{dv}{dt} + v \frac{du}{dt}]. For simple polynomials like this, expansion saves time and reduces the risk of errors during your JAMB exam!

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  29. 29.

    Integrate ∫(4x−3−7x2+5x−6)dx\int (4x^{-3} - 7x^2 + 5x - 6) \mathrm d x.

    1. A.−2x−2−73x3+52x2−6x-2x^{-2} - \frac{7}{3}x^3 + \frac{5}{2} x^2 - 6x
    2. B.2x2+73x3−5x+62x^2 + \frac{7}{3} x^3 - 5x + 6
    3. C.12x2+14x−512x^2 + 14x - 5
    4. D.−12x−4−14x+5-12x^{-4} - 14x + 5
    Show answer

    Answer: A. −2x−2−73x3+52x2−6x-2x^{-2} - \frac{7}{3}x^3 + \frac{5}{2} x^2 - 6x

    AI explanation

    To solve this integral, we use the Power Rule for Integration.

    1. Analyze the Concept

    The power rule states that for any term axnax^n (where n≠−1n \neq -1):

    ∫axn dx=axn+1n+1+C\int ax^n \, dx = \frac{ax^{n+1}}{n+1} + C

    Essentially, you add 1 to the exponent and then divide the term by that new exponent. We apply this rule to each term in the expression individually.

    2. Step-by-Step Solution

    We are integrating: ∫(4x−3−7x2+5x1−6x0) dx\int (4x^{-3} - 7x^2 + 5x^1 - 6x^0) \, dx

    • Term 1: 4x−34x^{-3} Add 1 to the exponent: −3+1=−2-3 + 1 = -2. Divide by the new exponent: 4x−2−2=−2x−2\frac{4x^{-2}}{-2} = -2x^{-2}
    • Term 2: −7x2-7x^2 Add 1 to the exponent: 2+1=32 + 1 = 3. Divide by the new exponent: −7x33=−73x3-\frac{7x^3}{3} = -\frac{7}{3}x^3
    • Term 3: 5x15x^1 Add 1 to the exponent: 1+1=21 + 1 = 2. Divide by the new exponent: 5x22=52x2\frac{5x^2}{2} = \frac{5}{2}x^2
    • Term 4: −6-6 (which is −6x0-6x^0) Add 1 to the exponent: 0+1=10 + 1 = 1. Divide by the new exponent: −6x11=−6x-\frac{6x^1}{1} = -6x
    3. Combine the results

    Putting these together, we get:

    −2x−2−73x3+52x2−6x+C-2x^{-2} - \frac{7}{3}x^3 + \frac{5}{2}x^2 - 6x + C

    Comparing this result to your given options, it matches Option A.

    Exam Tip

    When integrating, always check your work by differentiating your answer. If you differentiate −2x−2−73x3+52x2−6x-2x^{-2} - \frac{7}{3}x^3 + \frac{5}{2}x^2 - 6x, you will arrive back at the original expression (4x−3−7x2+5x−6)(4x^{-3} - 7x^2 + 5x - 6). This is a great way to guarantee you haven't made a sign error during the exam!

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  30. 30.

    If the volume of a frustrum is given as V=πh3(R2+Rr+r2)V = \frac{\pi h}{3} (R^2 + Rr + r^2), find dV dR\frac{\mathrm d V}{\mathrm d R}.

    1. A.πh3(2R+r)\frac{\pi h}{3} (2R + r)
    2. B.2R+r+πh32R + r + \frac{\pi h}{3}
    3. C.πh3(2R2+r+2r)\frac{\pi h}{3} (2R^2 + r + 2r)
    4. D.2R23πh\frac{2R^2}{3} \pi h
    Show answer

    Answer: A. πh3(2R+r)\frac{\pi h}{3} (2R + r)

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  31. 31.

    Integrate ∫−12(2x2+x)dx\int_{-1} ^{2} (2x^2 + x) \mathrm {d} x

    1. A.4124\frac{1}{2}
    2. B.3123\frac{1}{2}
    3. C.7127\frac{1}{2}
    4. D.5145\frac{1}{4}
    Show answer

    Answer: C. 7127\frac{1}{2}

    AI explanation

    1. Analyze the question

    We are required to evaluate a definite integral of the polynomial function (2x2+x)(2x^2 + x) over the interval [−1,2][-1, 2].

    2. Explain the concept

    To solve this, we use the Power Rule for Integration, which states:

    ∫xn dx=xn+1n+1\int x^n \, dx = \frac{x^{n+1}}{n+1}

    For a definite integral ∫abf(x) dx\int_{a}^{b} f(x) \, dx, we find the antiderivative F(x)F(x) and then calculate F(b)−F(a)F(b) - F(a).

    3. Show the solution

    Step 1: Find the indefinite integral

    ∫(2x2+x) dx=2(x33)+x22=2x33+x22\int (2x^2 + x) \, dx = 2\left(\frac{x^3}{3}\right) + \frac{x^2}{2} = \frac{2x^3}{3} + \frac{x^2}{2}

    Step 2: Apply the limits from -1 to 2

    [2x33+x22]−12\left[ \frac{2x^3}{3} + \frac{x^2}{2} \right]_{-1}^{2}

    Step 3: Substitute the upper limit (2)

    F(2)=2(2)33+(2)22=2(8)3+42=163+2F(2) = \frac{2(2)^3}{3} + \frac{(2)^2}{2} = \frac{2(8)}{3} + \frac{4}{2} = \frac{16}{3} + 2

    Convert 2 to a fraction with denominator 3: 2=632 = \frac{6}{3}

    F(2)=163+63=223F(2) = \frac{16}{3} + \frac{6}{3} = \frac{22}{3}

    Step 4: Substitute the lower limit (-1)

    F(−1)=2(−1)33+(−1)22=2(−1)3+12=−23+12F(-1) = \frac{2(-1)^3}{3} + \frac{(-1)^2}{2} = \frac{2(-1)}{3} + \frac{1}{2} = -\frac{2}{3} + \frac{1}{2}

    Find a common denominator (6):

    F(−1)=−46+36=−16F(-1) = -\frac{4}{6} + \frac{3}{6} = -\frac{1}{6}

    Step 5: Calculate F(2)−F(−1)F(2) - F(-1)

    223−(−16)=223+16\frac{22}{3} - \left( -\frac{1}{6} \right) = \frac{22}{3} + \frac{1}{6}

    Convert 223\frac{22}{3} to a fraction with denominator 6: 446\frac{44}{6}

    446+16=456\frac{44}{6} + \frac{1}{6} = \frac{45}{6}

    Simplify the fraction by dividing by 3:

    45÷36÷3=152=712\frac{45 \div 3}{6 \div 3} = \frac{15}{2} = 7\frac{1}{2}
    4. Identify the answer

    The result is 7127\frac{1}{2}, which matches option C.

    5. Tip

    When dealing with definite integrals involving negative limits, be extremely careful with the signs during the subtraction step (F(b)−F(a)F(b) - F(a)). A common mistake is to lose a negative sign when subtracting a negative value, which leads to the wrong answer. Always use brackets to keep your signs organized!

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  32. 32.

    If 2x+y^{x + y} = 16 and 4x−y=132^{x - y} = \frac{1}{32}, find the values of x and y.

    1. A.x = 34\frac{3}{4}, y = 114\frac{11}{4}
    2. B.x = 34\frac{3}{4}, y = 134\frac{13}{4}
    3. C.x = 23\frac{2}{3}, y = 45\frac{4}{5}
    4. D.x = 23\frac{2}{3}, y = 134\frac{13}{4}
    Show answer

    Answer: B. x = 34\frac{3}{4}, y = 134\frac{13}{4}

    AI explanation

    To solve this problem, we need to express both sides of the equations with the same base so that we can equate the exponents.

    1. Analyze the equations

    We are given: (i) 2x+y=162^{x + y} = 16 (ii) 4x−y=1324^{x - y} = \frac{1}{32}

    2. Simplify Equation (i)

    Since 16=2416 = 2^4, we can rewrite the equation as: 2x+y=242^{x + y} = 2^4 Equating the exponents: x+y=4x + y = 4 --- (Equation 1)

    3. Simplify Equation (ii)

    We know that 4=224 = 2^2 and 32=2532 = 2^5. Substituting these into the equation: (22)x−y=125(2^2)^{x - y} = \frac{1}{2^5} 22(x−y)=2−52^{2(x - y)} = 2^{-5} Equating the exponents: 2(x−y)=−52(x - y) = -5 x−y=−52x - y = -\frac{5}{2} x−y=−2.5x - y = -2.5 --- (Equation 2)

    4. Solve the simultaneous equations

    We now have:

    1. x+y=4x + y = 4
    2. x−y=−2.5x - y = -2.5

    Add Equation 1 and Equation 2: (x+y)+(x−y)=4+(−2.5)(x + y) + (x - y) = 4 + (-2.5) 2x=1.52x = 1.5 x=1.52=0.75x = \frac{1.5}{2} = 0.75 or 34\frac{3}{4}

    Now, substitute x=34x = \frac{3}{4} into Equation 1: 34+y=4\frac{3}{4} + y = 4 y=4−34y = 4 - \frac{3}{4} y=16−34y = \frac{16 - 3}{4} y=134y = \frac{13}{4}

    5. Conclusion

    The values are x=34x = \frac{3}{4} and y=134y = \frac{13}{4}. This matches option B.

    Exam Tip: When dealing with indices, always try to reduce the numbers to their smallest prime base (like 2, 3, or 5). Remember that 1an=a−n\frac{1}{a^n} = a^{-n}; this is a common trap in JAMB questions that tests your knowledge of negative indices.

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  33. 33.

    23÷4514+35−13\frac{\frac{2}{3} \div \frac{4}{5}}{\frac{1}{4} + \frac{3}{5} - \frac{1}{3}}

    1. A.3150\frac{31}{50}
    2. B.2031\frac{20}{31}
    3. C.3120\frac{31}{20}
    4. D.5031\frac{50}{31}
    Show answer

    Answer: D. 5031\frac{50}{31}

    AI explanation

    To solve this expression, we will simplify the numerator and the denominator separately before performing the final division.

    1. Simplify the Numerator

    The numerator is: 23÷45\frac{2}{3} \div \frac{4}{5}

    When dividing fractions, we multiply by the reciprocal of the divisor:

    23×54=1012\frac{2}{3} \times \frac{5}{4} = \frac{10}{12}

    Simplifying 1012\frac{10}{12} by dividing both numerator and denominator by 2 gives: Numerator = 56\frac{5}{6}

    2. Simplify the Denominator

    The denominator is: 14+35−13\frac{1}{4} + \frac{3}{5} - \frac{1}{3}

    To add and subtract these, we find the Least Common Multiple (LCM) of 4, 5, and 3, which is 60.

