NECO 2004 Physics · Question 19

A car travels with a constant velocity of 45 kmh−1kmh^{-1} for 20s. What distance does it cover in this time?

Options

  1. A.0.025m
  2. B.0.250m
  3. C.2.500m
  4. D.25.000m
  5. E.250.000m

Answer: E. 250.000m

Explanation written with AI and checked against the answer key

Analyze the question: A car moves at a constant velocity of 45 km/h for 20 s. We need the distance covered, and the options are in metres. Concept: For constant velocity, distance = velocity × time. The units must match, so we convert km/h to m/s first. Conversion: 1 km/h = 1000 m / 3600 s = 5/18 m/s 45 km/h = 45 × (5/18) = 12.5 m/s Solution: Distance = v × t = 12.5 m/s × 20 s = 250 m Check against the options: 250. Answer: E (250.000 m) Tip: To convert km/h to m/s, multiply by 5/18. A quick shortcut is to divide by 3.6, so 45 ÷ 3.6 = 12.5. Always convert units before substituting into a formula. Many students lose marks by using 45 × 20 = 900 directly.

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