JAMB 2025 Mathematics · Question 33

Given the progression 3, 5, 7, 9,.... . . . find an expression for the (n - 2)th^{th} term of the progression.

Options

  1. A.2n−12n - 1
  2. B.2n+12n + 1
  3. C.2n+32n + 3
  4. D.2n−32n - 3

Answer: D. 2n−32n - 3

Explanation written with AI and checked against the answer key

1. Analyze the question

We are given an arithmetic progression (AP): 3, 5, 7, 9, ... and we need to find an expression for the (n−2)th(n - 2)^{th} term.

2. Explain the concept

In an arithmetic progression, the nthn^{th} term (TnT_n) is calculated using the formula:

Tn=a+(n−1)dT_n = a + (n - 1)d

Where:

  • aa is the first term.
  • dd is the common difference.
  • nn is the position of the term.

For this sequence:

  • a=3a = 3
  • d=5−3=2d = 5 - 3 = 2
3. Show the solution

First, let's find the general formula for the nthn^{th} term of this specific sequence:

Tn=3+(n−1)2T_n = 3 + (n - 1)2
Tn=3+2n−2T_n = 3 + 2n - 2
Tn=2n+1T_n = 2n + 1

Now, the question asks for the (n−2)th(n - 2)^{th} term. To find this, we substitute (n−2)(n - 2) into the position variable of our general formula:

T(n−2)=2(n−2)+1T_{(n-2)} = 2(n - 2) + 1

Expand the brackets:

T(n−2)=2n−4+1T_{(n-2)} = 2n - 4 + 1

Simplify the expression:

T(n−2)=2n−3T_{(n-2)} = 2n - 3
4. Identify the answer

Comparing our result (2n−32n - 3) with the given options, it matches option D.

5. Exam Tip

When asked for a term like (n−k)th(n - k)^{th}, don't panic! Simply find the general nthn^{th} term formula first, then replace every 'nn' in that formula with the expression (n−k)(n - k). Always remember to use brackets when substituting to avoid sign errors during expansion.

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