    • 14=1560\frac{1}{4} = \frac{15}{60}
    • 35=3660\frac{3}{5} = \frac{36}{60}
    • 13=2060\frac{1}{3} = \frac{20}{60}

    Now, combine them:

    15+36−2060=51−2060=3160\frac{15 + 36 - 20}{60} = \frac{51 - 20}{60} = \frac{31}{60}

    Denominator = 3160\frac{31}{60}

    3. Final Division

    Now, divide the simplified numerator by the simplified denominator:

    56÷3160\frac{5}{6} \div \frac{31}{60}

    Again, multiply by the reciprocal:

    56×6031\frac{5}{6} \times \frac{60}{31}

    We can simplify before multiplying: 6 goes into 60 ten times:

    5×1031=50315 \times \frac{10}{31} = \frac{50}{31}
    Conclusion

    Comparing our result to the given options, we find that it matches option D.

    Exam Tip: When dealing with complex fractions, always handle the numerator and denominator as two separate problems first. This prevents "fraction fatigue" and reduces the likelihood of making a silly calculation error in the middle of the process.

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  34. 34.

    Express (0.0439÷3.62)(0.0439 \div 3.62) as a fraction.

    1. A.21100\frac{21}{100}
    2. B.211000\frac{21}{1000}
    3. C.121000\frac{12}{1000}
    4. D.12100\frac{12}{100}
    Show answer

    Answer: C. 121000\frac{12}{1000}

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  35. 35.

    Find the equation of a line perpendicular to the line 4y = 7x + 3 which passes through (-3, 1)

    1. A.7y + 4x + 5 = 0
    2. B.7y - 4x - 5 = 0
    3. C.3y - 5x + 2 = 0
    4. D.3y + 5x - 2 = 0
    Show answer

    Answer: A. 7y + 4x + 5 = 0

    AI explanation

    1. Analyze the question

    We need to find the equation of a line that is perpendicular to a given line (4y=7x+34y = 7x + 3) and passes through a specific point (−3,1)(-3, 1).

    2. Explain the concept
    • Slope-Intercept Form: A line equation in the form y=mx+cy = mx + c has a slope of mm.
    • Perpendicular Slopes: If two lines are perpendicular, the product of their slopes is −1-1 (m1×m2=−1m_1 \times m_2 = -1). This means the slope of the new line will be the negative reciprocal of the original slope (m2=−1/m1m_2 = -1 / m_1).
    • Point-Slope Form: Once we have the new slope (mm) and a point (x1,y1)(x_1, y_1), we use the formula: y−y1=m(x−x1)y - y_1 = m(x - x_1).
    3. Show the solution

    Step 1: Find the slope of the given line. The equation is 4y=7x+34y = 7x + 3. Divide by 4 to get it into y=mx+cy = mx + c form: y=74x+34y = \frac{7}{4}x + \frac{3}{4} The slope (m1m_1) is 74\frac{7}{4}.

    Step 2: Find the slope of the perpendicular line (m2m_2). Since m1×m2=−1m_1 \times m_2 = -1: 74×m2=−1\frac{7}{4} \times m_2 = -1 m2=−47m_2 = -\frac{4}{7}

    Step 3: Use the point-slope formula with point (−3,1)(-3, 1). y−1=−47(x−(−3))y - 1 = -\frac{4}{7}(x - (-3)) y−1=−47(x+3)y - 1 = -\frac{4}{7}(x + 3)

    Step 4: Simplify the equation. Multiply both sides by 7 to clear the fraction: 7(y−1)=−4(x+3)7(y - 1) = -4(x + 3) 7y−7=−4x−127y - 7 = -4x - 12

    Rearrange to the form Ay+Bx+C=0Ay + Bx + C = 0: 7y+4x−7+12=07y + 4x - 7 + 12 = 0 7y+4x+5=07y + 4x + 5 = 0

    4. Identify the answer

    Comparing our result (7y+4x+5=07y + 4x + 5 = 0) to the given options, it matches option A.

    5. Tip

    When dealing with perpendicular lines, remember the "flip and switch" rule: flip the fraction of the slope and switch the sign (e.g., 74\frac{7}{4} becomes −47-\frac{4}{7}). This saves you time during your JAMB exam!

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  36. 36.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  37. 37.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  38. 38.

    In a committee of 5, which must be selected from 4 males and 3 females. In how many ways can the members be chosen if it were to include 2 females?

    1. A.144 ways
    2. B.15 ways
    3. C.185 ways
    4. D.12 ways
    Show answer

    Answer: D. 12 ways

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  39. 39.

    A binary operation ⊗\otimes is defined by m⊗ n=mn+m−nm \otimes n = mn + m - n on the set of real numbers, for all m, n ∈\in R. Find the value of 3 ⊗\otimes (2 ⊗\otimes 4).

    1. A.6
    2. B.25
    3. C.15
    4. D.18
    Show answer

    Answer: C. 15

    AI explanation

    To solve this problem, we need to apply the given binary operation rule step by step, following the order of operations (BODMAS), which requires us to solve the expression inside the parentheses first.

    1. Analyze the operation

    The rule is defined as: m⊗n=mn+m−nm \otimes n = mn + m - n

    We need to find the value of: 3⊗(2⊗4)3 \otimes (2 \otimes 4)

    2. Solve the inner bracket: (2⊗4)(2 \otimes 4)

    Using the rule m⊗n=mn+m−nm \otimes n = mn + m - n, where m=2m = 2 and n=4n = 4: (2⊗4)=(2×4)+2−4(2 \otimes 4) = (2 \times 4) + 2 - 4 (2⊗4)=8+2−4(2 \otimes 4) = 8 + 2 - 4 (2⊗4)=10−4(2 \otimes 4) = 10 - 4 (2⊗4)=6(2 \otimes 4) = 6

    3. Solve the final expression: 3⊗63 \otimes 6

    Now substitute the result back into the original expression: 3⊗(2⊗4)=3⊗63 \otimes (2 \otimes 4) = 3 \otimes 6

    Using the rule again, where m=3m = 3 and n=6n = 6: 3⊗6=(3×6)+3−63 \otimes 6 = (3 \times 6) + 3 - 6 3⊗6=18+3−63 \otimes 6 = 18 + 3 - 6 3⊗6=21−63 \otimes 6 = 21 - 6 3⊗6=153 \otimes 6 = 15

    4. Conclusion

    Comparing our result to the options provided: A. 6 B. 25 C. 15 D. 18

    The calculated value is 15, which matches option C.

    Exam Tip: When dealing with binary operations involving brackets, always treat the bracketed part as a single number first. Never try to distribute the operation across the brackets, as binary operations are not always distributive!

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  40. 40.

    Rationalize 2+32−3\frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} - \sqrt{3}}

    1. A.−5−26-5 - 2\sqrt{6}
    2. B.−5+32-5 + 3\sqrt{2}
    3. C.5−235 - 2\sqrt{3}
    4. D.5+265 + 2\sqrt{6}
    Show answer

    Answer: A. −5−26-5 - 2\sqrt{6}

    AI explanation

    Analysis

    To rationalize a fraction with a surd in the denominator, we multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of (2−3)(\sqrt{2} - \sqrt{3}) is (2+3)(\sqrt{2} + \sqrt{3}).

    Concept

    Rationalization removes the square root from the denominator. We use the difference of two squares identity: (a−b)(a+b)=a2−b2(a - b)(a + b) = a^2 - b^2.

    Step-by-Step Solution

    Step 1: Set up the multiplication

    2+32−3×2+32+3\frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} - \sqrt{3}} \times \frac{\sqrt{2} + \sqrt{3}}{\sqrt{2} + \sqrt{3}}

    Step 2: Expand the numerator Using the FOIL method (First, Outer, Inner, Last): (2+3)(2+3)=(2)2+23+32+(3)2(\sqrt{2} + \sqrt{3})(\sqrt{2} + \sqrt{3}) = (\sqrt{2})^2 + \sqrt{2}\sqrt{3} + \sqrt{3}\sqrt{2} + (\sqrt{3})^2 =2+6+6+3= 2 + \sqrt{6} + \sqrt{6} + 3 =5+26= 5 + 2\sqrt{6}

    Step 3: Expand the denominator Using the difference of two squares: (2−3)(2+3)=(2)2−(3)2(\sqrt{2} - \sqrt{3})(\sqrt{2} + \sqrt{3}) = (\sqrt{2})^2 - (\sqrt{3})^2 =2−3= 2 - 3 =−1= -1

    Step 4: Combine and simplify

    5+26−1\frac{5 + 2\sqrt{6}}{-1}

    Divide each term by −1-1: =−5−26= -5 - 2\sqrt{6}

    Conclusion

    Comparing our result to the given options, we find that the calculation matches option A.

    Exam Tip

    When rationalizing, always check the sign of your denominator after squaring. Many students forget that (2)2−(3)2(\sqrt{2})^2 - (\sqrt{3})^2 results in 2−3=−12 - 3 = -1, not 11. If you get a negative denominator, remember to distribute that negative sign to every term in your numerator!

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  41. 41.

    If M varies directly as N and inversely as the root of P. Given that M = 3, N = 5 and P = 25. Find the value of P when M = 2 and N = 6.

    1. A.36
    2. B.63
    3. C.47
    4. D.81
    Show answer

    Answer: D. 81

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  42. 42.

    The angle of elevation of the top of a tree from a point on the ground 60m away from the foot of the tree is 78°. Find the height of the tree correct to the nearest whole number.

    1. A.148m
    2. B.382m
    3. C.282m
    4. D.248m
    Show answer

    Answer: C. 282m

    AI explanation

    1. Analyze the question

    We are given:

    • The distance from the foot of the tree to the point on the ground (adjacent side) = 60m60\text{m}
    • The angle of elevation (θ\theta) = 78∘78^\circ
    • We need to find the height of the tree (opposite side).
    2. Explain the concept

    This is a trigonometry problem involving a right-angled triangle. We use the SOH CAH TOA mnemonic:

    • SOH: sin⁡(θ)=OppositeHypotenuse\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}}
    • CAH: cos⁡(θ)=AdjacentHypotenuse\cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}}
    • TOA: tan⁡(θ)=OppositeAdjacent\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}

    Since we have the Adjacent side and need the Opposite side, we use the Tangent (tan) ratio.

