JAMB 2020 Mathematics · Question 36

If log10_{10}2 = 0.3010 and log10_{10}3 = 0.4771, eventually without using the logarithm tables, log10_{10}4.5

Options

  1. A.0.3010
  2. B.0.4771
  3. C.0.6532
  4. D.0.9542

Answer: C. 0.6532

Explanation written with AI and checked against the answer key

1. Analyze the question

We are given the values of log⁡102\log_{10}2 and log⁡103\log_{10}3. We need to find the value of log⁡104.5\log_{10}4.5 by expressing 4.54.5 in terms of 22 and 33.

2. Explain the concept

To solve this, we use the laws of logarithms:

  • Quotient Rule: log⁡b(xy)=log⁡bx−log⁡by\log_b(\frac{x}{y}) = \log_b x - \log_b y
  • Product Rule: log⁡b(xy)=log⁡bx+log⁡by\log_b(xy) = \log_b x + \log_b y
  • Power Rule: log⁡b(xn)=nlog⁡bx\log_b(x^n) = n \log_b x

First, convert the decimal 4.54.5 into a fraction: 4.5=4510=924.5 = \frac{45}{10} = \frac{9}{2}

3. Show the solution

Step 1: Express log⁡104.5\log_{10}4.5 using the quotient rule.

log⁡104.5=log⁡10(92)\log_{10}4.5 = \log_{10}\left(\frac{9}{2}\right)
log⁡104.5=log⁡109−log⁡102\log_{10}4.5 = \log_{10}9 - \log_{10}2

Step 2: Express 99 as a power of 33. Since 9=329 = 3^2, we have:

log⁡109=log⁡10(32)=2log⁡103\log_{10}9 = \log_{10}(3^2) = 2 \log_{10}3

Step 3: Substitute the known values into the equation.

log⁡104.5=2(log⁡103)−log⁡102\log_{10}4.5 = 2(\log_{10}3) - \log_{10}2
log⁡104.5=2(0.4771)−0.3010\log_{10}4.5 = 2(0.4771) - 0.3010

Step 4: Perform the arithmetic.

2×0.4771=0.95422 \times 0.4771 = 0.9542
0.9542−0.3010=0.65320.9542 - 0.3010 = 0.6532
4. Identify the answer

Comparing our result to the given options: A. 0.3010 B. 0.4771 C. 0.6532 D. 0.9542

The correct option is C.

5. Tip

Whenever you see a decimal in a logarithm question (like 4.5 or 0.75), always convert it to a fraction first. It makes it much easier to break the number down into the prime factors (2, 3, 5, etc.) provided in the question!

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