JAMB 2015 Mathematics · Question 54

Solve the equation 3x2−4x−5=0 3x^2 − 4x − 5 = 0

Options

  1. A.x = 1.75 or − 0.15
  2. B.x = 2.12 or − 0.79
  3. C.x = 1.5 or − 0.34
  4. D.x = 2.35 or −1.23

Answer: B. x = 2.12 or − 0.79

Explanation written with AI and checked against the answer key

Analysis

To solve the quadratic equation 3x2−4x−5=03x^2 - 4x - 5 = 0, we need to find the values of xx that satisfy the equation. Since this equation does not factorize easily into simple integers, we use the Quadratic Formula.

Concept: The Quadratic Formula

For any quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0, the solutions for xx are given by:

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

In your equation (3x2−4x−5=03x^2 - 4x - 5 = 0):

  • a=3a = 3
  • b=−4b = -4
  • c=−5c = -5
Step-by-Step Solution

1. Substitute the values into the formula:

x=−(−4)±(−4)2−4(3)(−5)2(3)x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(3)(-5)}}{2(3)}

2. Simplify the terms:

  • −(−4)=4-(-4) = 4
  • (−4)2=16(-4)^2 = 16
  • −4×3×−5=60-4 \times 3 \times -5 = 60
  • 2×3=62 \times 3 = 6

So, the equation becomes:

x=4±16+606x = \frac{4 \pm \sqrt{16 + 60}}{6}
x=4±766x = \frac{4 \pm \sqrt{76}}{6}

3. Calculate the square root: 76≈8.7178\sqrt{76} \approx 8.7178

4. Solve for the two possible values of xx:

  • Case 1 (Addition): x=4+8.71786=12.71786≈2.1196≈2.12x = \frac{4 + 8.7178}{6} = \frac{12.7178}{6} \approx 2.1196 \approx \mathbf{2.12}
  • Case 2 (Subtraction): x=4−8.71786=−4.71786≈−0.7863≈−0.79x = \frac{4 - 8.7178}{6} = \frac{-4.7178}{6} \approx -0.7863 \approx \mathbf{-0.79}
Conclusion

Comparing our results (x≈2.12x \approx 2.12 or −0.79-0.79) with the given options, we find that they match option B.

Exam Tip

When you see a quadratic equation in a JAMB exam, always check the discriminant (b2−4acb^2 - 4ac) first. If it is not a perfect square, you know immediately that the answer will involve decimals, and you should reach for the quadratic formula rather than trying to factorize by grouping!

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