NECO 2004 Physics · Question 21
The resultant of two forces P and Q is least when the angle between them is
Options
- A.0°
- B.45°
- C.60°
- D.90°
- E.180°
Answer: E. 180°
Explanation written with AI and checked against the answer key
Analyze the question: We want the angle θ between forces P and Q that makes their resultant R as small as possible.
Concept: The magnitude of the resultant of two forces is given by the cosine rule (parallelogram law):
R = √(P² + Q² + 2PQ cos θ)
Solution:
R depends on cos θ, so R is smallest when cos θ is smallest.
- θ = 0°: cos θ = 1, so R = P + Q (the maximum)
- θ = 45°: cos θ ≈ 0.707
- θ = 60°: cos θ = 0.5
- θ = 90°: cos θ = 0, so R = √(P² + Q²)
- θ = 180°: cos θ = -1, so R = √(P² − 2PQ + Q²) = |P − Q| (the minimum)
The smallest value of cos θ among the options is -1, at 180°. At this angle the forces act in exactly opposite directions, so they partly cancel and the resultant is just the difference of their magnitudes.
Answer: E. 180°
Exam tip: Remember the two extremes:
- Same direction (0°) gives the maximum resultant, P + Q.
- Opposite directions (180°) gives the minimum resultant, |P − Q|.
Whenever you see "greatest" or "least" resultant, check these two angles first.
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