    3. Show the solution

    Step 1: Set up the formula

    tan⁡(θ)=Height of treeDistance from foot\tan(\theta) = \frac{\text{Height of tree}}{\text{Distance from foot}}
    tan⁡(78∘)=h60\tan(78^\circ) = \frac{h}{60}

    Step 2: Solve for hh

    h=60×tan⁡(78∘)h = 60 \times \tan(78^\circ)

    Step 3: Calculate the value Using a calculator, tan⁡(78∘)≈4.7046\tan(78^\circ) \approx 4.7046

    h=60×4.7046h = 60 \times 4.7046
    h=282.276h = 282.276

    Step 4: Round to the nearest whole number Rounding 282.276282.276 to the nearest whole number gives 282m282\text{m}.

    4. Identify the answer

    Comparing our result to the given options: A. 148m B. 382m C. 282m D. 248m

    The correct option is C.

    5. Exam Tip

    When dealing with "angle of elevation" problems, always draw a quick sketch of a right-angled triangle. Remember that the "foot of the tree" is the base, and the "height" is the vertical side. If your calculator gives you a very strange number, ensure it is set to DEG (Degrees) mode and not RAD (Radians) mode!

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  43. 43.

    Simplify 81−34^{\frac{-3}{4}} x 2512^{\frac{1}{2}} x 24325^{\frac{2}{5}}

    1. A.25\frac{2}{5}
    2. B.35\frac{3}{5}
    3. C.52\frac{5}{2}
    4. D.53\frac{5}{3}
    Show answer

    Answer: D. 53\frac{5}{3}

    AI explanation

    To simplify the expression 81−34×2512×2432581^{-\frac{3}{4}} \times 25^{\frac{1}{2}} \times 243^{\frac{2}{5}}, we need to express each base as a power of its prime factors.

    1. Analyze the components
    • 8181: 81=3481 = 3^4
    • 2525: 25=5225 = 5^2
    • 243243: 243=35243 = 3^5
    2. Substitute and apply the Power of a Power rule

    The rule states that (am)n=am×n(a^m)^n = a^{m \times n}. Let's apply this to each term:

    • First term: (34)−34=34×(−34)=3−3(3^4)^{-\frac{3}{4}} = 3^{4 \times (-\frac{3}{4})} = 3^{-3} • Recall that x−n=1xnx^{-n} = \frac{1}{x^n}, so 3−3=133=1273^{-3} = \frac{1}{3^3} = \frac{1}{27}
    • Second term: (52)12=52×12=51=5(5^2)^{\frac{1}{2}} = 5^{2 \times \frac{1}{2}} = 5^1 = 5
    • Third term: (35)25=35×25=32=9(3^5)^{\frac{2}{5}} = 3^{5 \times \frac{2}{5}} = 3^2 = 9
    3. Combine the results

    Now, multiply the simplified values together:

    127×5×9\frac{1}{27} \times 5 \times 9

    We can simplify this by multiplying 5×95 \times 9 first:

    127×45\frac{1}{27} \times 45

    Now, divide both 45 and 27 by their greatest common divisor, which is 9:

    45÷927÷9=53\frac{45 \div 9}{27 \div 9} = \frac{5}{3}
    4. Conclusion

    Comparing our result to the given options, we find that 53\frac{5}{3} matches option D.

    Exam Tip: When dealing with fractional exponents, always look for the prime base that allows the denominator of the exponent to cancel out. For example, seeing a denominator of "4" in the exponent should immediately make you look for a way to express the base as something to the power of 4 (like 81=3481 = 3^4). This makes the calculation much faster!

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  44. 44.

    Find the value of x and y in the simultaneous equation: 3x + y = 21; xy = 30

    1. A.x = 3 or 7, y = 12 or 8
    2. B.x = 6 or 1, y = 11 or 5
    3. C.x = 2 or 5, y = 15 or 6
    4. D.x = 1 or 5, y = 10 or 7
    Show answer

    Answer: C. x = 2 or 5, y = 15 or 6

    AI explanation

    Analysis

    We are given a system of two equations:

    1. 3x+y=213x + y = 21
    2. xy=30xy = 30

    We need to find the values of xx and yy that satisfy both equations simultaneously.

    Concept

    This is a classic simultaneous equation problem where one equation is linear and the other is non-linear (quadratic). The best approach is the substitution method: express one variable in terms of the other using the linear equation and substitute it into the second equation.

    Step-by-Step Solution

    Step 1: Express yy in terms of xx using equation (1). From 3x+y=213x + y = 21: y=21−3xy = 21 - 3x --- (Equation 3)

    Step 2: Substitute Equation (3) into Equation (2). x(21−3x)=30x(21 - 3x) = 30 21x−3x2=3021x - 3x^2 = 30

    Step 3: Rearrange into a standard quadratic equation (ax2+bx+c=0ax^2 + bx + c = 0). Move all terms to one side: 3x2−21x+30=03x^2 - 21x + 30 = 0

    Divide the entire equation by 3 to simplify: x2−7x+10=0x^2 - 7x + 10 = 0

    Step 4: Factorize the quadratic equation. We look for two numbers that multiply to 1010 and add to −7-7. These numbers are −2-2 and −5-5. (x−2)(x−5)=0(x - 2)(x - 5) = 0

    So, x=2x = 2 or x=5x = 5.

    Step 5: Find the corresponding values for yy. Using y=21−3xy = 21 - 3x:

    • If x=2x = 2: y=21−3(2)=21−6=15y = 21 - 3(2) = 21 - 6 = 15
    • If x=5x = 5: y=21−3(5)=21−15=6y = 21 - 3(5) = 21 - 15 = 6

    Thus, the pairs are (x=2,y=15)(x=2, y=15) and (x=5,y=6)(x=5, y=6).

    Conclusion

    Comparing our results to the options provided: Option C states x=2x = 2 or 55 and y=15y = 15 or 66. This matches our calculated values perfectly.

    Exam Tip

    When you have a multiple-choice question like this, you can save time by testing the options. Simply plug the values of xx and yy into the equations. For example, if you test x=2x=2 and y=15y=15: 3(2)+15=6+15=213(2) + 15 = 6 + 15 = 21 (Correct) 2×15=302 \times 15 = 30 (Correct) This confirms Option C is the right choice without needing to solve the full quadratic equation!

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  45. 45.

    In the figure above, |CD| is the base of the triangle CDE. Find the area of the figure to the nearest whole number.

    Diagram for question 45
    1. A.56 cm2^2
    2. B.24 cm2^2
    3. C.42 cm2^2
    4. D.34 cm2^2
    Show answer

    Answer: D. 34 cm2^2

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  46. 46.

    Calculate the volume of the regular three dimensional figure drawn above, where < ABC = 90° (a right- angled triangle).

    Diagram for question 46
    1. A.394 cm3^3
    2. B.425 cm3^3
    3. C.268 cm3^3
    4. D.540 cm3^3
    Show answer

    Answer: B. 425 cm3^3

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  47. 47.

    The nth term of a sequence is given by 22n−1^{2n - 1}. Find the sum of the first four terms.

    1. A.74
    2. B.32
    3. C.42
    4. D.170
    Show answer

    Answer: D. 170

    AI explanation

    1. Analyze the question

    We are given the general formula for the nthn^{th} term of a sequence: Tn=22n−1T_n = 2^{2n - 1}. We need to find the sum of the first four terms (S4S_4), which means calculating T1,T2,T3,T_1, T_2, T_3, and T4T_4 and adding them together.

    2. Explain the concept

    A sequence is an ordered list of numbers. To find the sum of the first nn terms, we evaluate the formula for each value of nn from 1 to nn and find their total.

    • For n=1n=1: T1=22(1)−1T_1 = 2^{2(1) - 1}
    • For n=2n=2: T2=22(2)−1T_2 = 2^{2(2) - 1}
    • And so on.
    3. Show the solution

    Let's calculate each term individually:

    • For n=1n = 1: T1=22(1)−1=22−1=21=2T_1 = 2^{2(1) - 1} = 2^{2 - 1} = 2^1 = 2
    • For n=2n = 2: T2=22(2)−1=24−1=23=8T_2 = 2^{2(2) - 1} = 2^{4 - 1} = 2^3 = 8
    • For n=3n = 3: T3=22(3)−1=26−1=25=32T_3 = 2^{2(3) - 1} = 2^{6 - 1} = 2^5 = 32
    • For n=4n = 4: T4=22(4)−1=28−1=27=128T_4 = 2^{2(4) - 1} = 2^{8 - 1} = 2^7 = 128

    Now, find the sum (S4S_4): S4=T1+T2+T3+T4S_4 = T_1 + T_2 + T_3 + T_4 S4=2+8+32+128S_4 = 2 + 8 + 32 + 128 S4=10+32+128S_4 = 10 + 32 + 128 S4=42+128S_4 = 42 + 128 S4=170S_4 = 170

    4. Identify the answer

    Comparing our result to the given options, the correct sum is 170, which corresponds to option D.

    5. Exam Tip

    When dealing with exponential sequences, always double-check your powers. A common mistake is to multiply the base by the exponent instead of raising the base to the power. Also, notice that this is a Geometric Progression (GP) where the first term a=2a = 2 and the common ratio r=4r = 4. You could also use the sum formula for a GP: Sn=a(rn−1)r−1S_n = \frac{a(r^n - 1)}{r - 1}. S4=2(44−1)4−1=2(256−1)3=2(255)3=2×85=170S_4 = \frac{2(4^4 - 1)}{4 - 1} = \frac{2(256 - 1)}{3} = \frac{2(255)}{3} = 2 \times 85 = 170.

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  48. 48.

    If 2x2^2 + x - 3 divides x - 2, find the remainder.

    1. A.7
    2. B.3
    3. C.5
    4. D.6
    Show answer

    Answer: A. 7

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  49. 49.

    If 6x3+2x2−5x+16x^3 + 2x^2 - 5x + 1 divides x2−x−1x^2 - x - 1, find the remainder.

    1. A.9x + 9
    2. B.2x + 6
    3. C.6x + 8
    4. D.5x - 3
    Show answer

    Answer: A. 9x + 9

    AI explanation

    To solve this problem, we need to perform polynomial long division. We are dividing the polynomial P(x)=6x3+2x2−5x+1P(x) = 6x^3 + 2x^2 - 5x + 1 by the divisor D(x)=x2−x−1D(x) = x^2 - x - 1.

    1. Analyze the question

    We are dividing a cubic polynomial by a quadratic polynomial. The result will be a linear quotient and a linear remainder (since the degree of the remainder must be less than the degree of the divisor).

