JAMB 2018 Mathematics · Question 52

An arc of a circle of radius 14cm subtends angle 300° at the centre. Find the perimeter of the sector formed by the arc (take π = 227\frac{22}{7})

Options

  1. A.14.67cm
  2. B.73.33 cm
  3. C.101.33cm
  4. D.513.33cm

Answer: C. 101.33cm

Explanation written with AI and checked against the answer key

Analysis

To find the perimeter of a sector, we need to calculate the sum of the length of the arc and the two radii that enclose the sector.

Concept
  1. Arc Length Formula: The length of an arc (LL) is given by: L=θ360×2πrL = \frac{\theta}{360} \times 2\pi r where θ\theta is the angle subtended at the center and rr is the radius.
  2. Perimeter of a Sector: The perimeter (PP) is the sum of the arc length and the two radii: P=L+2rP = L + 2r
Step-by-Step Solution

Step 1: Identify the given values

  • Radius (rr) = 14 cm
  • Angle (θ\theta) = 300°
  • π=227\pi = \frac{22}{7}

Step 2: Calculate the Arc Length (LL) L=300360×2×227×14L = \frac{300}{360} \times 2 \times \frac{22}{7} \times 14

Simplify the fraction 300360\frac{300}{360}: 300360=3036=56\frac{300}{360} = \frac{30}{36} = \frac{5}{6}

Now, calculate LL: L=56×2×227×14L = \frac{5}{6} \times 2 \times \frac{22}{7} \times 14 L=56×2×22×2L = \frac{5}{6} \times 2 \times 22 \times 2 (since 14÷7=214 \div 7 = 2) L=5×886=4406L = \frac{5 \times 88}{6} = \frac{440}{6} L≈73.33 cmL \approx 73.33 \text{ cm}

Step 3: Calculate the Perimeter (PP) The perimeter of the sector is the arc length plus the two radii forming the sector: P=L+r+rP = L + r + r P=73.33+14+14P = 73.33 + 14 + 14 P=73.33+28P = 73.33 + 28 P=101.33 cmP = 101.33 \text{ cm}

Conclusion

Comparing our result with the given options, we find that 101.33 cm matches option C.

Exam Tip

Always remember that a "sector" is like a slice of pizza. The perimeter includes not just the curved crust (the arc), but also the two straight sides (the radii). Students often forget to add the two radii and mistakenly choose the arc length alone!

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