JAMB 2018 Mathematics · Question 39

Solve for t in the equation 34\frac{3}{4}t + 13\frac{1}{3}(21 - t) = 11

Options

  1. A.913\frac{9}{13}
  2. B.713\frac{7}{13}
  3. C.5
  4. D.935\frac{3}{5}

Answer: D. 935\frac{3}{5}

Explanation written with AI and checked against the answer key

Analysis

To solve for tt in the equation 34t+13(21−t)=11\frac{3}{4}t + \frac{1}{3}(21 - t) = 11, we need to clear the fractions, expand the brackets, and isolate the variable tt.

Concept

When dealing with equations involving fractions, the easiest way to simplify them is to find the Least Common Multiple (LCM) of the denominators and multiply every term in the equation by that value. This eliminates the fractions and makes the equation much easier to solve.

Step-by-Step Solution

Step 1: Identify the LCM The denominators are 4 and 3. The LCM of 4 and 3 is 12.

Step 2: Multiply every term by 12 12×(34t)+12×(13(21−t))=12×1112 \times (\frac{3}{4}t) + 12 \times (\frac{1}{3}(21 - t)) = 12 \times 11

Step 3: Simplify the terms

  • 12÷4=312 \div 4 = 3, so 3×3t=9t3 \times 3t = 9t
  • 12÷3=412 \div 3 = 4, so 4×(21−t)=84−4t4 \times (21 - t) = 84 - 4t
  • 12×11=13212 \times 11 = 132

Now the equation looks like this: 9t+84−4t=1329t + 84 - 4t = 132

Step 4: Combine like terms 9t−4t+84=1329t - 4t + 84 = 132 5t+84=1325t + 84 = 132

Step 5: Isolate tt Subtract 84 from both sides: 5t=132−845t = 132 - 84 5t=485t = 48

Divide by 5: t=485t = \frac{48}{5}

Step 6: Convert to a mixed fraction 48÷5=948 \div 5 = 9 remainder 33. So, t=935t = 9\frac{3}{5}

Conclusion

Comparing our result to the given options, we find that 9359\frac{3}{5} matches option D.

Exam Tip

When you have an equation with fractions, don't be tempted to work with decimals unless necessary. Clearing the fraction by multiplying by the LCM is a "golden rule" in JAMB Mathematics—it prevents errors that often occur when adding or subtracting fractions with different denominators.

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