    2. Explain the concept

    Polynomial long division follows the same logic as numerical long division:

    • Divide the leading term of the dividend by the leading term of the divisor.
    • Multiply the entire divisor by the result.
    • Subtract the result from the current dividend.
    • Repeat until the degree of the remainder is less than the degree of the divisor.
    3. Show the solution

    Step 1: Divide the first terms Divide 6x36x^3 by x2x^2: 6x3/x2=6x6x^3 / x^2 = 6x

    Step 2: Multiply and Subtract Multiply 6x6x by (x2−x−1)(x^2 - x - 1): 6x(x2−x−1)=6x3−6x2−6x6x(x^2 - x - 1) = 6x^3 - 6x^2 - 6x

    Subtract this from the original polynomial: (6x3+2x2−5x+1)−(6x3−6x2−6x)(6x^3 + 2x^2 - 5x + 1) - (6x^3 - 6x^2 - 6x) =(6x3−6x3)+(2x2−(−6x2))+(−5x−(−6x))+1= (6x^3 - 6x^3) + (2x^2 - (-6x^2)) + (-5x - (-6x)) + 1 =8x2+x+1= 8x^2 + x + 1

    Step 3: Divide the new leading term Divide 8x28x^2 by x2x^2: 8x2/x2=88x^2 / x^2 = 8

    Step 4: Multiply and Subtract Multiply 88 by (x2−x−1)(x^2 - x - 1): 8(x2−x−1)=8x2−8x−88(x^2 - x - 1) = 8x^2 - 8x - 8

    Subtract this from the current remainder (8x2+x+18x^2 + x + 1): (8x2+x+1)−(8x2−8x−8)(8x^2 + x + 1) - (8x^2 - 8x - 8) =(8x2−8x2)+(x−(−8x))+(1−(−8))= (8x^2 - 8x^2) + (x - (-8x)) + (1 - (-8)) =9x+9= 9x + 9

    4. Identify the answer

    The remainder is 9x+99x + 9. This matches option A.

    5. Exam Tip

    When performing polynomial subtraction, be very careful with the signs, especially when subtracting a negative term (e.g., −(−6x2)-(-6x^2) becomes +6x2+6x^2). A common mistake in JAMB exams is losing a negative sign during this step. Always write out the subtraction clearly to avoid "silly" errors.

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  50. 50.

    Differentiate 2xsin⁡x\frac{2x}{\sin x} with respect to x.

    1. A.2cot⁡xsec⁡x(1+tan⁡x)2 \cot x \sec x (1 + \tan x)
    2. B.2csc⁡x−xcot⁡x2 \csc x - x \cot x
    3. C.2xcsc⁡x+tan⁡x2x \csc x + \tan x
    4. D.2csc⁡x(1−xcot⁡x)2\csc x(1 - x\cot x)
    Show answer

    Answer: D. 2csc⁡x(1−xcot⁡x)2\csc x(1 - x\cot x)

    AI explanation

    1. Analyze the Question

    We are asked to find the derivative of the function y=2xsin⁡xy = \frac{2x}{\sin x} with respect to xx. Since this is a quotient of two functions, we must use the Quotient Rule.

    2. Explain the Concept

    The Quotient Rule states that if you have a function y=uvy = \frac{u}{v}, its derivative is given by:

    dydx=vdudx−udvdxv2\frac{dy}{dx} = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}

    In this problem:

    • u=2x  ⟹  dudx=2u = 2x \implies \frac{du}{dx} = 2
    • v=sin⁡x  ⟹  dvdx=cos⁡xv = \sin x \implies \frac{dv}{dx} = \cos x
    3. Show the Solution

    Substitute these values into the Quotient Rule formula:

    dydx=(sin⁡x)(2)−(2x)(cos⁡x)(sin⁡x)2\frac{dy}{dx} = \frac{(\sin x)(2) - (2x)(\cos x)}{(\sin x)^2}

    Simplify the expression:

    dydx=2sin⁡x−2xcos⁡xsin⁡2x\frac{dy}{dx} = \frac{2\sin x - 2x\cos x}{\sin^2 x}

    Now, split the fraction into two parts:

    dydx=2sin⁡xsin⁡2x−2xcos⁡xsin⁡2x\frac{dy}{dx} = \frac{2\sin x}{\sin^2 x} - \frac{2x\cos x}{\sin^2 x}

    Simplify each term:

    • For the first term: 2sin⁡xsin⁡2x=2sin⁡x=2csc⁡x\frac{2\sin x}{\sin^2 x} = \frac{2}{\sin x} = 2\csc x
    • For the second term: 2xcos⁡xsin⁡2x=2x⋅(cos⁡xsin⁡x)⋅(1sin⁡x)=2xcot⁡xcsc⁡x\frac{2x\cos x}{\sin^2 x} = 2x \cdot \left(\frac{\cos x}{\sin x}\right) \cdot \left(\frac{1}{\sin x}\right) = 2x \cot x \csc x

    So, the derivative is:

    dydx=2csc⁡x−2xcsc⁡xcot⁡x\frac{dy}{dx} = 2\csc x - 2x\csc x \cot x

    Factor out 2csc⁡x2\csc x:

    dydx=2csc⁡x(1−xcot⁡x)\frac{dy}{dx} = 2\csc x(1 - x\cot x)
    4. Identify the Answer

    Comparing our result to the given options, we find that it matches option D.

    5. Exam Tip

    When dealing with trigonometric functions in calculus, always remember your basic identities: 1sin⁡x=csc⁡x\frac{1}{\sin x} = \csc x and cos⁡xsin⁡x=cot⁡x\frac{\cos x}{\sin x} = \cot x. Recognizing these early makes simplifying your final answer much easier and helps you match it to the JAMB options quickly!

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  51. 51.

    Evaluate (60.32÷20.084)−1(\frac{6}{0.32} \div \frac{2}{0.084})^{-1} correct to 1 decimal place.

    1. A.1.3
    2. B.2.5
    3. C.4.6
    4. D.3.2
    Show answer

    Answer: A. 1.3

    AI explanation

    Step 1: Analyze the question

    We need to evaluate the expression (60.32÷20.084)−1(\frac{6}{0.32} \div \frac{2}{0.084})^{-1} and round the result to one decimal place.

    Step 2: Explain the concept

    To solve this, we follow the order of operations (BODMAS):

    1. Solve the divisions inside the parentheses first.
    2. Remember that dividing by a fraction is the same as multiplying by its reciprocal (flip the second fraction).
    3. Apply the exponent −1-1, which means finding the reciprocal of the final result (x−1=1xx^{-1} = \frac{1}{x}).
    Step 3: Show the solution

    Part A: Simplify the fractions inside the parentheses First, let's simplify the two divisions:

    • 60.32=60032=18.75\frac{6}{0.32} = \frac{600}{32} = 18.75
    • 20.084=200084≈23.8095\frac{2}{0.084} = \frac{2000}{84} \approx 23.8095

    Part B: Perform the division Now, we divide the first result by the second: 18.75÷23.809518.75 \div 23.8095

    Using the reciprocal method for accuracy: 60.32×0.0842\frac{6}{0.32} \times \frac{0.084}{2} =62×0.0840.32= \frac{6}{2} \times \frac{0.084}{0.32} =3×84320= 3 \times \frac{84}{320} =3×0.2625=0.7875= 3 \times 0.2625 = 0.7875

    Part C: Apply the exponent −1-1 The expression is (0.7875)−1(0.7875)^{-1}, which is 10.7875\frac{1}{0.7875}: 10.7875≈1.2698\frac{1}{0.7875} \approx 1.2698

    Part D: Round to 1 decimal place Rounding 1.26981.2698 to one decimal place gives 1.3.

    Step 4: Identify the answer

    Comparing our result to the given options, we see that 1.3 matches option A.

    Step 5: Exam Tip

    When dealing with decimals in JAMB, convert them to whole numbers by multiplying the numerator and denominator by powers of 10 (e.g., 10,100,100010, 100, 1000). This eliminates decimal errors and makes the division much easier to handle without a calculator.

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  52. 52.

    In the circle above, with centre O and radius 7 cm. Find the length of the arc AB, when < AOB = 57°.

    Diagram for question 52
    1. A.5.32 cm
    2. B.4.39 cm
    3. C.7.33 cm
    4. D.6.97 cm
    Show answer

    Answer: D. 6.97 cm

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  53. 53.

    Find the polynomial if given q(x) = x2^2 - x - 5, d(x) = 3x - 1 and r(x) = 7.

    1. A.3x3^3 - 4x2^2 - 14x + 12
    2. B.3x2^2 + 3x - 7
    3. C.3x3^3 + 4x2^2 + 14x - 12
    4. D.3x2^2 - 3x + 4
    Show answer

    Answer: A. 3x3^3 - 4x2^2 - 14x + 12

    AI explanation

    1. Analyze the question

    You are given the quotient q(x)q(x), the divisor d(x)d(x), and the remainder r(x)r(x) of a polynomial division. You need to find the original polynomial, which we can call P(x)P(x).

    2. Explain the concept

    In polynomial division, the relationship between the dividend P(x)P(x), the divisor d(x)d(x), the quotient q(x)q(x), and the remainder r(x)r(x) is defined by the Division Algorithm:

    P(x)=d(x)⋅q(x)+r(x)P(x) = d(x) \cdot q(x) + r(x)

    To find the polynomial, we simply need to multiply the divisor by the quotient and then add the remainder.

    3. Show the solution

    Given:

    • q(x)=x2−x−5q(x) = x^2 - x - 5
    • d(x)=3x−1d(x) = 3x - 1
    • r(x)=7r(x) = 7

    Step 1: Multiply d(x)d(x) and q(x)q(x) P(x)=(3x−1)(x2−x−5)+7P(x) = (3x - 1)(x^2 - x - 5) + 7

    Expand the brackets: =3x(x2−x−5)−1(x2−x−5)+7= 3x(x^2 - x - 5) - 1(x^2 - x - 5) + 7 =(3x3−3x2−15x)−(x2−x−5)+7= (3x^3 - 3x^2 - 15x) - (x^2 - x - 5) + 7

    Step 2: Simplify the expression =3x3−3x2−15x−x2+x+5+7= 3x^3 - 3x^2 - 15x - x^2 + x + 5 + 7

    Group the like terms: =3x3+(−3x2−x2)+(−15x+x)+(5+7)= 3x^3 + (-3x^2 - x^2) + (-15x + x) + (5 + 7) =3x3−4x2−14x+12= 3x^3 - 4x^2 - 14x + 12

    4. Identify the answer

    Comparing our result with the given options, the correct polynomial is 3x3−4x2−14x+123x^3 - 4x^2 - 14x + 12. This matches Option A.

