JAMB 2010

2010 JAMB Mathematics Past Questions

The 2010 JAMB Mathematics past questions with answers: 49 objective questions from the 2010 paper in the DeeepSolve question bank, each with its answer behind "Show answer". Try each question before you check, then practise the paper as a timed JAMB-style CBT.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.

Questions

  1. 1.

    If y = (2x + 1)3^3 find ddx\frac{\text{d}}{\text{dx}}

    1. A.3(2x+1)2
    2. B.6(2x+1)
    3. C.3(2x+1)
    4. D.6(2x+1)2
    Show answer

    Answer: D. 6(2x+1)2

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  2. 2.

    If y varies directly as the square root of x and y = 3 when x = 16. Calculate y when x = 64

    1. A.12
    2. B.6
    3. C.3
    4. D.5
    Show answer

    Answer: B. 6

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  3. 3.

    The interior angles of a quadrilateral are (x + 15)°, (2x - 45)°, ( x - 30)° and (x + 10)°. Find the value of the least interior angle.

    1. A.112o
    2. B.102o
    3. C.82o
    4. D.52o
    Show answer

    Answer: D. 52o

    AI explanation

    1. Analyze the question

    We are given the four interior angles of a quadrilateral in terms of xx. We need to find the value of xx first, then substitute it back into each expression to identify the smallest angle.

    2. Explain the concept

    The sum of the interior angles of any quadrilateral is always 360°. The formula for the sum of interior angles of a polygon with nn sides is (n−2)×180∘(n - 2) \times 180^\circ. For a quadrilateral (n=4n=4): (4−2)×180∘=2×180∘=360∘(4 - 2) \times 180^\circ = 2 \times 180^\circ = 360^\circ.

    3. Show the solution

    Step 1: Set up the equation Sum the given angles and equate them to 360°: (x+15)+(2x−45)+(x−30)+(x+10)=360(x + 15) + (2x - 45) + (x - 30) + (x + 10) = 360

    Step 2: Simplify the equation Group the xx terms and the constant numbers: (x+2x+x+x)+(15−45−30+10)=360(x + 2x + x + x) + (15 - 45 - 30 + 10) = 360 5x−50=3605x - 50 = 360

    Step 3: Solve for xx 5x=360+505x = 360 + 50 5x=4105x = 410 x=4105x = \frac{410}{5} x=82x = 82

    Step 4: Calculate each angle Now, substitute x=82x = 82 into each expression:

    1. (x+15)=82+15=97∘(x + 15) = 82 + 15 = 97^\circ
    2. (2x−45)=2(82)−45=164−45=119∘(2x - 45) = 2(82) - 45 = 164 - 45 = 119^\circ
    3. (x−30)=82−30=52∘(x - 30) = 82 - 30 = 52^\circ
    4. (x+10)=82+10=92∘(x + 10) = 82 + 10 = 92^\circ

    Step 5: Identify the least angle Comparing 97∘,119∘,52∘,97^\circ, 119^\circ, 52^\circ, and 92∘92^\circ, the smallest value is 52°.

    4. Identify the answer

    The calculated value for the least interior angle is 52°, which corresponds to option D.

    5. Tip

    When dealing with geometry problems involving variables, always check your final answers by adding them up. If they don't sum to the required total (360° for a quadrilateral), you know you made a calculation error in your algebra!

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  4. 4.

    If x * y = x + y2^2, find then value of (2*3)*5

    1. A.36
    2. B.25
    3. C.11
    4. D.55
    Show answer

    Answer: A. 36

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  5. 5.

    From the cyclic quadrilateral TUVW above, find the value of x

    1. A.26o
    2. B.24o
    3. C.20o
    4. D.23o
    Show answer

    Answer: C. 20o

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  6. 6.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  7. 7.

    Find the distance between the points (12\frac{1}{2}, 12\frac{1}{2}) and (-12\frac{1}{2}, -12\frac{1}{2}).

    1. A.1
    2. B.o
    3. C.√3
    4. D.√2
    Show answer

    Answer: D. √2

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  8. 8.

