JAMB 2013 Mathematics · Question 33

If y = (2x + 2)3^3, find δyδx\frac{\delta y}{\delta x}

Options

  1. A.3(2x +2)2
  2. B.6(2x +2)
  3. C.3(2x +2)
  4. D.6(2x +2)2

Answer: D. 6(2x +2)2

Explanation written with AI and checked against the answer key

To solve for the derivative of y=(2x+2)3y = (2x + 2)^3 with respect to xx, we use the Chain Rule in calculus.

1. Analyze the question

We are given a composite function y=u3y = u^3, where u=2x+2u = 2x + 2. We need to find dydx\frac{dy}{dx}.

2. Explain the concept

The Chain Rule states that if y=f(u)y = f(u) and u=g(x)u = g(x), then:

dydx=dydu×dudx\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}

In simpler terms, you differentiate the "outside" function while keeping the "inside" the same, and then multiply it by the derivative of the "inside" function.

3. Show the solution

Step 1: Identify the parts

  • Let u=2x+2u = 2x + 2
  • Then y=u3y = u^3

Step 2: Differentiate the parts

  • Differentiate yy with respect to uu: dydu=3u2\frac{dy}{du} = 3u^2
  • Differentiate uu with respect to xx: dudx=2\frac{du}{dx} = 2 (since the derivative of 2x2x is 22 and the derivative of 22 is 00)

Step 3: Apply the Chain Rule

dydx=3u2×2\frac{dy}{dx} = 3u^2 \times 2
dydx=6u2\frac{dy}{dx} = 6u^2

Step 4: Substitute uu back into the equation Since u=2x+2u = 2x + 2:

dydx=6(2x+2)2\frac{dy}{dx} = 6(2x + 2)^2
4. Identify the answer

Comparing our result to the given options: A. 3(2x + 2)² B. 6(2x + 2) C. 3(2x + 2) D. 6(2x + 2)²

The correct option is D.

5. Tip

When you see a function raised to a power, like (ax+b)n(ax + b)^n, always remember the "Power-Chain" shortcut: Bring the power down, subtract one from the power, and multiply by the derivative of the inside.

  • Bring down 3→3(2x+2)23 \rightarrow 3(2x + 2)^2
  • Multiply by derivative of (2x+2)(2x+2), which is 2→3×2(2x+2)2=6(2x+2)22 \rightarrow 3 \times 2(2x + 2)^2 = 6(2x + 2)^2.

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