    5. Tip

    When multiplying polynomials, always be careful with the negative signs. A common mistake in JAMB exams is forgetting to distribute the negative sign to every term inside the second bracket (e.g., −1×−5-1 \times -5 becomes +5+5). Always double-check your signs before adding the remainder!

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  54. 54.

    A man bought a car newly for ₦1,250,000. He had a crash with the car and later sold it at the rate of ₦1,085,000. What is the percentage gain or loss of the man?

    1. A.43.7% loss
    2. B.13.2% gain
    3. C.13.2% loss
    4. D.43.7% gain
    Show answer

    Answer: C. 13.2% loss

    AI explanation

    Analysis

    To solve this problem, we need to determine whether the man made a profit (gain) or incurred a loss.

    • Cost Price (CP): The amount the man originally paid for the car = ₦1,250,000.
    • Selling Price (SP): The amount the man sold the car for = ₦1,085,000.

    Since the Selling Price is less than the Cost Price, the man incurred a loss.

    Concept

    The formula for calculating the percentage loss is:

    Percentage Loss=(LossCost Price)×100%\text{Percentage Loss} = \left( \frac{\text{Loss}}{\text{Cost Price}} \right) \times 100\%

    Where:

    Loss=Cost Price−Selling Price\text{Loss} = \text{Cost Price} - \text{Selling Price}
    Step-by-Step Solution

    Step 1: Calculate the actual loss in Naira.

    Loss=1,250,000−1,085,000\text{Loss} = 1,250,000 - 1,085,000
    Loss=165,000\text{Loss} = 165,000

    Step 2: Calculate the percentage loss.

    Percentage Loss=(165,0001,250,000)×100%\text{Percentage Loss} = \left( \frac{165,000}{1,250,000} \right) \times 100\%

    Step 3: Simplify the calculation. Cancel out the zeros:

    Percentage Loss=(1651,250)×100%\text{Percentage Loss} = \left( \frac{165}{1,250} \right) \times 100\%
    Percentage Loss=16512.5\text{Percentage Loss} = \frac{165}{12.5}
    Percentage Loss=13.2%\text{Percentage Loss} = 13.2\%

    Since the selling price was lower than the cost price, this is a 13.2% loss.

    Conclusion

    Comparing our result to the given options, we find that the correct choice is C.

    Exam Tip

    Always check if the Selling Price is higher or lower than the Cost Price before calculating. If SP<CPSP < CP, it is a loss; if SP>CPSP > CP, it is a gain. This simple check helps you eliminate two of the four options immediately!

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  55. 55.

    Simplify 0.0839×6.3815.44\frac{0.0839 \times 6.381}{5.44} to 2 significant figures.

    1. A.0.2809
    2. B.2.51
    3. C.3.5
    4. D.0.098
    Show answer

    Answer: D. 0.098

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  56. 56.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  57. 57.

    If ∣2−53x14032∣=132\begin{vmatrix} 2 & -5 & 3 \\ x & 1 & 4 \\ 0 & 3 & 2 \end{vmatrix} = 132, find the value of x.

    1. A.5
    2. B.8
    3. C.6
    4. D.3
    Show answer

    Answer: B. 8

    AI explanation

    Analysis

    To find the value of xx, we need to calculate the determinant of the given 3×33 \times 3 matrix and equate it to 132132.

    Concept: Determinant of a 3×33 \times 3 Matrix

    For a matrix A=∣abcdefghi∣A = \begin{vmatrix} a & b & c \\ d & e & f \\ g & h & i \end{vmatrix}, the determinant is calculated by expanding along the first row:

    Det(A)=a(ei−fh)−b(di−fg)+c(dh−eg)\text{Det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg)
    Step-by-Step Solution

    Given the matrix:

    ∣2−53x14032∣=132\begin{vmatrix} 2 & -5 & 3 \\ x & 1 & 4 \\ 0 & 3 & 2 \end{vmatrix} = 132

    1. Expand along the first row: =2∣1432∣−(−5)∣x402∣+3∣x103∣=132= 2 \begin{vmatrix} 1 & 4 \\ 3 & 2 \end{vmatrix} - (-5) \begin{vmatrix} x & 4 \\ 0 & 2 \end{vmatrix} + 3 \begin{vmatrix} x & 1 \\ 0 & 3 \end{vmatrix} = 132

    2. Calculate the 2×22 \times 2 determinants:

    • First part: 2[(1×2)−(4×3)]=2[2−12]=2[−10]=−202[(1 \times 2) - (4 \times 3)] = 2[2 - 12] = 2[-10] = -20
    • Second part: +5[(x×2)−(4×0)]=5[2x−0]=10x+5[(x \times 2) - (4 \times 0)] = 5[2x - 0] = 10x
    • Third part: +3[(x×3)−(1×0)]=3[3x−0]=9x+3[(x \times 3) - (1 \times 0)] = 3[3x - 0] = 9x

    3. Combine the results: −20+10x+9x=132-20 + 10x + 9x = 132

    4. Solve for xx: 19x−20=13219x - 20 = 132 19x=132+2019x = 132 + 20 19x=15219x = 152 x=15219x = \frac{152}{19} x=8x = 8

    Conclusion

    The value of xx is 8. Comparing this to the provided options, it matches option B.

    Exam Tip

    When calculating determinants, always be very careful with the signs of the middle term. Remember the sign pattern for a 3×33 \times 3 matrix is:

    (+−+−+−+−+)\begin{pmatrix} + & - & + \\ - & + & - \\ + & - & + \end{pmatrix}

    Since the middle element in the first row was −5-5, the formula −b-b makes it −(−5)=+5-(-5) = +5. Missing this sign change is the most common mistake students make in JAMB Mathematics!

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  58. 58.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  59. 59.

    The weight of a day-old chick was measured to be 0.21g. If the actual weight of the chick is 0.18g, what was the percentage error in the measurement?

    1. A.15.5%
    2. B.18.2%
    3. C.14.8%
    4. D.16.7%
    Show answer

    Answer: D. 16.7%

    AI explanation

    Analysis

    To solve this problem, we need to calculate the percentage error. Percentage error is a measure of how far off a measurement is from the true or actual value, expressed as a percentage.

    Concept

    The formula for percentage error is:

    Percentage Error=(Measured Value−Actual ValueActual Value)×100%\text{Percentage Error} = \left( \frac{\text{Measured Value} - \text{Actual Value}}{\text{Actual Value}} \right) \times 100\%
    • Measured Value: The value obtained during the measurement (0.21g).
    • Actual Value: The true or correct weight (0.18g).
    • Error: The difference between the measured and actual values.
    Step-by-Step Solution
    1. Find the absolute error: $Error=Measured Value−Actual Value\text{Error} = \text{Measured Value} - \text{Actual Value}$ $Error=0.21g−0.18g=0.03g\text{Error} = 0.21\text{g} - 0.18\text{g} = 0.03\text{g}$
    1. Calculate the percentage error: $Percentage Error=(0.030.18)×100%\text{Percentage Error} = \left( \frac{0.03}{0.18} \right) \times 100\%$
    1. Simplify the fraction: $0.030.18=318=16\frac{0.03}{0.18} = \frac{3}{18} = \frac{1}{6}$
    1. Convert to percentage: $16×100%=16.666...%\frac{1}{6} \times 100\% = 16.666...\%$

    Rounding this to one decimal place gives 16.7%.

    Conclusion

    Comparing our result to the given options, 16.7% matches option D.

    Exam Tip

    When calculating percentage error, always remember that the denominator is the Actual Value (the "true" value), not the measured value. A common mistake students make is dividing by the measured value (0.21), which would lead to the wrong answer. Always keep the "True" value at the bottom!

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  60. 60.

    If 4sin⁡2x−3=04\sin^2 x - 3 = 0, find the value of x, when 0° ≤\leq x ≤\leq 90°

    1. A.90°
    2. B.45°
    3. C.60°
    4. D.30°
    Show answer

    Answer: C. 60°

    AI explanation

    1. Analyze the question

    We are given a trigonometric equation 4sin⁡2x−3=04\sin^2 x - 3 = 0 and asked to find the value of xx within the range 0∘≤x≤90∘0^\circ \leq x \leq 90^\circ.

    2. Explain the concept

    To solve this, we need to isolate the trigonometric function (sin⁡x\sin x) and then use the inverse sine function (or our knowledge of special angles) to find the value of xx. Remember that sin⁡2x\sin^2 x is the same as (sin⁡x)2(\sin x)^2.

    3. Show the solution

    Step 1: Isolate sin⁡2x\sin^2 x Start with the equation: 4sin⁡2x−3=04\sin^2 x - 3 = 0

    Add 3 to both sides: 4sin⁡2x=34\sin^2 x = 3

    Divide both sides by 4: sin⁡2x=34\sin^2 x = \frac{3}{4}

    Step 2: Solve for sin⁡x\sin x Take the square root of both sides: sin⁡2x=34\sqrt{\sin^2 x} = \sqrt{\frac{3}{4}} sin⁡x=34\sin x = \frac{\sqrt{3}}{\sqrt{4}} sin⁡x=32\sin x = \frac{\sqrt{3}}{2}

    Step 3: Find the value of xx We need to find the angle xx whose sine is 32\frac{\sqrt{3}}{2}. From the standard trigonometric ratios for special angles: sin⁡60∘=32\sin 60^\circ = \frac{\sqrt{3}}{2}

    Since 60∘60^\circ falls within the given range (0∘≤x≤90∘0^\circ \leq x \leq 90^\circ), this is our solution.

    4. Identify the answer

    Comparing our result to the options provided: A. 90° B. 45° C. 60° D. 30°

    The correct option is C.

    5. Tip

    Always memorize the "Special Angles" table for 0∘,30∘,45∘,60∘,0^\circ, 30^\circ, 45^\circ, 60^\circ, and 90∘90^\circ. A quick way to remember the sine values is:

    • sin⁡0∘=0/2=0\sin 0^\circ = \sqrt{0}/2 = 0
    • sin⁡30∘=1/2=1/2\sin 30^\circ = \sqrt{1}/2 = 1/2
    • sin⁡45∘=2/2\sin 45^\circ = \sqrt{2}/2
    • sin⁡60∘=3/2\sin 60^\circ = \sqrt{3}/2
    • sin⁡90∘=4/2=1\sin 90^\circ = \sqrt{4}/2 = 1

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  61. 61.

    Each of the interior angles of a regular polygon is 140°. Calculate the sum of all the interior angles of the polygon.

    1. A.1080°
    2. B.1260°
    3. C.2160°
    4. D.1800°
    Show answer

    Answer: B. 1260°

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  62. 62.

