JAMB 2012 Mathematics · Question 5

If ∣53x2∣\begin{vmatrix} 5 & 3 \\ x & 2 \end{vmatrix} = ∣3545∣\begin{vmatrix} 3 & 5 \\ 4 & 5 \end{vmatrix}, find the value of x

Options

  1. A.3
  2. B.4
  3. C.5
  4. D.7

Answer: C. 5

Explanation written with AI and checked against the answer key

1. Analyze the Question

We are given an equation involving the determinants of two 2×22 \times 2 matrices. We need to calculate the determinant of both sides and solve the resulting linear equation for the unknown variable xx.

2. Explain the Concept

The determinant of a 2×22 \times 2 matrix ∣abcd∣\begin{vmatrix} a & b \\ c & d \end{vmatrix} is calculated using the formula:

Determinant=(ad)−(bc)\text{Determinant} = (ad) - (bc)

This means you multiply the elements of the leading diagonal and subtract the product of the elements of the other diagonal.

3. Show the Solution

Step 1: Calculate the determinant of the left-hand side (LHS).

∣53x2∣=(5×2)−(3×x)\begin{vmatrix} 5 & 3 \\ x & 2 \end{vmatrix} = (5 \times 2) - (3 \times x)
=10−3x= 10 - 3x

Step 2: Calculate the determinant of the right-hand side (RHS).

∣3545∣=(3×5)−(5×4)\begin{vmatrix} 3 & 5 \\ 4 & 5 \end{vmatrix} = (3 \times 5) - (5 \times 4)
=15−20= 15 - 20
=−5= -5

Step 3: Equate the two results and solve for xx.

10−3x=−510 - 3x = -5

Subtract 10 from both sides:

−3x=−5−10-3x = -5 - 10
−3x=−15-3x = -15

Divide both sides by -3:

x=−15−3x = \frac{-15}{-3}
x=5x = 5
4. Identify the Answer

Comparing our result to the given options: A. 3 B. 4 C. 5 D. 7

The correct option is C.

5. Tip

When dealing with determinants, always remember the "cross-multiplication" rule: (Top-Left ×\times Bottom-Right) minus (Top-Right ×\times Bottom-Left). A common mistake students make is forgetting the minus sign between the two products—don't let that happen to you!

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