JAMB 2011 Mathematics · Question 37

If ∣2353x∣\begin{vmatrix} 2 & 3 \\ 5 & 3x \end{vmatrix} = ∣4132x∣\begin{vmatrix} 4 & 1 \\ 3 & 2x \end{vmatrix}, find the value of x.

Options

  1. A.-6
  2. B.6
  3. C.-12
  4. D.12

Answer: A. -6

Explanation written with AI and checked against the answer key

1. Analyze the question

We are given an equation involving two 2×22 \times 2 determinants. We need to evaluate both determinants, set them equal to each other, and solve for the unknown variable xx.

2. Explain the concept

The determinant of a 2×22 \times 2 matrix ∣abcd∣\begin{vmatrix} a & b \\ c & d \end{vmatrix} is calculated using the formula:

Determinant=(ad)−(bc)\text{Determinant} = (ad) - (bc)

This means you multiply the elements on the leading diagonal and subtract the product of the elements on the other diagonal.

3. Show the solution

Step 1: Evaluate the left-hand side (LHS)

∣2353x∣=(2×3x)−(3×5)\begin{vmatrix} 2 & 3 \\ 5 & 3x \end{vmatrix} = (2 \times 3x) - (3 \times 5)
=6x−15= 6x - 15

Step 2: Evaluate the right-hand side (RHS)

∣4132x∣=(4×2x)−(1×3)\begin{vmatrix} 4 & 1 \\ 3 & 2x \end{vmatrix} = (4 \times 2x) - (1 \times 3)
=8x−3= 8x - 3

Step 3: Set the LHS equal to the RHS and solve for xx

6x−15=8x−36x - 15 = 8x - 3

To isolate xx, move the xx terms to one side and the constants to the other:

−15+3=8x−6x-15 + 3 = 8x - 6x
−12=2x-12 = 2x

Divide both sides by 2:

x=−122x = \frac{-12}{2}
x=−6x = -6
4. Identify the answer

Comparing our result to the given options: A. -6 B. 6 C. -12 D. 12

The correct option is A.

5. Tip

When dealing with determinants, always remember the "cross-multiplication" rule: (Top-Left ×\times Bottom-Right) minus (Top-Right ×\times Bottom-Left). A common mistake students make is forgetting the minus sign between the two products—don't let that happen to you!

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