JAMB 2015 Mathematics · Question 40
Find the equation of a line which is form origin and passes through the point (−3, −4)
Options
- A.y =
- B.y =
- C.y =
- D.y =
Answer: B. y =
Explanation written with AI and checked against the answer key
Analyze the question: The line starts from the origin (0, 0) and passes through (−3, −4). We need its equation.
Concept: A line through the origin has the form y = mx, where m is the gradient. The gradient between two points is
m = (y₂ − y₁)/(x₂ − x₁)
Solution:
- Use the points (0, 0) and (−3, −4):
m = (−4 − 0)/(−3 − 0) = (−4)/(−3) = 4/3
- Substitute into y = mx:
y = 4x/3
Check: Put x = −3 into y = 4x/3: y = 4(−3)/3 = −4 ✓. This matches the point (−3, −4).
The other options fail the check. For example, option A gives y = 3(−3)/4 = −9/4, which is not −4.
Tip: For a line through the origin, the equation is always y = (y/x)x using the given point. Just divide y by x to get the gradient. Here, −4 ÷ −3 = 4/3. Remember that two negatives make a positive.
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