JAMB 2018 Mathematics · Question 10

In how many ways can the letters LEADER be arranged?

Options

  1. A.72
  2. B.144
  3. C.360
  4. D.720

Answer: C. 360

Explanation written with AI and checked against the answer key

Analysis

The question asks for the number of ways to arrange the letters in the word LEADER. This is a problem of permutations of objects where some are identical.

Concept

When arranging nn objects where some objects are repeated, we use the formula:

Number of arrangements=n!n1!×n2!×⋯×nk!\text{Number of arrangements} = \frac{n!}{n_1! \times n_2! \times \dots \times n_k!}

Where:

  • nn is the total number of letters.
  • n1,n2,…n_1, n_2, \dots are the frequencies of the repeated letters.
Step-by-Step Solution
  1. Count the total number of letters (nn): The word LEADER has 6 letters. So, n=6n = 6.
  1. Identify the frequency of each letter: • L: 1 • E: 2 (appears twice) • A: 1 • D: 1 • R: 1
  1. Apply the formula: Since the letter 'E' repeats 2 times, we divide the total permutations (6!6!) by the factorial of the number of repetitions (2!2!): $Arrangements=6!2!\text{Arrangements} = \frac{6!}{2!}$
  1. Calculate the values: • 6!=6×5×4×3×2×1=7206! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720 • 2!=2×1=22! = 2 \times 1 = 2
Arrangements=7202=360\text{Arrangements} = \frac{720}{2} = 360
Conclusion

The total number of ways to arrange the letters is 360.

Exam Tip

Always count the total letters first, then immediately look for repeats. A common mistake is to forget to divide by the factorial of the repeated letters. If you see a word with repeated letters, remember: "Total factorial divided by the factorial of the repeats."

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