    Make Q the subject of formula if p = M5\frac{M}{5}(X + Q) + 1

    1. A.5P−MX+5M\frac{5P - MX + 5}{M}
    2. B.5P−MX−5M\frac{5P - MX - 5}{M}
    3. C.5P+MX+5M\frac{5P + MX + 5}{M}
    4. D.5P+MX−5M\frac{5P + MX - 5}{M}
    Show answer

    Answer: B. 5P−MX−5M\frac{5P - MX - 5}{M}

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  9. 9.

    Find ∫(sin x + 2)dx

    1. A.cos x + x2 + K
    2. B.cos x 2x + K
    3. C.-cos x + x2 + K
    4. D.-cos x + 2x + K
    Show answer

    Answer: D. -cos x + 2x + K

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  10. 10.

    The 3rd term of an arithmetic progression is -9 and the 7th term is -29. Find the 10th term of the progression

    1. A.-44
    2. B.-165
    3. C.165
    4. D.44
    Show answer

    Answer: A. -44

    AI explanation

    Analysis

    To solve this problem, we need to use the formula for the nthn^{th} term of an Arithmetic Progression (AP):

    Tn=a+(n−1)dT_n = a + (n - 1)d

    Where:

    • aa is the first term
    • dd is the common difference
    • nn is the position of the term
    Concept

    An arithmetic progression is a sequence where the difference between consecutive terms is constant. We are given the 3rd term (T3T_3) and the 7th term (T7T_7). We will use these to create a system of linear equations to find aa and dd, then use those values to find the 10th term (T10T_{10}).

    Step-by-Step Solution

    1. Set up the equations based on the given information:

    • For the 3rd term (n=3n=3): T3=a+(3−1)d=−9T_3 = a + (3 - 1)d = -9 a+2d=−9a + 2d = -9 --- (Equation 1)
    • For the 7th term (n=7n=7): T7=a+(7−1)d=−29T_7 = a + (7 - 1)d = -29 a+6d=−29a + 6d = -29 --- (Equation 2)

    2. Solve the system of equations: Subtract Equation 1 from Equation 2 to eliminate aa: (a+6d)−(a+2d)=−29−(−9)(a + 6d) - (a + 2d) = -29 - (-9) 4d=−29+94d = -29 + 9 4d=−204d = -20 d=−5d = -5

    3. Find the first term (aa): Substitute d=−5d = -5 into Equation 1: a+2(−5)=−9a + 2(-5) = -9 a−10=−9a - 10 = -9 a=−9+10a = -9 + 10 a=1a = 1

    4. Calculate the 10th term (T10T_{10}): Using a=1a = 1, d=−5d = -5, and n=10n = 10: T10=a+(10−1)dT_{10} = a + (10 - 1)d T10=1+9(−5)T_{10} = 1 + 9(-5) T10=1−45T_{10} = 1 - 45 T10=−44T_{10} = -44

    Conclusion

    Comparing our result to the options provided, the 10th term is -44, which matches option A.

    Exam Tip

    When dealing with AP questions, always remember that any term TnT_n can be expressed as Tm+(n−m)dT_m + (n-m)d. For example, you could have jumped straight to the common difference by saying T7=T3+4dT_7 = T_3 + 4d. This saves time during the exam!

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  11. 11.

    Find r, if 6r78_8 = 5119_9

    1. A.3
    2. B.2
    3. C.6
    4. D.5
    Show answer

    Answer: A. 3

    AI explanation

    1. Analyze the question

    We are given an equation involving numbers in different bases: 6r78=51196r7_8 = 511_9. We need to find the value of the digit rr.

