JAMB 2021 Mathematics · Question 4
Simplify +
Options
- A.4
- B.
- C.3
- D.
Answer: A. 4
Explanation written with AI and checked against the answer key
Analyze the question: We need to simplify √27 + 3/√3 and match it to an option.
Concept: Simplify each term to a multiple of √3 by:
- Pulling out perfect squares from under the root.
- Rationalising the denominator (multiply top and bottom by the root).
Solution:
Step 1: Simplify √27 √27 = √(9 × 3) = 3√3
Step 2: Simplify 3/√3 3/√3 = (3 × √3)/(√3 × √3) = 3√3/3 = √3
Step 3: Add the results 3√3 + √3 = 4√3
Answer: The result is 4√3, which is option A.
Tip: When you see surds like √27, √12, or √48, always break them into (perfect square × another number) first. Once all the surds share the same root, such as √3, you can add or subtract them just like "like terms" in algebra (3x + x = 4x).
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