JAMB 2017 Mathematics · Question 9

Make S the subject of the relation p = s + sm2nr\frac{sm^2}{nr}

Options

  1. A.s = nrpnr+m2\frac{nrp}{nr + m^2}
  2. B.s = nr + m2mrp\frac{m^2}{mrp}
  3. C.s = nrpmr\frac{nrp}{mr} + m2
  4. D.s = nrpnr\frac{nrp}{nr} + m2

Answer: A. s = nrpnr+m2\frac{nrp}{nr + m^2}

Explanation written with AI and checked against the answer key

Analysis

The goal is to isolate the variable s in the given equation: p=s+sm2nrp = s + \frac{sm^2}{nr}

Concept

To make a variable the subject of a formula, we need to group all terms containing that variable on one side of the equation and factor it out. If the variable appears in a fraction, we must find a common denominator or multiply through to clear the fraction.

Step-by-Step Solution

Step 1: Identify the terms with 's' The equation is p=s+sm2nrp = s + \frac{sm^2}{nr}. Both terms on the right side contain ss.

Step 2: Factor out 's' Since ss is common to both terms, we can factor it out: p=s(1+m2nr)p = s(1 + \frac{m^2}{nr})

Step 3: Simplify the expression inside the bracket To add 11 and m2nr\frac{m^2}{nr}, find a common denominator, which is nrnr: 1+m2nr=nrnr+m2nr=nr+m2nr1 + \frac{m^2}{nr} = \frac{nr}{nr} + \frac{m^2}{nr} = \frac{nr + m^2}{nr}

Now substitute this back into the equation: p=s(nr+m2nr)p = s \left( \frac{nr + m^2}{nr} \right)

Step 4: Solve for 's' To isolate ss, multiply both sides by the reciprocal of the fraction (nr+m2nr)\left( \frac{nr + m^2}{nr} \right), which is (nrnr+m2)\left( \frac{nr}{nr + m^2} \right): s=p×(nrnr+m2)s = p \times \left( \frac{nr}{nr + m^2} \right)

s=nrpnr+m2s = \frac{nrp}{nr + m^2}

Conclusion

Comparing our result to the given options, we find that it matches option A.

Exam Tip: When you see a variable appearing in multiple terms, always look to factor it out immediately. If you are ever unsure about your algebraic manipulation, try picking simple numbers for p,n,r,p, n, r, and mm, calculate ss, and plug those values into the options to see which one gives you the same ss value!

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