JAMB 2014 Mathematics · Question 45

If y = 4x3 - 2x2 + x, find δyδx\frac{\delta y}{\delta x}

Options

  1. A.8x2 - 2x + 1
  2. B.8x2 - 4x + 1
  3. C.12x2 - 2x + 1
  4. D.12x2 - 4x + 1

Answer: D. 12x2 - 4x + 1

Explanation written with AI and checked against the answer key

Analysis

The question asks for the derivative of the function y=4x3−2x2+xy = 4x^3 - 2x^2 + x with respect to xx. This is a standard calculus problem involving the power rule for differentiation.

Concept: The Power Rule

To differentiate a term of the form axnax^n, you use the Power Rule:

ddx(axn)=n⋅axn−1\frac{d}{dx}(ax^n) = n \cdot ax^{n-1}

In simple terms:

  1. Bring the exponent down to multiply with the coefficient.
  2. Subtract 1 from the original exponent.
  3. Remember that the derivative of xx (which is x1x^1) is 11, and the derivative of a constant is 00.
Step-by-Step Solution

Given the function:

y=4x3−2x2+x1y = 4x^3 - 2x^2 + x^1

Step 1: Differentiate 4x34x^3 Multiply the exponent (3) by the coefficient (4) and subtract 1 from the exponent:

3×4x3−1=12x23 \times 4x^{3-1} = 12x^2

Step 2: Differentiate −2x2-2x^2 Multiply the exponent (2) by the coefficient (-2) and subtract 1 from the exponent:

2×−2x2−1=−4x1=−4x2 \times -2x^{2-1} = -4x^1 = -4x

Step 3: Differentiate xx The derivative of xx is simply 1:

ddx(x)=1\frac{d}{dx}(x) = 1

Step 4: Combine the results

dydx=12x2−4x+1\frac{dy}{dx} = 12x^2 - 4x + 1
Conclusion

Comparing our result to the given options, we find that it matches option D.

Exam Tip

When differentiating polynomials, always check the signs carefully. A common mistake is to forget to subtract 1 from the exponent or to miscalculate the product of the exponent and the coefficient. Also, remember that the derivative of any constant (like 5 or 10) is always 0, but the derivative of xx is always 1.

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