JAMB 2017 Mathematics · Question 34

A cylindrical tank has a capacity of 3080m3. What is the depth of the tank if the diameter of its base is 14m? Take pi = 22/7.

Options

  1. A.23m
  2. B.25m
  3. C.20m
  4. D.22m

Answer: C. 20m

Explanation written with AI and checked against the answer key

1. Analyze the Question

We are given the volume (capacity) of a cylindrical tank and the diameter of its base. We need to find the depth (height) of the tank.

  • Volume (VV): 3080 m33080 \, \text{m}^3
  • Diameter (dd): 14 m14 \, \text{m}
  • π\pi: 22/722/7
  • Find: Height (hh)
2. Explain the Concept

A cylinder's volume is calculated using the formula:

V=πr2hV = \pi r^2 h

Where:

  • rr is the radius of the base.
  • hh is the height (or depth) of the cylinder.

Since we are given the diameter, we must first find the radius. Remember that the radius is half of the diameter (r=d/2r = d / 2).

3. Show the Solution

Step 1: Find the radius (rr)

r=d2=142=7 mr = \frac{d}{2} = \frac{14}{2} = 7 \, \text{m}

Step 2: Substitute the known values into the volume formula

3080=(227)×(7)2×h3080 = \left(\frac{22}{7}\right) \times (7)^2 \times h

Step 3: Simplify the equation

3080=(227)×49×h3080 = \left(\frac{22}{7}\right) \times 49 \times h

Divide 49 by 7:

3080=22×7×h3080 = 22 \times 7 \times h
3080=154×h3080 = 154 \times h

Step 4: Solve for hh

h=3080154h = \frac{3080}{154}
h=20 mh = 20 \, \text{m}
4. Identify the Answer

Comparing our result to the given options, the correct answer is 20m, which corresponds to option C.

5. Exam Tip

When dealing with geometry problems involving π=22/7\pi = 22/7, always look for ways to cancel out the denominator early. Notice how the 77 in the denominator canceled out perfectly with the 727^2 (which is 7×77 \times 7), making the multiplication much easier and faster for your JAMB exam!

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