    2. Explain the concept

    To solve problems involving different bases, we convert both sides of the equation to Base 10 (decimal system). The formula to convert a number dn...d2d1d0d_n...d_2d_1d_0 in base xx to base 10 is: (dn×xn)+...+(d2×x2)+(d1×x1)+(d0×x0)(d_n \times x^n) + ... + (d_2 \times x^2) + (d_1 \times x^1) + (d_0 \times x^0)

    3. Show the solution

    Step 1: Convert the left side (6r786r7_8) to base 10 6r78=(6×82)+(r×81)+(7×80)6r7_8 = (6 \times 8^2) + (r \times 8^1) + (7 \times 8^0) =(6×64)+(8r)+(7×1)= (6 \times 64) + (8r) + (7 \times 1) =384+8r+7= 384 + 8r + 7 =391+8r= 391 + 8r

    Step 2: Convert the right side (5119511_9) to base 10 5119=(5×92)+(1×91)+(1×90)511_9 = (5 \times 9^2) + (1 \times 9^1) + (1 \times 9^0) =(5×81)+(1×9)+(1×1)= (5 \times 81) + (1 \times 9) + (1 \times 1) =405+9+1= 405 + 9 + 1 =415= 415

    Step 3: Equate both sides and solve for rr 391+8r=415391 + 8r = 415 Subtract 391 from both sides: 8r=415−3918r = 415 - 391 8r=248r = 24 Divide by 8: r=248r = \frac{24}{8} r=3r = 3

    4. Identify the answer

    Comparing our result with the given options, r=3r = 3 corresponds to option A.

    5. Tip

    When dealing with base conversion, always remember that the digit in the base must be smaller than the base itself. Since the number is in base 8, the digit rr must be less than 8. Our answer, 3, satisfies this condition perfectly!

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  12. 12.

    For what range of values of x is 12\frac{1}{2}x + 14\frac{1}{4} > 13\frac{1}{3}x + 12\frac{1}{2}?

    1. A.x < 32\frac{3}{2}
    2. B.x > 32\frac{3}{2}
    3. C.x < -32\frac{3}{2}
    4. D.x > -32\frac{3}{2}
    Show answer

    Answer: B. x > 32\frac{3}{2}

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  13. 13.

    If p and q are two non zero numbers and 18(p+q) = (18+p)q, which of the following must be true?

    1. A.q = 18
    2. B.p <1
    3. C.p = 18
    4. D.q < 1
    Show answer

    Answer: A. q = 18

    AI explanation

    Analysis of the Question

    We are given the equation 18(p+q)=(18+p)q18(p + q) = (18 + p)q where pp and qq are non-zero numbers. We need to simplify this expression to determine the relationship between pp and qq and identify which of the given options must be true.

    Concept Explanation

    This is an algebraic manipulation problem. The goal is to expand the brackets on both sides of the equation and rearrange the terms to isolate one variable or find a constant relationship.

    Step-by-Step Solution

    Step 1: Expand both sides of the equation. Given: 18(p+q)=(18+p)q18(p + q) = (18 + p)q

    Expand the left side: 18p+18q18p + 18q

    Expand the right side: 18q+pq18q + pq

    Step 2: Set the expanded sides equal to each other. 18p+18q=18q+pq18p + 18q = 18q + pq

    Step 3: Simplify the equation. Subtract 18q18q from both sides: 18p=pq18p = pq

    Step 4: Solve for the variables. Since the problem states that pp and qq are non-zero numbers, we can safely divide both sides by pp: 18pp=pqp\frac{18p}{p} = \frac{pq}{p} 18=q18 = q

    This shows that regardless of the value of pp (as long as it is not zero), qq must be equal to 18 for the equation to hold true.

    Conclusion

    Comparing our result (q=18q = 18) with the given options, we can see that option A is the correct statement.

    Exam Tip

    When you see an equation with variables on both sides, always expand the brackets first. If you see the same term on both sides (like the 18q18q we had here), you can cancel them out immediately to save time and reduce the risk of calculation errors!

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  14. 14.

    In how many ways can a committee of 2 women and 3 men be chosen from 6 men and 5 women?

    1. A.100
    2. B.200
    3. C.30
    4. D.50
    Show answer

    Answer: B. 200

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  15. 15.

    Evaluate ∫02(x3+x2)\int^{2}_{0}(x^3 + x^2)dx.

