JAMB 2011 Mathematics · Question 6

Find ∫\int cos4 x dx

Options

  1. A.34\frac{3}{4} sin 4x + k
  2. B.-14\frac{1}{4} sin 4x + k
  3. C.-34\frac{3}{4} sin 4x + k
  4. D.14\frac{1}{4} sin 4x + k

Answer: D. 14\frac{1}{4} sin 4x + k

Explanation written with AI and checked against the answer key

To solve the integral ∫cos⁡(4x) dx\int \cos(4x) \, dx, we use the standard rule for integrating trigonometric functions of the form cos⁡(ax)\cos(ax).

1. Analyze the question

We are asked to find the indefinite integral of the function f(x)=cos⁡(4x)f(x) = \cos(4x) with respect to xx.

2. Explain the concept

The integration rule for a cosine function with a linear argument axax is:

∫cos⁡(ax) dx=1asin⁡(ax)+k\int \cos(ax) \, dx = \frac{1}{a} \sin(ax) + k

where kk is the constant of integration. This is derived from the reverse of the chain rule in differentiation. Since the derivative of sin⁡(4x)\sin(4x) is 4cos⁡(4x)4\cos(4x), we must divide by 44 to balance the equation when integrating cos⁡(4x)\cos(4x).

3. Show the solution
  • Step 1: Identify the constant aa in the expression cos⁡(4x)\cos(4x). Here, a=4a = 4.
  • Step 2: Apply the integration formula: $∫cos⁡(4x) dx=14sin⁡(4x)+k\int \cos(4x) \, dx = \frac{1}{4} \sin(4x) + k$
  • Step 3: Compare this result with the given options.
4. Identify the answer

The result 14sin⁡(4x)+k\frac{1}{4} \sin(4x) + k matches option D.

5. Exam Tip

Whenever you are integrating a trigonometric function like sin⁡(ax)\sin(ax) or cos⁡(ax)\cos(ax), always remember to divide by the coefficient of xx. A common mistake is to multiply by the coefficient instead of dividing. Always check your answer by differentiating it; if you differentiate 14sin⁡(4x)\frac{1}{4} \sin(4x), you get 14⋅4cos⁡(4x)=cos⁡(4x)\frac{1}{4} \cdot 4 \cos(4x) = \cos(4x), which confirms the answer is correct.

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