JAMB 2018 Mathematics · Question 33
From a point R, 300m north of P, a man walks eastwards to a place; Q which is 600m from P. Find the bearing of P from Q correct to the nearest degree
Options
- A.026
- B.045
- C.210
- D.240
Answer: D. 240
Explanation written with AI and checked against the answer key
1. Analyze the question
We are given two points, P and R. Point R is 300m North of P. A man walks East from R to a point Q, such that the distance from P to Q is 600m. We need to find the bearing of P from Q.
2. Explain the concept
- Geometry: We have a right-angled triangle , where (because R is North of P and Q is East of R).
- Trigonometry: In a right-angled triangle, we can use SOH-CAH-TOA.
- Bearing: The bearing of P from Q is the angle measured clockwise from the North line at Q to the line QP.
3. Show the solution
Step 1: Visualize the triangle
- (Vertical side)
- (Hypotenuse)
- is the angle at P inside the triangle.
Using trigonometry in :
Step 2: Determine the bearing
- At point Q, draw a North line. Since Q is East of R, the line RQ is horizontal (West-East).
- The angle of the line QP relative to the South line at Q is equal to the alternate angle .
- The bearing is measured clockwise from the North line at Q.
- The angle from North to South is .
- The bearing of P from Q is .
- Since the angle between the vertical (South) and QP is , the bearing is .
4. Identify the answer
The calculated bearing is . Looking at the options provided: A. B. C. D.
The correct option is D.
5. Tip
When dealing with bearing questions, always draw a neat sketch. Remember that "North" is always , "East" is , "South" is , and "West" is . Using alternate angles (the "Z" rule) is the fastest way to transfer angles between your North lines!
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