JAMB 2019 Mathematics · Question 51

Evaluate (60.32÷20.084)−1(\frac{6}{0.32} \div \frac{2}{0.084})^{-1} correct to 1 decimal place.

Options

  1. A.1.3
  2. B.2.5
  3. C.4.6
  4. D.3.2

Answer: A. 1.3

Explanation written with AI and checked against the answer key

Step 1: Analyze the question

We need to evaluate the expression (60.32÷20.084)−1(\frac{6}{0.32} \div \frac{2}{0.084})^{-1} and round the result to one decimal place.

Step 2: Explain the concept

To solve this, we follow the order of operations (BODMAS):

  1. Solve the divisions inside the parentheses first.
  2. Remember that dividing by a fraction is the same as multiplying by its reciprocal (flip the second fraction).
  3. Apply the exponent −1-1, which means finding the reciprocal of the final result (x−1=1xx^{-1} = \frac{1}{x}).
Step 3: Show the solution

Part A: Simplify the fractions inside the parentheses First, let's simplify the two divisions:

  • 60.32=60032=18.75\frac{6}{0.32} = \frac{600}{32} = 18.75
  • 20.084=200084≈23.8095\frac{2}{0.084} = \frac{2000}{84} \approx 23.8095

Part B: Perform the division Now, we divide the first result by the second: 18.75÷23.809518.75 \div 23.8095

Using the reciprocal method for accuracy: 60.32×0.0842\frac{6}{0.32} \times \frac{0.084}{2} =62×0.0840.32= \frac{6}{2} \times \frac{0.084}{0.32} =3×84320= 3 \times \frac{84}{320} =3×0.2625=0.7875= 3 \times 0.2625 = 0.7875

Part C: Apply the exponent −1-1 The expression is (0.7875)−1(0.7875)^{-1}, which is 10.7875\frac{1}{0.7875}: 10.7875≈1.2698\frac{1}{0.7875} \approx 1.2698

Part D: Round to 1 decimal place Rounding 1.26981.2698 to one decimal place gives 1.3.

Step 4: Identify the answer

Comparing our result to the given options, we see that 1.3 matches option A.

Step 5: Exam Tip

When dealing with decimals in JAMB, convert them to whole numbers by multiplying the numerator and denominator by powers of 10 (e.g., 10,100,100010, 100, 1000). This eliminates decimal errors and makes the division much easier to handle without a calculator.

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