JAMB 2018 Mathematics · Question 24

Find the equation of the line through (5,7) parallel to the line 7x + 5y = 12

Options

  1. A.5x + 7y = 20
  2. B.7x + 5y = 70
  3. C.xy = 7
  4. D.15x + 17y = 90

Answer: B. 7x + 5y = 70

Explanation written with AI and checked against the answer key

Analysis

To find the equation of a line parallel to a given line, we must understand that parallel lines have the same slope (gradient). We are given a point (5,7)(5, 7) and the equation of a reference line 7x+5y=127x + 5y = 12.

Concept
  1. Slope-Intercept Form: The equation of a line is often written as y=mx+cy = mx + c, where mm is the slope.
  2. Parallel Lines: If two lines are parallel, their slopes are equal (m1=m2m_1 = m_2).
  3. Point-Slope Form: Once we have the slope and a point (x1,y1)(x_1, y_1), we can use the formula: y−y1=m(x−x1)y - y_1 = m(x - x_1)
Step-by-Step Solution

Step 1: Find the slope of the given line. The given equation is 7x+5y=127x + 5y = 12. Let's rewrite this in the form y=mx+cy = mx + c: 5y=−7x+125y = -7x + 12 y=−75x+125y = -\frac{7}{5}x + \frac{12}{5} The slope (mm) of this line is −75-\frac{7}{5}. Since our new line is parallel, its slope must also be −75-\frac{7}{5}.

Step 2: Use the point-slope formula. Using the point (5,7)(5, 7) and the slope m=−75m = -\frac{7}{5}: y−7=−75(x−5)y - 7 = -\frac{7}{5}(x - 5)

Step 3: Simplify the equation. Multiply both sides by 5 to clear the fraction: 5(y−7)=−7(x−5)5(y - 7) = -7(x - 5) 5y−35=−7x+355y - 35 = -7x + 35

Step 4: Rearrange into the standard form (Ax+By=CAx + By = C). Add 7x7x to both sides and add 3535 to both sides: 7x+5y=35+357x + 5y = 35 + 35 7x+5y=707x + 5y = 70

Conclusion

Comparing our result 7x+5y=707x + 5y = 70 with the given options, it matches option B.

Exam Tip: Whenever you see "parallel to," immediately look at the coefficients of xx and yy in the original equation. A parallel line will always have the same Ax+ByAx + By part; you only need to find the new constant (CC) by plugging in your given coordinates!

AI can make mistakes. Report anything that looks wrong.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.