JAMB 2017 Mathematics · Question 40

Find ∫(x2 + 3x − 5)dx

Options

  1. A.x33\frac{x_3}{3} - 3x22\frac{3x_2}{2} - 5x + k
  2. B.x33\frac{x_3}{3} - 3x22\frac{3x_2}{2} + 5x + k
  3. C.x33\frac{x_3}{3} + 3x22\frac{3x_2}{2} - 5x + k
  4. D.x33\frac{x_3}{3} + 3x22\frac{3x_2}{2} + 5x + k

Answer: C. x33\frac{x_3}{3} + 3x22\frac{3x_2}{2} - 5x + k

Explanation written with AI and checked against the answer key

To solve the indefinite integral ∫(x2+3x−5) dx\int (x^2 + 3x - 5) \, dx, we apply the Power Rule for Integration.

1. The Concept

The Power Rule states that for any term axnax^n:

∫axn dx=axn+1n+1+C\int ax^n \, dx = \frac{ax^{n+1}}{n+1} + C

(Where CC or kk is the constant of integration).

When integrating a polynomial, we integrate each term individually.

2. Step-by-Step Solution

We integrate each part of the expression (x2+3x−5)(x^2 + 3x - 5) separately:

  • For x2x^2: Increase the power by 1 (2+1=32+1=3) and divide by the new power: $∫x2 dx=x33\int x^2 \, dx = \frac{x^3}{3}$
  • For 3x3x: The power of xx is 1. Increase it by 1 (1+1=21+1=2) and divide by the new power: $∫3x1 dx=3x22\int 3x^1 \, dx = \frac{3x^2}{2}$
  • For −5-5: A constant aa integrates to axax. So, −5-5 becomes −5x-5x: $∫−5 dx=−5x\int -5 \, dx = -5x$
  • Adding the constant: Since this is an indefinite integral, we add the constant of integration, kk.
3. Combining the results

Putting it all together:

x33+3x22−5x+k\frac{x^3}{3} + \frac{3x^2}{2} - 5x + k

Comparing this result to your options, it matches option C.

Exam Tip

Always remember that integration is the reverse of differentiation. If you are ever unsure of your answer during an exam, quickly differentiate your result. If you differentiate x33+3x22−5x+k\frac{x^3}{3} + \frac{3x^2}{2} - 5x + k, you will get back to the original expression (x2+3x−5)(x^2 + 3x - 5), confirming your answer is correct!

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