JAMB 2021 Mathematics · Question 7

Find the probability that a number selected at random from 41 to 56 is a multiple of 9

Options

  1. A.18\frac{1}{8}
  2. B.215\frac{2}{15}
  3. C.316\frac{3}{16}
  4. D.78\frac{7}{8}

Answer: A. 18\frac{1}{8}

Explanation written with AI and checked against the answer key

1. Analyze the Question

We need to find the probability of picking a multiple of 9 from the set of integers ranging from 41 to 56 (inclusive).

2. Explain the Concept

Probability is defined as:

Probability=Number of favorable outcomesTotal number of possible outcomes\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}
  • Total outcomes: The count of numbers from 41 to 56.
  • Favorable outcomes: The count of numbers in that range that are divisible by 9.
3. Show the Solution

Step 1: Find the total number of outcomes. To find the number of integers in an inclusive range [a,b][a, b], use the formula: (b−a)+1(b - a) + 1.

Total=(56−41)+1\text{Total} = (56 - 41) + 1
Total=15+1=16\text{Total} = 15 + 1 = 16

Step 2: Identify the multiples of 9 within the range 41 to 56. Let's list the multiples of 9:

  • 9×4=369 \times 4 = 36 (Too small)
  • 9×5=459 \times 5 = 45 (Within range)
  • 9×6=549 \times 6 = 54 (Within range)
  • 9×7=639 \times 7 = 63 (Too large)

The multiples of 9 in the range are 45 and 54. There are 2 favorable outcomes.

Step 3: Calculate the probability.

Probability=216\text{Probability} = \frac{2}{16}

Simplify the fraction by dividing both the numerator and the denominator by 2:

Probability=18\text{Probability} = \frac{1}{8}
4. Identify the Answer

Comparing our result to the options provided, the correct choice is A.

5. Exam Tip

When counting numbers in an inclusive range (e.g., "from X to Y"), students often forget to add the "+1". Always remember: if you are counting from 1 to 3, there are 3 numbers (1, 2, 3). If you just did 3−13 - 1, you would get 2, which is incorrect. Adding the 1 ensures you include both endpoints!

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