JAMB 2021 Mathematics · Question 10

If the binary operation ∗\ast is defined by m ∗\ast n = mn + m + n for any real number m and n, find the identity of the elements under this operation

Options

  1. A.e = 1
  2. B.e = -1
  3. C.e = -2
  4. D.e = 0

Answer: D. e = 0

Explanation written with AI and checked against the answer key

Analysis

To find the identity element (ee) of a binary operation, we use the fundamental property: m∗e=mm \ast e = m (or e∗m=me \ast m = m) This means that when you perform the operation between any element mm and the identity ee, the result must be the element mm itself.

Concept

The identity element is the "neutral" element of an operation. Just as 00 is the identity for addition (m+0=mm + 0 = m) and 11 is the identity for multiplication (m×1=mm \times 1 = m), we need to find the value of ee that satisfies the given rule: m∗n=mn+m+nm \ast n = mn + m + n

Step-by-Step Solution
  1. Set up the equation: Using the definition m∗e=mm \ast e = m, substitute ee for nn in the given formula: m∗e=me+m+em \ast e = me + m + e
  1. Equate to mm: Since m∗em \ast e must equal mm: me+m+e=mme + m + e = m
  1. Solve for ee: Subtract mm from both sides of the equation: me+e=0me + e = 0
  1. Factor out ee: e(m+1)=0e(m + 1) = 0
  1. Determine the value of ee: For this equation to hold true for any real number mm, the term (m+1)(m + 1) cannot be zero (unless m=−1m = -1). Therefore, the only way for the product to be zero for all mm is if e=0e = 0.
Verification

Let's check if e=0e = 0 works: m∗0=(m×0)+m+0m \ast 0 = (m \times 0) + m + 0 m∗0=0+m+0m \ast 0 = 0 + m + 0 m∗0=mm \ast 0 = m Since the result is mm, e=0e = 0 is indeed the identity element.

Conclusion

The correct option is D.

Exam Tip: Whenever you are asked to find the identity element, always remember the rule a∗e=aa \ast e = a. If you are asked for the inverse element later, remember that a∗a−1=ea \ast a^{-1} = e (where ee is the identity you just found).

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