JAMB 2022 Mathematics · Question 15

Integrate (2x+1)3^3

Options

  1. A.2x+138\frac{{2x+1}^3}{8} + C
  2. B.2x+148\frac{{2x+1}^4}{8} + C
  3. C.2x+144\frac{{2x+1}^4}{4} + C
  4. D.2x+126\frac{{2x+1}^2}{6} + C

Answer: B. 2x+148\frac{{2x+1}^4}{8} + C

Explanation written with AI and checked against the answer key

To solve the integral of (2x+1)3(2x + 1)^3 with respect to xx, we use the method of Integration by Substitution (or the reverse chain rule).

1. Analyze the question

We are asked to find the indefinite integral:

∫(2x+1)3 dx\int (2x + 1)^3 \, dx
2. Explain the concept

When integrating a function of the form (ax+b)n(ax + b)^n, where aa and bb are constants, we use the rule:

∫(ax+b)n dx=(ax+b)n+1a(n+1)+C\int (ax + b)^n \, dx = \frac{(ax + b)^{n+1}}{a(n+1)} + C

This rule works because we increase the power by 1 and then divide by the new power, while also dividing by the derivative of the inner function (2x+1)(2x + 1), which is 22.

3. Show the solution
  • Step 1: Identify the components. Here, n=3n = 3 and the derivative of the inner function (2x+1)(2x + 1) is 22.
  • Step 2: Apply the power rule for integration. Increase the exponent by 1: $(2x+1)3+1=(2x+1)4(2x + 1)^{3+1} = (2x + 1)^4$
  • Step 3: Divide by the new exponent (44) and multiply by the derivative of the inner function (22): $Result=(2x+1)44×2+C\text{Result} = \frac{(2x + 1)^4}{4 \times 2} + C$
  • Step 4: Simplify the denominator: $Result=(2x+1)48+C\text{Result} = \frac{(2x + 1)^4}{8} + C$
4. Identify the answer

Comparing our result to the given options, we find that it matches option B.

5. Exam Tip

Whenever you see a linear expression inside a power (like ax+bax+b), don't forget to divide by the coefficient of xx (the aa value). Many students forget this step and choose the wrong answer. You can always check your answer by differentiating it—if you differentiate (2x+1)48+C\frac{(2x+1)^4}{8} + C, you will get back to (2x+1)3(2x+1)^3 using the chain rule!

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