JAMB 2016 Mathematics · Question 37

Integrate 2x3+2xx\frac{2x^3 + 2x}{x} with respect to x

Options

  1. A.2x33\frac{2x^3}{3} - 2x + k
  2. B.x3 + 2x + k
  3. C.2x33\frac{2x^3}{3} + 2x + k
  4. D.x3 - 2x + k

Answer: C. 2x33\frac{2x^3}{3} + 2x + k

Explanation written with AI and checked against the answer key

Analysis

The question asks us to find the indefinite integral of the function 2x3+2xx\frac{2x^3 + 2x}{x} with respect to xx. Before we can integrate, we must simplify the algebraic expression to make it easier to handle.

Concept: Integration of Algebraic Functions

To integrate a polynomial, we use the Power Rule for Integration:

∫xn dx=xn+1n+1+k\int x^n \, dx = \frac{x^{n+1}}{n+1} + k

where kk is the constant of integration.

Step-by-Step Solution

Step 1: Simplify the expression Divide each term in the numerator by the denominator (xx):

2x3+2xx=2x3x+2xx\frac{2x^3 + 2x}{x} = \frac{2x^3}{x} + \frac{2x}{x}
=2x2+2= 2x^2 + 2

Step 2: Set up the integral Now, integrate the simplified expression with respect to xx:

∫(2x2+2) dx\int (2x^2 + 2) \, dx

Step 3: Integrate term by term Apply the power rule to each term:

  • For 2x22x^2: ∫2x2 dx=2(x2+12+1)=2x33\int 2x^2 \, dx = 2 \left( \frac{x^{2+1}}{2+1} \right) = \frac{2x^3}{3}
  • For 22: ∫2 dx=2x\int 2 \, dx = 2x

Step 4: Combine and add the constant

2x33+2x+k\frac{2x^3}{3} + 2x + k
Conclusion

Comparing our result to the given options, we find that our solution matches option C.

Exam Tip

Whenever you see a fraction in an integration problem, always check if you can simplify it by dividing the numerator by the denominator first. It usually turns a complex-looking problem into a very simple one! Also, never forget to add the constant kk (or cc) at the end of every indefinite integral; examiners often penalize for missing it.

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