JAMB 2015 Mathematics · Question 53

Find the distance between the points (-2,-3) and (-2,4)

Options

  1. A.3m
  2. B.2.4m
  3. C.3.2m
  4. D.7.0m

Answer: D. 7.0m

Explanation written with AI and checked against the answer key

1. Analyze the question

We are asked to find the distance between two points on a Cartesian plane: P1(−2,−3)P_1(-2, -3) and P2(−2,4)P_2(-2, 4).

2. Explain the concept

The distance dd between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is calculated using the distance formula:

d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Observation: Notice that the xx-coordinates for both points are the same (x1=−2x_1 = -2 and x2=−2x_2 = -2). When the xx-coordinates are identical, the line connecting the points is a vertical line. In this case, the distance is simply the absolute difference between the yy-coordinates:

d=∣y2−y1∣d = |y_2 - y_1|
3. Show the solution

Using the coordinates P1(−2,−3)P_1(-2, -3) and P2(−2,4)P_2(-2, 4):

  • x1=−2,y1=−3x_1 = -2, y_1 = -3
  • x2=−2,y2=4x_2 = -2, y_2 = 4

Method 1 (Using the formula):

d=(−2−(−2))2+(4−(−3))2d = \sqrt{(-2 - (-2))^2 + (4 - (-3))^2}
d=(0)2+(4+3)2d = \sqrt{(0)^2 + (4 + 3)^2}
d=02+72d = \sqrt{0^2 + 7^2}
d=49d = \sqrt{49}
d=7d = 7

Method 2 (Vertical distance shortcut): Since the xx-coordinates are the same, the distance is the vertical change:

d=∣4−(−3)∣d = |4 - (-3)|
d=∣4+3∣d = |4 + 3|
d=7d = 7
4. Identify the answer

Comparing our result to the given options, the distance is 7.0 units. Note that while the options include "m" (meters), the calculation yields a scalar value of 7.

The correct option is D.

5. Exam Tip

Whenever you see two points with the same xx-coordinate, don't waste time with the full square root formula! Just subtract the yy-values. If the yy-coordinates were the same, you would just subtract the xx-values. This saves precious time during your JAMB exam.

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