JAMB 2013 Mathematics · Question 1
If log104 = 0.6021, evaluate log1041/3
Options
- A.0.3011
- B.0.9021
- C.1.8063
- D.0.2007
Answer: D. 0.2007
Explanation written with AI and checked against the answer key
The question is ambiguous as typed, so let me look at the two sensible readings.
Reading 1: log₁₀(4^(1/3))
Use the power rule: log(aⁿ) = n·log a
log₁₀(4^(1/3)) = (1/3) × log₁₀4 = (1/3) × 0.6021 = 0.2007
Reading 2: log₁₀(41/3)
This would be log₁₀41 − log₁₀3. We can't get log₁₀41 from the given value of log₁₀4 alone, so this reading doesn't work. The question must mean 4^(1/3).
Step-by-step solution
- Rewrite the expression: log₁₀(4^(1/3))
- Bring the power down: (1/3) × log₁₀4
- Substitute the given value: (1/3) × 0.6021
- Calculate: 0.6021 ÷ 3 = 0.2007
Checking the other options
- A (0.3011) is about 0.6021 ÷ 2, which would be log√4, not the cube root.
- B (0.9021) has no logical link to the working.
- C (1.8063) is 3 × 0.6021, which would be log(4³). That is the wrong direction.
Exam tip: In a log question with a fractional power, the power comes out as a multiplier. The exponent 1/3 means "divide by 3", and the exponent 3 means "multiply by 3". Always check which one applies, because options like C are designed to catch students who mix them up.
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