    Score (x) 0 1 2 3 4 5 6 Freq (f) 5 7 3 7 11 6 7 Find the mean of the data.

    1. A.3.26
    2. B.4.91
    3. C.6.57
    4. D.3.0
    Show answer

    Answer: A. 3.26

    AI explanation

    To find the mean of a frequency distribution, we use the formula:

    Mean (xˉ)=∑fx∑f\text{Mean } (\bar{x}) = \frac{\sum fx}{\sum f}

    Where:

    • xx is the score
    • ff is the frequency
    • ∑fx\sum fx is the sum of the products of each score and its frequency
    • ∑f\sum f is the total number of frequencies
    Step 1: Create a frequency table and calculate fxfx

    | Score (xx) | Frequency (ff) | f×xf \times x | | :--- | :--- | :--- | | 0 | 5 | 0×5=00 \times 5 = 0 | | 1 | 7 | 1×7=71 \times 7 = 7 | | 2 | 3 | 2×3=62 \times 3 = 6 | | 3 | 7 | 3×7=213 \times 7 = 21 | | 4 | 11 | 4×11=444 \times 11 = 44 | | 5 | 6 | 5×6=305 \times 6 = 30 | | 6 | 7 | 6×7=426 \times 7 = 42 |

    Step 2: Calculate the totals
    • Total Frequency (∑f\sum f): 5+7+3+7+11+6+7=465 + 7 + 3 + 7 + 11 + 6 + 7 = 46
    • Total Sum of products (∑fx\sum fx): 0+7+6+21+44+30+42=1500 + 7 + 6 + 21 + 44 + 30 + 42 = 150
    Step 3: Calculate the Mean
    xˉ=15046\bar{x} = \frac{150}{46}
    xˉ≈3.2608...\bar{x} \approx 3.2608...

    Rounding to two decimal places, we get 3.26.

    Conclusion

    Comparing our result to the options provided, the correct value matches option A.

    Exam Tip: When dealing with frequency tables in JAMB, always double-check your addition of the frequencies (∑f\sum f) first. A small error in the total frequency will throw off your entire calculation. If you have time, perform the multiplication f×xf \times x twice to ensure no arithmetic slips occurred.

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  63. 63.

    A binary operation Δ is defined by a Δ b = a + 3b + 2. Find (3 Δ 2) Δ 5

    1. A.35
    2. B.59
    3. C.28
    4. D.87
    Show answer

    Answer: C. 28

    AI explanation

    1. Analyze the question

    We are given a binary operation defined as aΔb=a+3b+2a \Delta b = a + 3b + 2. We need to evaluate the expression (3Δ2)Δ5(3 \Delta 2) \Delta 5. This is a two-step problem where we first solve the operation inside the bracket, then use that result to solve the final operation.

    2. Explain the concept

    A binary operation is simply a rule that tells you how to combine two numbers. In this case, the rule is: "Take the first number, add three times the second number, and then add 2." We must follow the order of operations (BODMAS) to ensure accuracy.

    3. Show the solution

    Step 1: Solve the expression inside the bracket (3Δ2)(3 \Delta 2) Using the formula aΔb=a+3b+2a \Delta b = a + 3b + 2:

    • Here, a=3a = 3 and b=2b = 2.
    • 3Δ2=3+3(2)+23 \Delta 2 = 3 + 3(2) + 2
    • 3Δ2=3+6+23 \Delta 2 = 3 + 6 + 2
    • 3Δ2=113 \Delta 2 = 11

    Step 2: Solve the final expression (11Δ5)(11 \Delta 5) Now, we substitute the result from Step 1 into the original equation:

    • Here, a=11a = 11 and b=5b = 5.
    • 11Δ5=11+3(5)+211 \Delta 5 = 11 + 3(5) + 2
    • 11Δ5=11+15+211 \Delta 5 = 11 + 15 + 2
    • 11Δ5=2811 \Delta 5 = 28
    4. Identify the answer

    Comparing our result to the given options: A. 35 B. 59 C. 28 D. 87

    The correct option is C.

    5. Tip

    When dealing with binary operations in JAMB, always solve the bracketed part first. If you have multiple operations, treat the result of the first operation as a single number and plug it back into the definition. Don't rush the arithmetic—a simple sign error here is the most common reason students lose marks!

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  64. 64.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  65. 65.

    Make q the subject of the formula in the equation mna2−pqb2=1\frac{mn}{a^2} - \frac{pq}{b^2} = 1

    1. A.q=b2(mn−a2)a2pq = \frac{b^2(mn - a^2)}{a^2 p}
    2. B.q=m2n−a2p2q = \frac{m^2 n - a^2}{p^2}
    3. C.q=mn−2b2a2q = \frac{mn - 2b^2}{a^2}
    4. D.q=b2(n2−ma2)nq = \frac{b^2 (n^2 - ma^2)}{n}
    Show answer

    Answer: A. q=b2(mn−a2)a2pq = \frac{b^2(mn - a^2)}{a^2 p}

    AI explanation

    Analysis

    We are given the equation:

    mna2−pqb2=1\frac{mn}{a^2} - \frac{pq}{b^2} = 1

    Our goal is to isolate qq on one side of the equation.

    Concept

    To make a variable the subject of a formula, we use algebraic manipulation (addition, subtraction, multiplication, and division) to move all other terms to the opposite side of the equation until the desired variable stands alone.

    Step-by-Step Solution

    Step 1: Isolate the term containing qq. Subtract mna2\frac{mn}{a^2} from both sides:

    −pqb2=1−mna2-\frac{pq}{b^2} = 1 - \frac{mn}{a^2}

    Step 2: Simplify the right side. Find a common denominator (a2a^2) for the right side:

    −pqb2=a2−mna2-\frac{pq}{b^2} = \frac{a^2 - mn}{a^2}

    Step 3: Eliminate the negative sign. Multiply both sides by −1-1 to make the qq term positive:

    pqb2=−(a2−mna2)\frac{pq}{b^2} = -\left(\frac{a^2 - mn}{a^2}\right)

    Distributing the negative sign inside the parenthesis:

    pqb2=mn−a2a2\frac{pq}{b^2} = \frac{mn - a^2}{a^2}

    Step 4: Solve for qq. Multiply both sides by b2b^2:

    pq=b2(mn−a2)a2pq = \frac{b^2(mn - a^2)}{a^2}

    Finally, divide both sides by pp:

    q=b2(mn−a2)a2pq = \frac{b^2(mn - a^2)}{a^2 p}
    Conclusion

    Comparing our result to the given options, we find that it matches Option A.

    Exam Tip

    When dealing with fractions in algebraic equations, always try to clear the fractions by multiplying through by the Least Common Multiple (LCM) or by grouping terms with the same denominator. This makes the equation much easier to handle and reduces the chance of sign errors!

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  66. 66.

    If P varies inversely as the square root of q, where p = 3 and q = 16, find the value of q when p = 4.

    1. A.12
    2. B.8
    3. C.9
    4. D.16
    Show answer

    Answer: C. 9

    AI explanation

    1. Analyze the Question

    We are given a relationship of inverse variation between two variables, pp and qq. Specifically, pp varies inversely as the square root of qq. We are given an initial set of values to find the constant of variation, and then asked to find a new value for qq when pp changes.

    2. Explain the Concept

    In mathematics, when pp varies inversely as the square root of qq, the relationship is expressed as:

    p∝1qp \propto \frac{1}{\sqrt{q}}

    To turn this into an equation, we introduce a constant of variation, kk:

    p=kqp = \frac{k}{\sqrt{q}}

    Our goal is to first find kk using the given values, then use that kk to solve for the unknown qq.

    3. Show the Solution

    Step 1: Find the constant kk Given p=3p = 3 and q=16q = 16:

    3=k163 = \frac{k}{\sqrt{16}}

    Since 16=4\sqrt{16} = 4:

    3=k43 = \frac{k}{4}

    Multiply both sides by 4:

    k=3×4=12k = 3 \times 4 = 12

    Step 2: Find qq when p=4p = 4 Now that we know k=12k = 12, our formula is p=12qp = \frac{12}{\sqrt{q}}. Substitute p=4p = 4:

    4=12q4 = \frac{12}{\sqrt{q}}

    Multiply both sides by q\sqrt{q} and divide by 4:

    q=124\sqrt{q} = \frac{12}{4}
    q=3\sqrt{q} = 3

    To solve for qq, square both sides:

    q=32q = 3^2
    q=9q = 9
    4. Identify the Answer

    Comparing our result to the given options: A. 12 B. 8 C. 9 D. 16

    The correct option is C.

    5. Exam Tip

    When dealing with inverse variation, always remember: "If one goes up, the other goes down." Since pp increased from 3 to 4, we should expect qq to decrease from its original value of 16. Since 9 is the only option smaller than 16, you could have narrowed your choices down quickly!

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  67. 67.

    If y = 8x3^3 - 3x2^2 + 7x - 1, find d2ydx2\frac{\mathrm d^2 y}{\mathrm d x^2}.

    1. A.48x - 6
    2. B.11x2^2 + 6x - 7
    3. C.32x + 7
    4. D.24x2^2 - 6x + 7
    Show answer

    Answer: A. 48x - 6

    AI explanation

    Analysis

    The question asks for the second derivative (d2ydx2\frac{\mathrm d^2 y}{\mathrm d x^2}) of the given polynomial function y=8x3−3x2+7x−1y = 8x^3 - 3x^2 + 7x - 1. To find the second derivative, we must differentiate the function with respect to xx twice.

    Concept: The Power Rule

    To differentiate a term of the form axnax^n, we use the Power Rule:

    ddx(axn)=n⋅axn−1\frac{\mathrm d}{\mathrm d x}(ax^n) = n \cdot ax^{n-1}

    The derivative of a constant (a number without xx) is always 00.

    Step-by-Step Solution

    Step 1: Find the first derivative (dydx\frac{\mathrm d y}{\mathrm d x}) We differentiate each term of y=8x3−3x2+7x−1y = 8x^3 - 3x^2 + 7x - 1 individually:

    • For 8x38x^3: 3×8x3−1=24x23 \times 8x^{3-1} = 24x^2
    • For −3x2-3x^2: 2×−3x2−1=−6x2 \times -3x^{2-1} = -6x
    • For 7x7x: 1×7x1−1=7x0=71 \times 7x^{1-1} = 7x^0 = 7
    • For −1-1: The derivative is 00

    So, the first derivative is:

    dydx=24x2−6x+7\frac{\mathrm d y}{\mathrm d x} = 24x^2 - 6x + 7

    Step 2: Find the second derivative (d2ydx2\frac{\mathrm d^2 y}{\mathrm d x^2}) Now, we differentiate the result from Step 1:

    • For 24x224x^2: 2×24x2−1=48x2 \times 24x^{2-1} = 48x
    • For −6x-6x: 1×−6x1−1=−61 \times -6x^{1-1} = -6
    • For 77: The derivative is 00

    Combining these, we get:

    d2ydx2=48x−6\frac{\mathrm d^2 y}{\mathrm d x^2} = 48x - 6
    Conclusion

    Comparing our result to the given options, we find that it matches option A.

