JAMB 2013 Mathematics · Question 45

If the angles of a quadrilateral are (3y + 10)°, (2y + 30)°, (y + 20)° and 4y°. Find the value of y.

Options

  1. A.66°
  2. B.12°
  3. C.30°
  4. D.42°

Answer: C. 30°

Explanation written with AI and checked against the answer key

1. Analyze the question

You are given the four interior angles of a quadrilateral in terms of a variable yy. You need to find the value of yy by applying the geometric property of quadrilaterals.

2. Explain the concept

The fundamental principle here is that the sum of the interior angles of any quadrilateral is always 360°. If the angles are A,B,C,A, B, C, and DD, then:

A+B+C+D=360∘A + B + C + D = 360^\circ
3. Show the solution

Step 1: Set up the equation. Sum the given expressions and set them equal to 360:

(3y+10)+(2y+30)+(y+20)+4y=360(3y + 10) + (2y + 30) + (y + 20) + 4y = 360

Step 2: Group the like terms. Combine the terms with yy and the constant numbers separately:

(3y+2y+y+4y)+(10+30+20)=360(3y + 2y + y + 4y) + (10 + 30 + 20) = 360

Step 3: Simplify the equation.

(3+2+1+4)y+(60)=360(3 + 2 + 1 + 4)y + (60) = 360
10y+60=36010y + 60 = 360

Step 4: Solve for yy. Subtract 60 from both sides:

10y=360−6010y = 360 - 60
10y=30010y = 300

Divide by 10:

y=30010y = \frac{300}{10}
y=30y = 30
4. Identify the answer

The value of yy is 30. Looking at the options provided, this corresponds to Option C.

5. Tip

When dealing with polygons, remember the formula for the sum of interior angles: (n−2)×180∘(n - 2) \times 180^\circ, where nn is the number of sides. For a quadrilateral, n=4n=4, so (4−2)×180=2×180=360∘(4-2) \times 180 = 2 \times 180 = 360^\circ. This formula works for any polygon, whether it's a triangle, pentagon, or hexagon!

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