Mr. F. Abioye observed his image through a plane mirror, kept at a distance 4.7m away from him in his room. At…

Analysis of the Question

The question asks for the distance between Mr. Abioye and his image as seen in a plane mirror. You are given the distance between the object (Mr. Abioye) and the mirror.

Concept: Properties of Plane Mirrors

In physics, plane mirrors follow specific laws of reflection:

1. Object Distance = Image Distance: The distance of the object from the mirror ($u$) is exactly equal to the distance of the image from the mirror ($v$).
2. Virtual Image: The image formed is virtual and appears to be located behind the mirror at the same distance as the object is in front of it.

Step-by-Step Solution

1. Identify the given values: • Distance from Mr. Abioye to the mirror ($u$) = 4.7 m. • Since the image is formed at the same distance behind the mirror, the distance from the mirror to the image ($v$) = 4.7 m.

2. Calculate the total distance: • The question asks for the distance from Mr. Abioye to his image. • This distance is the sum of the distance from Mr. Abioye to the mirror plus the distance from the mirror to the image. • Total distance = $u + v$ • Total distance = 4.7 m + 4.7 m • Total distance = 9.4 m

Conclusion

The image is located 9.4 meters away from Mr. Abioye.

Exam Tip

Always remember that in plane mirror problems, the "total distance" is usually double the distance between the object and the mirror. If the question asks for the distance between the object and the mirror, it is 4.7m; if it asks for the distance between the object and the image, it is 9.4m. Read the question carefully to see which one is being requested!