JAMB 2010 Mathematics · Question 41
Find the equation of a line parallel to y = -4x + 2 passing through (2,3)
Options
- A.y + 4x + 11 = 0
- B.y - 4x - 11 = 0
- C.y + 4x - 11 = 0
- D.y - 4x + 11 = 0
Answer: C. y + 4x - 11 = 0
Explanation written with AI and checked against the answer key
Analyze the question: We need a line parallel to y = -4x + 2 that passes through the point (2, 3).
Concept: Parallel lines have the same gradient (slope). The line y = -4x + 2 is in the form y = mx + c, so its gradient is m = -4. Our new line must also have m = -4.
Solution:
Use the point-slope form: y - y₁ = m(x - x₁)
y - 3 = -4(x - 2)
y - 3 = -4x + 8
y + 4x - 3 - 8 = 0
y + 4x - 11 = 0
Check: Substitute (2, 3): 3 + 4(2) - 11 = 3 + 8 - 11 = 0 ✓
Compare with the options:
- A: y + 4x + 11 = 0 → 3 + 8 + 11 = 22 ≠ 0 ✗
- B: gradient is +4, so not parallel ✗
- C: y + 4x - 11 = 0 → works ✓
- D: gradient is +4 ✗
Tip: For "parallel" questions, copy the gradient. For "perpendicular" questions, use the negative reciprocal. Then plug in the point to confirm. Checking the given point in each option is a fast way to eliminate wrong choices in the exam hall.
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