    1. A.456\frac{5}{6}
    2. B.623\frac{2}{3}
    3. C.156\frac{5}{6}
    4. D.256\frac{5}{6}
    Show answer

    Answer: B. 623\frac{2}{3}

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  16. 16.

    If p : q = 23\frac{2}{3} : 56\frac{5}{6} and q : r = 34\frac{3}{4} : 12\frac{1}{2}, find p : q : r

    1. A.12 : 15 : 10
    2. B.12 : 15 : 16
    3. C.10 : 15 : 24
    4. D.9 : 10 : 15
    Show answer

    Answer: A. 12 : 15 : 10

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  17. 17.

    Find the standard deviation of 2, 3, 5 and 6

    1. A.√6
    2. B.√10
    3. C.√25\frac{2}{5}
    4. D.√52\frac{5}{2}
    Show answer

    Answer: D. √52\frac{5}{2}

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  18. 18.

    Find the sum to infinity of the following series. 0.5 + 0.05 + 0.005 + 0.0005 + .....

    1. A.58\frac{5}{8}
    2. B.57\frac{5}{7}
    3. C.511\frac{5}{11}
    4. D.59\frac{5}{9}
    Show answer

    Answer: D. 59\frac{5}{9}

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  19. 19.

    A student measures a piece of rope and found that it was 1.26m long. If the actual length of the rope was 1.25m, what was the percentage error in the measurement?

    1. A.0.25%
    2. B.0.01%
    3. C.0.80%
    4. D.0.40%
    Show answer

    Answer: C. 0.80%

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  20. 20.

    If P = (2−311)\begin{pmatrix} 2 & -3 \\ 1 & 1 \end{pmatrix} , what is P−1^-1

    1. A.(−15−35−15−25)\begin{pmatrix} -{\frac{1}{5}} & -{\frac{3}{5}} \\ -{\frac{1}{5}} & -{\frac{2}{5}} \end{pmatrix}
    2. B.(15351525)\begin{pmatrix} {\frac{1}{5}} & {\frac{3}{5}} \\ {\frac{1}{5}} & {\frac{2}{5}} \end{pmatrix}
    3. C.(−1535−1525)\begin{pmatrix} -{\frac{1}{5}} & {\frac{3}{5}} \\ -{\frac{1}{5}} & {\frac{2}{5}} \end{pmatrix}
    4. D.(1535−1525)\begin{pmatrix} {\frac{1}{5}} & {\frac{3}{5}} \\ -{\frac{1}{5}} & {\frac{2}{5}} \end{pmatrix}
    Show answer

    Answer: D. (1535−1525)\begin{pmatrix} {\frac{1}{5}} & {\frac{3}{5}} \\ -{\frac{1}{5}} & {\frac{2}{5}} \end{pmatrix}

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  21. 21.

    If two smaller sides of a right angled triangle are 4cm and 5cm, find its area

    1. A.10 cm2
    2. B.6 cm2
    3. C.24 cm2
    4. D.8 cm2
    Show answer

    Answer: A. 10 cm2

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  22. 22.

    Determine the value of x for which (x2^2 - 1)>0

    1. A.x < -1 or x > 1
    2. B.-1 < x < 1
    3. C.x > 0
    4. D.x < -1
    Show answer

    Answer: A. x < -1 or x > 1

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  23. 23.

    If three unbiased coins are tossed, find the probability that they are all heads

    1. A.12\frac{1}{2}
    2. B.13\frac{1}{3}
    3. C.19\frac{1}{9}
    4. D.18\frac{1}{8}
    Show answer

    Answer: D. 18\frac{1}{8}

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  24. 24.

    Evaluate ∣205463891∣\begin{vmatrix} 2 & 0 & 5 \\ 4 & 6 & 3 \\ 8 & 9 & 1 \end{vmatrix}

    1. A.5y - 2x -18 = 0
    2. B.102
    3. C.-102
    4. D.-42
    Show answer

    Answer: C. -102

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  25. 25.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  26. 26.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  27. 27.

    An arc subtends an angle of 50º at the center of circle of radius 6cm. Calculate the area of the sector formed

    1. A.100/7
    2. B.80/7
    3. C.110/7
    4. D.90/7
    Show answer

    Answer: C. 110/7

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  28. 28.

