JAMB 2013 Mathematics · Question 14

If the midpoint of the line PQ is (2,3) and the point P is (-2, 1), find the coordinate of the point Q.

Options

  1. A.(8,6)
  2. B.(5,6)
  3. C.(0,4)
  4. D.(6,5)

Answer: D. (6,5)

Explanation written with AI and checked against the answer key

Analysis

To find the coordinates of point Q, we use the Midpoint Formula. The midpoint M(x,y)M(x, y) of a line segment connecting two points P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2) is calculated as:

M=(x1+x22,y1+y22)M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
Concept

We are given the midpoint M(2,3)M(2, 3) and one endpoint P(−2,1)P(-2, 1). We need to find the coordinates of the other endpoint Q(x2,y2)Q(x_2, y_2). We can set up two separate equations—one for the x-coordinate and one for the y-coordinate—and solve for x2x_2 and y2y_2.

Step-by-Step Solution

1. Set up the equation for the x-coordinate:

x1+x22=xm\frac{x_1 + x_2}{2} = x_m
−2+x22=2\frac{-2 + x_2}{2} = 2

Multiply both sides by 2:

−2+x2=4-2 + x_2 = 4

Add 2 to both sides:

x2=4+2=6x_2 = 4 + 2 = 6

2. Set up the equation for the y-coordinate:

y1+y22=ym\frac{y_1 + y_2}{2} = y_m
1+y22=3\frac{1 + y_2}{2} = 3

Multiply both sides by 2:

1+y2=61 + y_2 = 6

Subtract 1 from both sides:

y2=6−1=5y_2 = 6 - 1 = 5

3. Combine the coordinates: The coordinates of point Q are (6,5)(6, 5).

Conclusion

Comparing our result (6,5)(6, 5) with the given options, it matches option D.

Exam Tip

When dealing with midpoint problems, you can use a "jump" method: look at how much the x-coordinate changed from P to the midpoint, and apply that same change again to get to Q.

  • From x=−2x = -2 to x=2x = 2 is a jump of +4+4. Adding +4+4 to 22 gives 66.
  • From y=1y = 1 to y=3y = 3 is a jump of +2+2. Adding +2+2 to 33 gives 55. This is a quick way to verify your answer in the exam hall!

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