JAMB 2024 Mathematics · Question 48

Calculate the standard deviation of the following scores 5, 4, 6, 7, and 8

Options

  1. A.2\sqrt{2}
  2. B.3\sqrt{3}
  3. C.2
  4. D.3

Answer: A. 2\sqrt{2}

Explanation written with AI and checked against the answer key

To calculate the standard deviation of a set of numbers, we follow a systematic process.

1. Analyze the question

We are given the dataset: 5, 4, 6, 7, 8. We need to find the standard deviation, which measures how spread out the numbers are from the mean.

2. Explain the concept

The formula for standard deviation (σ\sigma) is:

σ=∑(x−xˉ)2n\sigma = \sqrt{\frac{\sum(x - \bar{x})^2}{n}}

Where:

  • xx = each individual score
  • xˉ\bar{x} = the mean (average) of the scores
  • nn = the number of scores
  • ∑\sum = the sum of the values
3. Show the solution

Step 1: Find the mean (xˉ\bar{x})

xˉ=5+4+6+7+85=305=6\bar{x} = \frac{5 + 4 + 6 + 7 + 8}{5} = \frac{30}{5} = 6

Step 2: Subtract the mean from each score and square the result (x−xˉ)2(x - \bar{x})^2

  • (5−6)2=(−1)2=1(5 - 6)^2 = (-1)^2 = 1
  • (4−6)2=(−2)2=4(4 - 6)^2 = (-2)^2 = 4
  • (6−6)2=(0)2=0(6 - 6)^2 = (0)^2 = 0
  • (7−6)2=(1)2=1(7 - 6)^2 = (1)^2 = 1
  • (8−6)2=(2)2=4(8 - 6)^2 = (2)^2 = 4

Step 3: Find the sum of these squares

1+4+0+1+4=101 + 4 + 0 + 1 + 4 = 10

Step 4: Divide by the number of scores (n=5n=5)

Variance=105=2\text{Variance} = \frac{10}{5} = 2

Step 5: Take the square root to find the standard deviation

σ=2\sigma = \sqrt{2}
4. Identify the answer

Comparing our result to the given options, the correct choice is A.

5. Exam Tip

When calculating standard deviation, always remember that Variance = (Standard Deviation)². If you find the variance first, simply take the square root at the very end. Also, if your calculated mean is a whole number, the subtraction step becomes much faster and less prone to errors!

AI can make mistakes. Report anything that looks wrong.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.