    At what rate will the interest on N400 increases to N24 in 3 years reckoning in simple interest?

    1. A.3%
    2. B.2%
    3. C.5%
    4. D.4%
    Show answer

    Answer: B. 2%

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  29. 29.

    If 9x2^2 + 6xy + 4y2^2 is a factor of 27x3^3 - 8y3^3, find the other factor.

    1. A.2y + 3x
    2. B.2y - 3x
    3. C.3x + 2y
    4. D.3x - 2y
    Show answer

    Answer: D. 3x - 2y

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  30. 30.

    Evaluate (8116)−14×2−1\left(\frac{81}{16}\right)^{\frac{-1}{4}}\times 2^{-1}

    1. A.1/3
    2. B.3
    3. C.6
    4. D.1/6
    Show answer

    Answer: A. 1/3

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  31. 31.This question needs a diagram, table or passage that we don't have yet, so it isn't shown.

  32. 32.

    W is directly proportional to U. If W = 5 when U = 3, find U when W = 27\frac{2}{7}

    1. A.635\frac{6}{35}
    2. B.1021\frac{10}{21}
    3. C.2110\frac{21}{10}
    4. D.356\frac{35}{6}
    Show answer

    Answer: A. 635\frac{6}{35}

    AI explanation

    Analysis

    The question involves Direct Variation. When a variable WW is directly proportional to UU, it means that as UU increases, WW increases at a constant rate. Mathematically, this is expressed as W=kUW = kU, where kk is the constant of proportionality.

    Concept
    1. Find the constant (kk): Use the initial values given (W=5,U=3W=5, U=3) to determine the value of kk.
    2. Form the equation: Substitute kk back into the general formula W=kUW = kU.
    3. Solve for the unknown: Use the new value of WW to find the corresponding value of UU.
    Step-by-Step Solution

    Step 1: Find kk Given W=kUW = kU: 5=k×35 = k \times 3 k=53k = \frac{5}{3}

    Step 2: Form the equation Now that we know k=53k = \frac{5}{3}, our specific equation is: W=53UW = \frac{5}{3}U

    Step 3: Solve for UU when W=27W = \frac{2}{7} Substitute W=27W = \frac{2}{7} into the equation: 27=53U\frac{2}{7} = \frac{5}{3}U

    To isolate UU, multiply both sides by the reciprocal of 53\frac{5}{3}, which is 35\frac{3}{5}: U=27×35U = \frac{2}{7} \times \frac{3}{5} U=2×37×5U = \frac{2 \times 3}{7 \times 5} U=635U = \frac{6}{35}

    Conclusion

    Comparing our result to the options provided, we can see that our calculated value matches option A.

    Exam Tip: In variation problems, always ensure you find the constant (kk) first. A common mistake students make is trying to use ratios incorrectly; writing out W=kUW = kU clearly at the start of your working prevents this error.

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  33. 33.

    Find the gradient of the line passing through the points P(1, 1) and Q(2, 5).

    1. A.3
    2. B.2
    3. C.5
    4. D.4
    Show answer

    Answer: D. 4

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  34. 34.

    If ∣x327∣=15\begin{vmatrix} x & 3 \\ 2 & 7 \end{vmatrix} = 15, find the value of x

    1. A.3
    2. B.4
    3. C.5
    4. D.2
    Show answer

    Answer: A. 3

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  35. 35.

    Factorize completely x3+3x2−10x2x2−8\frac{x^{3} + 3x^{2} - 10x}{2x^{2} - 8}

    1. A.x(x-5)2(x+2)
    2. B.x(x-5)2(x-2)
    3. C.x(x+5)2(x+2)
    4. D.x2+52x+4
    Show answer

    Answer: C. x(x+5)2(x+2)

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  36. 36.

    At what value of X does the function y = -3 - 2x + X2 attain a minimum value?

    1. A.-1
    2. B.14
    3. C.4
    4. D.1
    Show answer

    Answer: D. 1

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  37. 37.

