JAMB 2012 Mathematics · Question 10

If angle θ\theta is 135o, evaluate cosθ\theta

Options

  1. A.12\frac{1}{2}
  2. B.22\frac{\sqrt{2}}{2}
  3. C.−22-\frac{\sqrt{2}}{2}
  4. D.−12-\frac{1}{2}

Answer: C. −22-\frac{\sqrt{2}}{2}

Explanation written with AI and checked against the answer key

Analyze the question: We need the exact value of cos 135°.

Concept: 135° lies in the second quadrant (between 90° and 180°). In this quadrant, cosine is negative (remember "ASTC": only Sine is positive in the 2nd quadrant). To find the value, use the reference angle:

Reference angle = 180° − θ

Solution:

  1. Reference angle = 180° − 135° = 45°
  2. cos 45° = √2/2
  3. Cosine is negative in the 2nd quadrant, so:

cos 135° = −cos 45° = −√2/2

(Check: cos 135° = cos(90° + 45°) = −sin 45° = −√2/2 ✓)

Answer: Option C, −√2/2.

Tip: Memorize the 45° values: sin 45° = cos 45° = √2/2. For angles like 135°, 225°, and 315°, just find the reference angle (45°) and then decide the sign using ASTC (All, Sine, Tangent, Cosine). In the 2nd quadrant, only sine is positive, so cosine and tangent are negative.

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