    Exam Tip: When dealing with polynomials, remember that every time you differentiate, the power of xx decreases by 1. If you are asked for the nthn^{th} derivative, you simply repeat the process nn times. Always double-check your signs (positive/negative) during the multiplication step!

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  68. 68.

    If y=6x3+2x−2−x−3y = 6x^3 + 2x^{-2} - x^{-3}, find dydx\frac{\mathrm d y}{\mathrm d x}.

    1. A.dydx=15x2−4x−2−3x−2\frac{\mathrm d y}{\mathrm d x} = 15x^2 - 4x^{-2} - 3x^{-2}
    2. B.dydx=6x+4x−1−3x−4\frac{\mathrm d y}{\mathrm d x} = 6x + 4x^{-1} - 3x^{-4}
    3. C.dydx=18x2−4x−3+3x−4\frac{\mathrm d y}{\mathrm d x} = 18x^2 - 4x^{-3} + 3x^{-4}
    4. D.dydx=12x2+4x−1−3x−2\frac{\mathrm d y}{\mathrm d x} = 12x^2 + 4x^{-1} - 3x^{-2}
    Show answer

    Answer: C. dydx=18x2−4x−3+3x−4\frac{\mathrm d y}{\mathrm d x} = 18x^2 - 4x^{-3} + 3x^{-4}

    AI explanation

    Analysis

    To find dydx\frac{\mathrm{d}y}{\mathrm{d}x}, we need to apply the Power Rule of Differentiation. The power rule states that if y=axny = ax^n, then dydx=n⋅axn−1\frac{\mathrm{d}y}{\mathrm{d}x} = n \cdot ax^{n-1}.

    Concept

    The Power Rule is the fundamental tool for differentiating polynomials and terms with negative or fractional exponents. You simply:

    1. Bring the current exponent down to multiply with the coefficient.
    2. Subtract 1 from the current exponent.
    Step-by-Step Solution

    Given the function: y=6x3+2x−2−x−3y = 6x^3 + 2x^{-2} - x^{-3}

    We differentiate each term individually:

    1. For 6x36x^3: • Bring down the 3: 3×6=183 \times 6 = 18 • Subtract 1 from the exponent: 3−1=23 - 1 = 2 • Result: 18x218x^2
    1. For 2x−22x^{-2}: • Bring down the -2: −2×2=−4-2 \times 2 = -4 • Subtract 1 from the exponent: −2−1=−3-2 - 1 = -3 • Result: −4x−3-4x^{-3}
    1. For −x−3-x^{-3}: • Bring down the -3: −3×−1=+3-3 \times -1 = +3 • Subtract 1 from the exponent: −3−1=−4-3 - 1 = -4 • Result: +3x−4+3x^{-4}

    Combining these results, we get: dydx=18x2−4x−3+3x−4\frac{\mathrm{d}y}{\mathrm{d}x} = 18x^2 - 4x^{-3} + 3x^{-4}

    Conclusion

    Comparing our result to the given options, it matches option C perfectly.

    Exam Tip

    When dealing with negative exponents, be very careful with your signs during subtraction. Many students mistakenly calculate −2−1-2 - 1 as −1-1 instead of −3-3. Always remember: "Subtracting 1 from a negative number makes it more negative."

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  69. 69.

    A factory worker earns ₦50,000 per month out of which he spends 15% on his children's education, ₦13,600 on Food, 3% on electricity and uses the rest for his personal purpose. How much does he have left?

    1. A.N21,850
    2. B.N18,780
    3. C.N27,400
    4. D.N32,500
    Show answer

    Answer: C. N27,400

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  70. 70.

    Find the value of x for 2+2x3−2≥4x−65\frac{2 + 2x}{3} - 2 \geq \frac{4x - 6}{5}

    1. A.x ≥\geq -5
    2. B.x ≥\geq -1
    3. C.x ≤\leq -1
    4. D.x ≤\leq 3
    Show answer

    Answer: C. x ≤\leq -1

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  71. 71.

    If P(2, m) is the midpoint of the line joining Q(m, n) and R(n, -4), find the values of m and n.

    1. A.m = 0, n = 4
    2. B.m = 4, n = 0
    3. C.m = 2, n = 2
    4. D.m = -2, n = 4
    Show answer

    Answer: A. m = 0, n = 4

    AI explanation

    Analysis

    To solve this problem, we use the Midpoint Formula. If a point P(x,y)P(x, y) is the midpoint of a line segment joining two points Q(x1,y1)Q(x_1, y_1) and R(x2,y2)R(x_2, y_2), the coordinates of the midpoint are given by:

    x=x1+x22andy=y1+y22x = \frac{x_1 + x_2}{2} \quad \text{and} \quad y = \frac{y_1 + y_2}{2}
    Concept

    In this question, we are given:

    • Midpoint P=(2,m)P = (2, m)
    • Point Q=(m,n)Q = (m, n)
    • Point R=(n,−4)R = (n, -4)

    By substituting these values into the midpoint formula, we create a system of two equations that we can solve simultaneously.

    Step-by-Step Solution

    Step 1: Set up the equations for the x and y coordinates. For the x-coordinate:

    2=m+n22 = \frac{m + n}{2}

    Multiply both sides by 2:

    4=m+n…(Equation 1)4 = m + n \quad \dots \text{(Equation 1)}

    For the y-coordinate:

    m=n+(−4)2m = \frac{n + (-4)}{2}

    Multiply both sides by 2:

    2m=n−4…(Equation 2)2m = n - 4 \quad \dots \text{(Equation 2)}

    Step 2: Solve the system of equations. From Equation 1, we can express nn in terms of mm:

    n=4−mn = 4 - m

    Substitute this into Equation 2:

    2m=(4−m)−42m = (4 - m) - 4
    2m=−m2m = -m
    2m+m=02m + m = 0
    3m=03m = 0
    m=0m = 0

    Step 3: Find the value of n. Substitute m=0m = 0 back into Equation 1:

    4=0+n4 = 0 + n
    n=4n = 4

    Thus, m=0m = 0 and n=4n = 4.

    Conclusion

    Comparing our result (m=0,n=4m = 0, n = 4) with the given options, it matches option A.

    Exam Tip

    When dealing with midpoint questions, always write out your x1,y1,x2,y2x_1, y_1, x_2, y_2 clearly before plugging them into the formula. This prevents "sign errors" (like forgetting the negative sign in −4-4), which is the most common reason students lose marks in coordinate geometry.

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  72. 72.

    Tade bought 200 mangoes at 4 for ₦2.50. 30 out of the mangoes got spoilt and the remaining were sold at 2 for ₦2.40. Find the percentage profit or loss.

    1. A.43.6% loss
    2. B.35% profit
    3. C.63.2% profit
    4. D.28% loss
    Show answer

    Answer: C. 63.2% profit

    AI explanation

    1. Analyze the question

    We need to determine the total cost price (CP) of the mangoes, the total selling price (SP) after accounting for the spoilt ones, and then calculate the percentage profit or loss using the formula:

    Percentage Profit/Loss=Profit or LossCost Price×100%\text{Percentage Profit/Loss} = \frac{\text{Profit or Loss}}{\text{Cost Price}} \times 100\%
    2. Explain the concept
    • Cost Price (CP): The total amount spent to acquire the goods.
    • Selling Price (SP): The total amount received from selling the goods.
    • Profit: Occurs when SP > CP (Profit = SP - CP).
    • Loss: Occurs when CP > SP (Loss = CP - SP).
    3. Show the solution

    Step 1: Calculate the Total Cost Price (CP) Tade bought 200 mangoes at 4 for ₦2.50.

    • Number of groups of 4 in 200 = 200÷4=50200 \div 4 = 50 groups.
    • Total CP = 50×₦2.50=₦125.0050 \times ₦2.50 = ₦125.00.

    Step 2: Calculate the Total Selling Price (SP)

    • Number of good mangoes = 200−30=170200 - 30 = 170 mangoes.
    • They were sold at 2 for ₦2.40.
    • Number of groups of 2 in 170 = 170÷2=85170 \div 2 = 85 groups.
    • Total SP = 85×₦2.40=₦204.0085 \times ₦2.40 = ₦204.00.

    Step 3: Determine Profit or Loss Since the SP (₦204.00) is greater than the CP (₦125.00), Tade made a profit.

    • Profit = ₦204.00−₦125.00=₦79.00₦204.00 - ₦125.00 = ₦79.00.

    Step 4: Calculate Percentage Profit

    • Percentage Profit = ProfitCP×100%\frac{\text{Profit}}{\text{CP}} \times 100\%
    • Percentage Profit = 79125×100%\frac{79}{125} \times 100\%
    • Percentage Profit = 0.632×100%=63.2%0.632 \times 100\% = 63.2\%.
    4. Identify the answer

    Comparing our result to the options provided, we see that 63.2% profit matches option C.

    5. Tip

    When dealing with "items per price" questions, always find the cost/selling price of a single unit first if the numbers are complex, or group them as we did above. Also, always double-check if the question asks for the percentage of the Cost Price (which is standard) or the Selling Price, as this is a common trap in JAMB questions!

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  73. 73.

    If the 3rd and 7th terms of a G.P are 9 and 1/9 respectively. Find the common ratio.

    1. A.13\frac{1}{3}
    2. B.19\frac{1}{9}
    3. C.23\frac{2}{3}
    4. D.29\frac{2}{9}
    Show answer

    Answer: A. 13\frac{1}{3}

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  74. 74.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  75. 75.

    If sin⁡x=45\sin x = \frac{4}{5}, find 1+cot⁡2xcsc⁡2x−1\frac{1 + \cot^2 x}{\csc^2 x - 1}.

    1. A.132\frac{13}{2}
    2. B.259\frac{25}{9}
    3. C.313\frac{3}{13}
    4. D.411\frac{4}{11}
    Show answer

    Answer: B. 259\frac{25}{9}

    AI explanation

    1. Analyze the question

    We are given sin⁡x=45\sin x = \frac{4}{5} and asked to evaluate the expression 1+cot⁡2xcsc⁡2x−1\frac{1 + \cot^2 x}{\csc^2 x - 1}.

