JAMB 2014 Mathematics · Question 43

If log7.5 = 0.8751, evaluate 2 log75 + log750

Options

  1. A.6.6252
  2. B.6.6253
  3. C.66.252
  4. D.66.253

Answer: B. 6.6253

Explanation written with AI and checked against the answer key

1. Analyze the question

We are given that log⁡7.5=0.8751\log 7.5 = 0.8751. We need to evaluate the expression 2log⁡75+log⁡7502 \log 75 + \log 750 using the properties of logarithms.

2. Explain the concept

To solve this, we need to express 7575 and 750750 in terms of 7.57.5 using the laws of logarithms:

  • Product Rule: log⁡(a×b)=log⁡a+log⁡b\log(a \times b) = \log a + \log b
  • Power Rule: nlog⁡a=log⁡(an)n \log a = \log(a^n)
  • Base 10 property: log⁡(10)=1\log(10) = 1 and log⁡(100)=2\log(100) = 2

Since 75=7.5×1075 = 7.5 \times 10 and 750=7.5×100750 = 7.5 \times 100, we can rewrite the expression.

3. Show the solution

Step 1: Expand the terms using the product rule.

  • log⁡75=log⁡(7.5×10)=log⁡7.5+log⁡10\log 75 = \log(7.5 \times 10) = \log 7.5 + \log 10
  • log⁡750=log⁡(7.5×100)=log⁡7.5+log⁡100\log 750 = \log(7.5 \times 100) = \log 7.5 + \log 100

Step 2: Substitute these into the original expression. The expression is 2log⁡75+log⁡7502 \log 75 + \log 750. =2(log⁡7.5+log⁡10)+(log⁡7.5+log⁡100)= 2(\log 7.5 + \log 10) + (\log 7.5 + \log 100)

Step 3: Simplify using known values. We know log⁡10=1\log 10 = 1 and log⁡100=2\log 100 = 2. =2(log⁡7.5+1)+(log⁡7.5+2)= 2(\log 7.5 + 1) + (\log 7.5 + 2) =2log⁡7.5+2+log⁡7.5+2= 2 \log 7.5 + 2 + \log 7.5 + 2 =3log⁡7.5+4= 3 \log 7.5 + 4

Step 4: Calculate the final value. Substitute log⁡7.5=0.8751\log 7.5 = 0.8751: =3(0.8751)+4= 3(0.8751) + 4 =2.6253+4= 2.6253 + 4 =6.6253= 6.6253

4. Identify the answer

Comparing our result to the given options, we find that the correct choice is B.

5. Tip

When dealing with log problems involving decimals like 7.5,75,7507.5, 75, 750, always try to break them down into the given value multiplied by powers of 1010 (10,100,100010, 100, 1000). This makes the calculation much faster and avoids the need for a calculator!

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