JAMB 2012 Mathematics · Question 2

Evaluate ∫0π4sec2θdθ\int^{\frac{\pi}{4}}_0sec^2 \theta d \theta

Options

  1. A.1
  2. B.2
  3. C.3
  4. D.4

Answer: A. 1

Explanation written with AI and checked against the answer key

Analyze the question: We need the definite integral of sec²θ from 0 to π/4.

Concept: The derivative of tan θ is sec²θ, so the integral of sec²θ dθ is tan θ + C.

Solution:

∫0π/4sec⁡2θ dθ=[tan⁡θ]0π/4\int_0^{\pi/4} \sec^2\theta \, d\theta = \left[\tan\theta\right]_0^{\pi/4}
=tan⁡π4−tan⁡0= \tan\frac{\pi}{4} - \tan 0

We know tan(π/4) = tan 45° = 1 and tan 0 = 0, so:

=1−0=1= 1 - 0 = 1

Answer: The value is 1, which is option A.

Tip: Memorise the pairs of trig derivatives and integrals: d/dθ(tan θ) = sec²θ, so ∫sec²θ dθ = tan θ. Also remember the key values: tan 0 = 0, tan 45° = 1. In JAMB, be careful that π/4 is in radians (equal to 45°), so your calculator should be in radian mode if you use it, though here you do not need one.

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