JAMB 2015 Mathematics · Question 48
100112 + *****2 + 111002 + 1012 = 10011112
Options
- A.11112
- B.110112
- C.101112
- D.110012
Answer: B. 110112
Explanation written with AI and checked against the answer key
Analyze the question: The numbers are in base 2 (binary). The question reads 10011₂ + ?????₂ + 11100₂ + 101₂ = 1001111₂, and we need the missing binary number.
Concept: Convert to base 10, solve for the unknown, then convert back to binary (or work directly in binary).
Step 1: Convert the known numbers to base 10
- 10011₂ = 16 + 0 + 0 + 2 + 1 = 19
- 11100₂ = 16 + 8 + 4 = 28
- 101₂ = 4 + 0 + 1 = 5
- 1001111₂ = 64 + 0 + 0 + 8 + 4 + 2 + 1 = 79
Step 2: Find the missing number
19 + x + 28 + 5 = 79 52 + x = 79 x = 27
Step 3: Convert 27 to binary
27 = 16 + 8 + 0 + 2 + 1 = 11011₂
Step 4: Check the options
- A. 1111₂ = 15
- B. 11011₂ = 27 ✔
- C. 10111₂ = 23
- D. 11001₂ = 25
Verification: 19 + 27 + 28 + 5 = 79 ✔
Answer: B (11011₂)
Tip: In binary-addition questions with a missing number, convert everything to base 10, do the arithmetic, then convert back. Powers of 2 to memorise: 1, 2, 4, 8, 16, 32, 64, 128.
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