JAMB 2023 Mathematics · Question 64

A student pilot was required to fly to an airport and then return as part of his flight training. The average…

Question

A student pilot was required to fly to an airport and then return as part of his flight training. The average speed to the airport was 120 km/h, and the average speed returning was 150 km/h. If the total flight time was 3 hours, calculate the distance between the two airports.

  1. A.270 km
  2. B.200 km
  3. C.360 km
  4. D.450 km

Answer: B. 200 km

Explanation written with AI and checked against the answer key

1. Analyze the Question

We are given:

  • Speed to the airport (v1v_1) = 120 km/h120\text{ km/h}
  • Speed returning (v2v_2) = 150 km/h150\text{ km/h}
  • Total time (TT) = 3 hours3\text{ hours}
  • Distance (dd) is the same for both legs of the trip.

We need to find the distance dd.

2. Explain the Concept

The fundamental formula for motion is:

Time=DistanceSpeed\text{Time} = \frac{\text{Distance}}{\text{Speed}}

Since the total time is the sum of the time taken to go (t1t_1) and the time taken to return (t2t_2), we can write:

t1+t2=Tt_1 + t_2 = T
dv1+dv2=T\frac{d}{v_1} + \frac{d}{v_2} = T
3. Show the Solution

Substitute the given values into the equation:

d120+d150=3\frac{d}{120} + \frac{d}{150} = 3

To solve for dd, find the Least Common Multiple (LCM) of 120 and 150, which is 600. Multiply every term by 600 to clear the fractions:

600(d120)+600(d150)=600(3)600 \left( \frac{d}{120} \right) + 600 \left( \frac{d}{150} \right) = 600(3)

Simplify:

5d+4d=18005d + 4d = 1800
9d=18009d = 1800

Divide both sides by 9:

d=18009d = \frac{1800}{9}
d=200 kmd = 200\text{ km}
4. Identify the Answer

The distance between the two airports is 200 km. This corresponds to option B.

5. Exam Tip

When you have a round trip with two different speeds (v1v_1 and v2v_2) and a total time (TT), you can use the shortcut formula:

d=v1×v2v1+v2×Td = \frac{v_1 \times v_2}{v_1 + v_2} \times T

Plugging in our values:

d=120×150120+150×3=18000270×3=1800090=200 kmd = \frac{120 \times 150}{120 + 150} \times 3 = \frac{18000}{270} \times 3 = \frac{18000}{90} = 200\text{ km}

This formula is a great time-saver for JAMB!

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