JAMB 2015 Physics · Question 28

The dimension of universal gravitational constant is……….?

Options

  1. A.M­–1L3T–2 M­^{–1}L^3 T^{–2}
  2. B.ML3T2
  3. C.ML3
  4. D.MLT-2

Answer: A. M­–1L3T–2 M­^{–1}L^3 T^{–2}

Explanation written with AI and checked against the answer key

Analyze the question: We need the dimensional formula of the universal gravitational constant, G.

Concept: Newton's law of gravitation says

F = G m₁m₂ / r²

Rearranging for G:

G = F r² / (m₁ m₂)

Solution:

Dimensions of each quantity:

  • Force, F = MLT⁻²
  • Distance squared, r² = L²
  • Mass product, m₁m₂ = M²

Substitute:

G = (MLT⁻² × L²) / M²

G = ML³T⁻² / M²

G = M⁻¹L³T⁻²

Checking the options:

  • A. M⁻¹L³T⁻², which matches our result.
  • B. ML³T², which has the wrong powers of M and T.
  • C. ML³, which is incomplete.
  • D. MLT⁻², which is the dimension of force, not G.

The SI unit of G is N·m²/kg², which is m³ kg⁻¹ s⁻². This agrees with M⁻¹L³T⁻².

Exam tip: For dimension questions, start from a formula that contains the quantity, make it the subject, and replace each term with its dimensions. Remember that force is MLT⁻². You can also check by converting the units: m³ kg⁻¹ s⁻² gives L³ M⁻¹ T⁻² straight away.

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