JAMB 2015 Physics · Question 28
The dimension of universal gravitational constant is……….?
Options
- A.
- B.ML3T2
- C.ML3
- D.MLT-2
Answer: A.
Explanation written with AI and checked against the answer key
Analyze the question: We need the dimensional formula of the universal gravitational constant, G.
Concept: Newton's law of gravitation says
F = G m₁m₂ / r²
Rearranging for G:
G = F r² / (m₁ m₂)
Solution:
Dimensions of each quantity:
- Force, F = MLT⁻²
- Distance squared, r² = L²
- Mass product, m₁m₂ = M²
Substitute:
G = (MLT⁻² × L²) / M²
G = ML³T⁻² / M²
G = M⁻¹L³T⁻²
Checking the options:
- A. M⁻¹L³T⁻², which matches our result.
- B. ML³T², which has the wrong powers of M and T.
- C. ML³, which is incomplete.
- D. MLT⁻², which is the dimension of force, not G.
The SI unit of G is N·m²/kg², which is m³ kg⁻¹ s⁻². This agrees with M⁻¹L³T⁻².
Exam tip: For dimension questions, start from a formula that contains the quantity, make it the subject, and replace each term with its dimensions. Remember that force is MLT⁻². You can also check by converting the units: m³ kg⁻¹ s⁻² gives L³ M⁻¹ T⁻² straight away.
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