JAMB 2015 Mathematics · Question 9
Make x the subject of the equation s = 2 + (x + ⅗y)
Options
- A.x = 5[(s − 2) ÷ t] - 3/5y
- B.x = 25[(s − 2) ÷ t] − 3ty
- C.x = [1 ÷ (s − 2)3ty]
- D.x = [5(s − 2) 2 ÷ 3ty] × t
Answer: A. x = 5[(s − 2) ÷ t] - 3/5y
Explanation written with AI and checked against the answer key
Analyze the question: We need to rearrange s = 2 + (t/5)(x + 3y/5) so that x stands alone on one side.
Concept: Undo the operations in reverse order: subtract the constant, remove the fraction multiplying the bracket, then subtract the term that sits with x.
Solution:
- Start with: s = 2 + (t/5)(x + 3y/5)
- Subtract 2 from both sides: s − 2 = (t/5)(x + 3y/5)
- Multiply both sides by 5/t, which removes the factor t/5: 5(s − 2)/t = x + 3y/5
- Subtract 3y/5 from both sides: x = 5(s − 2)/t − 3y/5
Checking the options:
- A. x = 5[(s − 2) ÷ t] − 3/5 y. This is 5(s − 2)/t − 3y/5, which matches our result exactly.
- B. Has 25 and 3ty, which do not appear in our working.
- C and D. Have an incorrect structure and do not match.
Note on reading the question: The term "⅗y" means (3/5)·y. Option A's "3/5y" is read as (3/5)y, which is the same thing.
Exam tip: For "make x the subject" questions, work backwards. Move the terms that are furthest from x first (here the +2, then the multiplier t/5, then 3y/5). Always do the same operation to both sides, and check by substituting simple values if time allows.
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