    2. Explain the concept

    To solve this, we use fundamental trigonometric identities:

    • Pythagorean Identity: 1+cot⁡2x=csc⁡2x1 + \cot^2 x = \csc^2 x
    • Rearranged Identity: csc⁡2x−1=cot⁡2x\csc^2 x - 1 = \cot^2 x

    By substituting these identities into the expression, we can simplify the problem significantly before plugging in the value of sin⁡x\sin x.

    3. Show the solution

    Step 1: Simplify the expression using identities. The expression is:

    1+cot⁡2xcsc⁡2x−1\frac{1 + \cot^2 x}{\csc^2 x - 1}

    Using the identity 1+cot⁡2x=csc⁡2x1 + \cot^2 x = \csc^2 x, the numerator becomes csc⁡2x\csc^2 x. Using the identity csc⁡2x−1=cot⁡2x\csc^2 x - 1 = \cot^2 x, the denominator becomes cot⁡2x\cot^2 x.

    So, the expression simplifies to:

    csc⁡2xcot⁡2x\frac{\csc^2 x}{\cot^2 x}

    Step 2: Express in terms of sin⁡x\sin x and cos⁡x\cos x. Recall that csc⁡x=1sin⁡x\csc x = \frac{1}{\sin x} and cot⁡x=cos⁡xsin⁡x\cot x = \frac{\cos x}{\sin x}.

    csc⁡2xcot⁡2x=1sin⁡2xcos⁡2xsin⁡2x=1sin⁡2x×sin⁡2xcos⁡2x=1cos⁡2x=sec⁡2x\frac{\csc^2 x}{\cot^2 x} = \frac{\frac{1}{\sin^2 x}}{\frac{\cos^2 x}{\sin^2 x}} = \frac{1}{\sin^2 x} \times \frac{\sin^2 x}{\cos^2 x} = \frac{1}{\cos^2 x} = \sec^2 x

    Step 3: Find cos⁡x\cos x and solve. Given sin⁡x=45\sin x = \frac{4}{5}, we use the identity sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1:

    (45)2+cos⁡2x=1\left(\frac{4}{5}\right)^2 + \cos^2 x = 1
    1625+cos⁡2x=1\frac{16}{25} + \cos^2 x = 1
    cos⁡2x=1−1625=925\cos^2 x = 1 - \frac{16}{25} = \frac{9}{25}

    Now, substitute cos⁡2x\cos^2 x into our simplified expression (1cos⁡2x\frac{1}{\cos^2 x}):

    1925=259\frac{1}{\frac{9}{25}} = \frac{25}{9}
    4. Identify the answer

    Comparing our result 259\frac{25}{9} with the given options, it matches option B.

    5. Tip

    Whenever you see trigonometric expressions involving squares like csc⁡2x\csc^2 x or cot⁡2x\cot^2 x, always check if you can simplify them using the Pythagorean identities (1+tan⁡2x=sec⁡2x1 + \tan^2 x = \sec^2 x or 1+cot⁡2x=csc⁡2x1 + \cot^2 x = \csc^2 x) before substituting the numerical values. It saves time and reduces the chance of calculation errors!

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  76. 76.

    ddx[log⁡(4x3−2x)]\frac{d}{dx} [\log (4x^3 - 2x)] is equal to

    1. A.12x−24x2\frac{12x - 2}{4x^2}
    2. B.43x2−2x7x\frac{43x^2 - 2x}{7x}
    3. C.4x2−27x+6\frac{4x^2 - 2}{7x + 6}
    4. D.12x2−24x3−2x\frac{12x^2 - 2}{4x^3 - 2x}
    Show answer

    Answer: D. 12x2−24x3−2x\frac{12x^2 - 2}{4x^3 - 2x}

    AI explanation

    Analysis

    The question asks for the derivative of a logarithmic function with respect to xx. Specifically, we need to apply the rules of differentiation for logarithms.

    Concept: Differentiation of Logarithmic Functions

    To differentiate a function of the form y=ln⁡(u)y = \ln(u), where uu is a function of xx, we use the Chain Rule. The formula is:

    ddx[ln⁡(u)]=1u⋅dudx\frac{d}{dx} [\ln(u)] = \frac{1}{u} \cdot \frac{du}{dx}

    In this problem, the function is log⁡(4x3−2x)\log(4x^3 - 2x). In standard calculus contexts for JAMB, log⁡\log without a base specified is typically treated as the natural logarithm (ln⁡\ln).

    Step-by-Step Solution

    Step 1: Identify uu Let u=4x3−2xu = 4x^3 - 2x.

    Step 2: Differentiate uu with respect to xx Using the power rule (ddxaxn=anxn−1\frac{d}{dx} ax^n = anx^{n-1}):

    dudx=ddx(4x3)−ddx(2x)\frac{du}{dx} = \frac{d}{dx}(4x^3) - \frac{d}{dx}(2x)
    dudx=(4×3)x3−1−2\frac{du}{dx} = (4 \times 3)x^{3-1} - 2
    dudx=12x2−2\frac{du}{dx} = 12x^2 - 2

    Step 3: Apply the Chain Rule formula Substitute uu and dudx\frac{du}{dx} into the formula 1u⋅dudx\frac{1}{u} \cdot \frac{du}{dx}:

    ddx[ln⁡(4x3−2x)]=14x3−2x⋅(12x2−2)\frac{d}{dx} [\ln(4x^3 - 2x)] = \frac{1}{4x^3 - 2x} \cdot (12x^2 - 2)

    Step 4: Simplify the expression

    12x2−24x3−2x\frac{12x^2 - 2}{4x^3 - 2x}

    Comparing this result to the given options, it matches Option D perfectly.

    Exam Tip

    Whenever you see a derivative of a logarithm, remember the "Rule of Reciprocals": The derivative is simply the derivative of the inside part divided by the inside part itself. Don't let the "log" symbol intimidate you; just focus on differentiating the expression inside the bracket and placing it over the original expression.

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  77. 77.

    In a class of 50 students, 40 students offered Physics and 30 offered Biology. How many offered both Physics and Biology?

    1. A.42
    2. B.20
    3. C.70
    4. D.54
    Show answer

    Answer: B. 20

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  78. 78.

    If 251−x×5x+2÷ (1125)x=625−125^{1 - x} \times 5^{x + 2} \div (\frac{1}{125})^{x} = 625^{-1}, find the value of x.

    1. A.x = -4
    2. B.x = 2
    3. C.x = -2
    4. D.x = 4
    Show answer

    Answer: A. x = -4

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  79. 79.

    Find the probability that a number selected at random from 21 to 34 is a multiple of 3

    1. A.311\frac{3}{11}
    2. B.29\frac{2}{9}
    3. C.514\frac{5}{14}
    4. D.513\frac{5}{13}
    Show answer

    Answer: C. 514\frac{5}{14}

    AI explanation

    1. Analyze the question

    We need to find the probability of picking a multiple of 3 from the set of integers ranging from 21 to 34 (inclusive).

    2. Explain the concept

    Probability is defined as:

    Probability=Number of favorable outcomesTotal number of possible outcomes\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}
    • Total outcomes: The count of all integers from 21 to 34.
    • Favorable outcomes: The count of numbers within that range that are divisible by 3.
    3. Show the solution

    Step 1: Find the total number of outcomes. To find the number of integers in an inclusive range [a,b][a, b], we use the formula: (b−a)+1(b - a) + 1.

    Total=(34−21)+1\text{Total} = (34 - 21) + 1
    Total=13+1=14\text{Total} = 13 + 1 = 14

    There are 14 possible numbers in total.

    Step 2: Identify the multiples of 3 in the range. Let's list the numbers from 21 to 34 and identify the multiples of 3:

    • 21 (3 × 7) - Yes
    • 22
    • 23
    • 24 (3 × 8) - Yes
    • 25
    • 26
    • 27 (3 × 9) - Yes
    • 28
    • 29
    • 30 (3 × 10) - Yes
    • 31
    • 32
    • 33 (3 × 11) - Yes
    • 34

    The multiples are {21, 24, 27, 30, 33}. Counting these, we have 5 favorable outcomes.

    Step 3: Calculate the probability.

    Probability=514\text{Probability} = \frac{5}{14}
    4. Identify the answer

    Comparing our result to the given options, the correct choice is C.

    5. Tip

    When counting numbers in an inclusive range (e.g., "from X to Y"), always remember to add 1 to the difference (Y−X)(Y - X). A common mistake students make is calculating 34−21=1334 - 21 = 13 and forgetting to include the starting number, which leads to an incorrect denominator!

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  80. 80.

    Solve the inequality: -7 ≤\leq 9 - 8x < 16 - x

    1. A.-1 ≤\leq x ≤\leq 2
    2. B.-1 ≤\leq x < 2
    3. C.-1 < x < 2
    4. D.-1 < x ≤\leq 2
    Show answer

    Answer: D. -1 < x ≤\leq 2

    AI explanation

    To solve the inequality −7≤9−8x<16−x-7 \leq 9 - 8x < 16 - x, we need to split it into two separate inequalities and solve them individually, then find the intersection of their solution sets.

    Step 1: Solve the first part

    −7≤9−8x-7 \leq 9 - 8x

    Subtract 9 from both sides: −7−9≤−8x-7 - 9 \leq -8x −16≤−8x-16 \leq -8x

    Now, divide both sides by -8. Remember: When you divide or multiply an inequality by a negative number, the inequality sign must be reversed. −16−8≥x\frac{-16}{-8} \geq x 2≥x2 \geq x (or x≤2x \leq 2)

    Step 2: Solve the second part

    9−8x<16−x9 - 8x < 16 - x

    Group the xx terms on one side and the constants on the other. Add 8x8x to both sides: 9<16−x+8x9 < 16 - x + 8x 9<16+7x9 < 16 + 7x

    Subtract 16 from both sides: 9−16<7x9 - 16 < 7x −7<7x-7 < 7x

    Divide both sides by 7: −1<x-1 < x (or x>−1x > -1)

    Step 3: Combine the results

    We have two conditions:

    1. x≤2x \leq 2
    2. x>−1x > -1

    Combining these, we get: −1<x≤2-1 < x \leq 2

    Our calculated result, −1<x≤2-1 < x \leq 2, matches this option perfectly.

    Exam Tip: When dealing with compound inequalities, always remember the "Golden Rule": if you multiply or divide by a negative number, flip the inequality sign immediately! It is the most common place where students lose marks in JAMB Mathematics.

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