JAMB 2022 Mathematics · Question 21

Let (*) be a binary operation on a natural number defined by a * b = a - b + (ab)2^2, then find 3 * 5

Options

  1. A.223
  2. B.232
  3. C.32
  4. D.-232

Answer: A. 223

Explanation written with AI and checked against the answer key

Analysis

The question asks us to evaluate a binary operation defined as a∗b=a−b+(ab)2a * b = a - b + (ab)^2 for the specific values a=3a = 3 and b=5b = 5.

Concept

A binary operation is simply a rule that combines two elements of a set to produce a third element. In this case, the rule is:

  1. Subtract the second number from the first (a−ba - b).
  2. Multiply the two numbers together (abab).
  3. Square the result of that multiplication ((ab)2(ab)^2).
  4. Add the results of step 1 and step 3 together.
Step-by-Step Solution

Step 1: Identify the variables Given a∗b=a−b+(ab)2a * b = a - b + (ab)^2 We are to find 3∗53 * 5, so: a=3a = 3 b=5b = 5

Step 2: Substitute the values into the formula 3∗5=3−5+(3×5)23 * 5 = 3 - 5 + (3 \times 5)^2

Step 3: Solve the expression inside the parentheses 3×5=153 \times 5 = 15

Step 4: Square the result 152=15×15=22515^2 = 15 \times 15 = 225

Step 5: Complete the calculation 3−5+2253 - 5 + 225 −2+225=223-2 + 225 = 223

Conclusion

Following the defined operation, 3∗53 * 5 equals 223223. This matches option A.

Exam Tip

When dealing with binary operations in JAMB, always pay close attention to the order of the variables. If the operation were not commutative (meaning a∗ba * b is not the same as b∗ab * a), swapping the numbers would give you a completely different answer. Always substitute carefully!

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