    If the area of ΔPQR above is 123\sqrt{3} cm2^2, find the value of q?

    1. A.6 cm
    2. B.7 cm
    3. C.8 cm
    4. D.5 cm
    Show answer

    Answer: C. 8 cm

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  38. 38.

    Solve the inequalities -6 ≤\leq 4 - 2x < 5 - x

    1. A.-1 < x < 5
    2. B.-1 < x ≤\leq 5
    3. C.-1 ≤\leq x ≤\leq 6
    4. D.-1 ≤\leq x < 6
    Show answer

    Answer: B. -1 < x ≤\leq 5

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  39. 39.

    Express the product of 0.21 and 0.34 in standard form

    1. A.7.14 x 10-3
    2. B.7.14 x 10-2
    3. C.7.14 x 10-1
    4. D.7.14 x 10-4
    Show answer

    Answer: B. 7.14 x 10-2

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  40. 40.

    If x is inversely proportional to y and x = 212\frac{1}{2} when y = 2, find x if y = 4

    1. A.4
    2. B.5
    3. C.114\frac{1}{4}
    4. D.214\frac{1}{4}
    Show answer

    Answer: C. 114\frac{1}{4}

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  41. 41.

    Find the equation of a line parallel to y = -4x + 2 passing through (2,3)

    1. A.y + 4x + 11 = 0
    2. B.y - 4x - 11 = 0
    3. C.y + 4x - 11 = 0
    4. D.y - 4x + 11 = 0
    Show answer

    Answer: C. y + 4x - 11 = 0

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  42. 42.

    Solve for x and y if x - y = 2 and x2 - y2 = 8

    1. A.(-1, 3)
    2. B.(3, 1)
    3. C.(-3, 1)
    4. D.(1, 3)
    Show answer

    Answer: B. (3, 1)

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  43. 43.

    In a survey of 50 newspaper readers, 40 read Champion and 30 read Guardian, how many read both papers?

    1. A.10
    2. B.5
    3. C.15
    4. D.20
    Show answer

    Answer: D. 20

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  44. 44.

    If y = x sinx, find dydx\frac{dy}{dx}

    1. A.sin x - x cosx
    2. B.sinx + x cosx
    3. C.sinx - cosx
    4. D.sinx + cosx
    Show answer

    Answer: B. sinx + x cosx

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  45. 45.

    A cylindrical pipe 50m long with radius 7m has one end open. What is the total surface area of the pipe?

    1. A.749π\pim2
    2. B.700π\pim2
    3. C.350π\pim2
    4. D.98π\pim2
    Show answer

    Answer: A. 749π\pim2

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  46. 46.

    Simplify (34\frac{3}{4} of 49\frac{4}{9} ÷\div 912\frac{1}{2}) ÷\div 1519\frac{5}{19}

    1. A.15\frac{1}{5}
    2. B.14\frac{1}{4}
    3. C.136\frac{1}{36}
    4. D.125\frac{1}{25}
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    Answer: C. 136\frac{1}{36}

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  47. 47.

    What is the locus of point that is equidistant from points P(1,3) and Q(3,5)?

    1. A.y = -χ + 6
    2. B.y = -χ - 6
    3. C.y = χ + 6
    4. D.y = χ - 6
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    Answer: A. y = -χ + 6

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  48. 48.

    Rationalize 23+55−3\frac{2\sqrt{3} + \sqrt{5}}{\sqrt{5} - \sqrt{3}}

    1. A.(3 √ 15 +11) / 2
    2. B.3 √ 15 -11
    3. C.(3 √ 15 -11) / 2
    4. D.3 √ 15 +11
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    Answer: A. (3 √ 15 +11) / 2

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  49. 49.

    If cotθ\theta = 815\frac{8}{15}, where θ\theta is acute, find sinθ\theta

    1. A.817\frac{8}{17}
    2. B.1517\frac{15}{17}
    3. C.1617\frac{16}{17}
    4. D.1317\frac{13}{17}
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    Answer: B. 1517\frac{15}{17}

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